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graph the line with slope 2 passing through the point (-4, -4)

how do i graph a slope with line 2 passing thru (-4,-4)

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Graph the equation that pass through the point (0,4) and has ...


Aug 28, 2013 · Graph the equation that pass through the point (0,4) and has a slope of -2 TacomaCCMath. ... How to graph a line in point-slope form - Duration: 3:27.

SOLUTION: graph the line with slope 4 passing through the ...


You can put this solution on YOUR website! If you want to find the equation of line with a given a slope of which goes through the point (,), you can simply use the ...
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Graph the line with slope -1/3 passing through the point (4,-2)


Graph the line with slope -1/3 passing through the point (4,-2) - 4378438
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Graph the line with slope 2 passing through the point (-5,4)


math i have more than one question so if u no any of the answers please tell me 1.) write the point-slope form of the equation of the line with slope -2 passing ...
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Graph the line with slope 3 passing through the point -4,1 ...


Kay, the first step to graphing the line is to start at point (-4,1). Since the slope is 3, the next point is (-3,4) if you go up 3 units and one unit right, or the ...
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Graph the line passing through the point -2 4 with slope ...


If the slope is undefined, then its a vertical line (up and down) . So draw a vertical line (up and down) that goes through -2 on the x-axis.
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Statistics - Graph the line with slope -3 passing through the ...


I am working on graphing a line with a slope passing through some points ... Graph the line with slope -3 passing through the point (5,4) Jan 10th, 2014 . Anonymous.
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Finding the Equation of a Line Given a Point and a Slope 2 ...


Algebra > Lines > Finding the Equation of a Line Given a Point and a Slope. ... Let's find the equation of the line that passes through the point ... Graphing Linear ...
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Graph the line with slope −2 passing through th... - OpenStudy


Graph the line with slope −2 passing through the point (-1,-4). your sexy . ill help . Point-Slope Formula--- where is the slope, and is the ...
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Suggested Questions And Answer :


graph the line with slope 2 passing through the point (-4, -4)

Problem: graph the line with slope 2 passing through the point (-4, -4) how do i graph a slope with line 2 passing thru (-4,-4) Plot the point (-4, -4) Find another point by counting to the right one space for every two spaces you count up. Draw a line between the two points and extend the line in both directions.
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how do I graph the line if the slope is 1/2 and it runs through the points (4,-3)

How do I graph the line if the slope is 1/2 and it passes through the points (4,-3) on the graph paper start at the point (4, -3)  then go one point over and two points up.  You have two points now you can graph the line. (y - (-3)) = 1/2x y = 1/2 x - 3  is the line
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write an equation of the line that passes through the given point and is parallel to the give line (6,8), y=-5/2x+10

Since we know the lines are parallel they must have the same slope. That is the first place to start. We know that the slope intercept form of a line is y=mx+b where m is the slope and b is the y itnercept Since we know the slope or m value we can start by writing this as y=-5/2x+b now we need to find the y intercept or b value. The easiest way to do this is to graph the line by plotting the point and using the slope to find other points.  Here is a graph of the two lines:   The y intercept of the unknown line, or the point at which it crosses the y axis is 23. The equation then for the unknown line is y=-5/2x+23
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Graph the line with slope -1 passing through the point (3,-2)

strate line with slope=-1, & go thru point=(3,-2) y=-x+konst projekt line from x=3 tu x=0...deltax=-3 deltay=sloep*deltax=(-1)*(-3)=+3 y=-2+3=1 y=-x+1 up tu yu tu selekt sum x's & kalkulate the y theer
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How is the graph of a line with undefined slope situated in a retanular coordinate system?

If you haven't got, or don't know, the slope of a line, what else can define a line? Knowing one point isn't enough because many lines will pass through that point. Knowing two points is enough, because you can join them to give you a line. That done, you can find the slope, by taking the difference between the rectangular coordinates. Divide the difference between the vertical (usually called y) by the difference between the horizontal (usually called x) and you have the slope. The slope is positive if it looks like / and negative if it looks like \.
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how do you solve and graph y=-2x+1

how do you solve and graph y=-2x+1 The equation is in slope-intercept form, so you know that the line passes through the point (0, 1). The slope is -2, which means that for every unit to the right (positive x), the line drops two units (negative y). From that, you can determine that (1, -1) is on the line, (2, -3) is on the line, and so on. To get a good distance between two points to define your line, pick a x value at least ten units from the first point. At x = 10, you will have moved 10 units, so you would move -20 units down. -20 below 1 is -19, so your second point is (10, -19). Plot that and draw a line through that point and the y-intercept.
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how do you graph y=-1/7x?

The line y=-1/7x or -x/7 has a negative shallow slope which means it slopes backwards (\). It passes through the origin (0,0) where the x and y axes cross. When x=7 y=-1 so we have two points (7,-1) and (0,0) such that if you draw a straight to pass through these two points extended in both directions you have the required graph. Just to make sure, check that the point (-7,1) also lies on the line.
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compute the slope m that passes through points (1,4) and (1,1)

1) To graph the line, connect the line between the two defined points. The line is vertical. 2) slope m = (y2 - y1) / (x2 - x1) The slope for the two points given is undefined since x2 - x1 = 0 and you can't divide by 0.
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a line that passes though the points (0,2) and (-3,5) has the equation :

the equation of a line in slope intercept form is y=mx+b m=slope b=y intercept The first thing we can do is calculate the slope which is the change in y over the change in x or "rise over run" 2 moving up to 5 is a difference of 3 0 moving left to -3 is a -3 3/-3 we can simplify this to -1 so we know that y=-1x+b We still need to find the y intercept. In this case one of our points (0,2) is on the y axis. so we know that the y intercept is 2 because that is where the line crosses the y axis. The equation then is y=-1x+2 the coefficent for x isn't really necessary so you could write this as y=-x+2 The graph of this line looks like this:    
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Calculus sin(x) function.

QUESTION: x), points P and Q are at consecutive lowest and highest points with P occuring before Q. Find the slope of the line which passes through P and Q. f(x) is at its lowest when sin(6πx) = -1, which is when the argument, 6πx = -π/2 + 2nπ. i.e. 6x = -1/2 + 2n x1 = -1/12 + n/3 f(x) is at its highest when sin(6πx) = 1, which is when the argument, 6πx = π/2 + 2nπ. i.e. 6x = 1/2 + 2n x2 = 1/12 + n/3 x1 and x2 are consecutive values for n = 0. i.e. x1 = -1/12, x2= 1/12 f1 = f(x1) = -6,  f2 = f(1/12) = 6 Our lowest and highest points now are (x1,f1) = (-1/12, -6), (x2,f2) = (1/12, 6). Slope between these two points is given by m = (f2 - f1) / (x2 - x1) m = (6 - (-6)) / (1/12 - (-1/12)) = 12/(1/6) = 72 Slope = 72
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