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what to type for radicals?

The question asks to simplify a radical which is 4 - 64 and this equals radical 60 and simplified it equals 2 radical 15.

Research, Knowledge and Information :

Typing Radicals—Wolfram Language Documentation

Typing Radicals. Typing : Typing : Typing : ... Type the second radical in the same way as the first. Press Ctrl + @, type y, press Ctrl + %, type n, and press Ctrl ...
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How to Make a Radical Sign |

How to Make a Radical Sign; How to Make a Radical Sign. March 31, 2015. By: Mason Howard. Share; Share on Facebook; ... Type the letter V to insert a radical sign. PC ...
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Typing Chinese radicals? - Stack Exchange

Typing Chinese radicals? ... If you search ANKI web I had a set of flashcards for learning to type with Cangjie. The other "radical" input method is Wubi which is ...
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Evaluating Radical Expressions on the TI83/84 - YouTube

Aug 09, 2010 · It also shows how to enter radicals enter the calculator using rational exponents ... Evaluating Radical Expressions on the TI83/84 Mathispower4u. ...

How to type square root radical sign

How to type square root radical sign √ On Windows: Hold down the ALT key and type 8730 on the keypad. Note: ...
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Radical (chemistry) - Wikipedia

Radical (chemistry) The hydroxyl radical, Lewis structure shown, contains one unpaired electron. In chemistry, a radical (more precisely, a free radical) is an ...
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How to Put a Radical on Microsoft Word : Using ... - YouTube

Oct 18, 2013 · ... Putting a radical on ... How to Put a Radical on Microsoft Word : Using ... How to Type Numbers With the ...

List of kanji radicals by stroke count - Wikipedia

The simplified table of Japanese kanji radicals page only lists common readings. Table of radicals ... and 白 is Radical 106 too, but not used as crown type for ...
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Entering a Radical Function on a TI-83 -

E. Radical Functions. When you enter a radical function, ... Other Radical Functions. There is built in function that you can use to enter a function such as .
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Suggested Questions And Answer :

what to type for radicals?

To radicalise a square root you break the number down to its factors and then decide whether you can pair any of the factors. For example, if the number is 64, this can be broken down to 2*2*2*2*2*2, that is 3 pairs of twos. When you take the square root, each pair reduces to one single number: so we have (2*2)(2*2)(2*2) reducing to 2*2*2. This is the number 8. But it's not always that easy. Another example, 180=2*2*3*3*5=(2*2)(3*3)5. This time we can reduce the pairs to 2*3=6, but we have a 5 left. To radicalise the square root we take the reduced pairs, 6, and multiply by the square root of 5: 6sqrt(5). That is square root of 180 in radical form. Now let's take 60=2*2*3*5=(2*2)3*5. Square root is 2sqrt(15). Example: 1350=2*3*3*3*5*5=2(3*3)3(5*5). We can reduce the pairs to 3*5 but we're left with 2*3=6; so the square root in radical form is 3*5sqrt(6)=15sqrt(6). We can't radicalise negative numbers unless we involve the imaginary number i, defined as the square root of -1. But  if we wanted to radicalise square root of -60, we would radicalise 60 then follow it with i: 2sqrt(15)i or 2isqrt(15). Not all numbers can be radicalised, but that just means we can't pair any of its factors. Other roots, like cube roots, can be radicalised, too, but instead of pairs we group in threes, so cube root of 1350=2(3*3*3)5*5. Reduce the group of three 3s to just one: 3cuberoot(50).  But 64=(2*2*2)(2*2*2), so the cube root of 64 is 2*2=4 because each of three 2s reduces to 2. For fourth roots we group in fours, and so on. Radicalisation happens in algebra, too. 25(x+1)(x-2)^2= (5*5)((x-2)*(x-2))(x+1), so square root is 5(x-2)sqrt(x+1).
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How do I figure this word problem out?

How do I figure this word problem out? Printing an article of 48000 words, using two sizes of type. The larger type contains 1800 words per page, the smaller type contains 2400 words.  The article is allowed 21 full pages. How many pages must be in the smaller type?   Large Type = L =1800 L Small Type = S = 2400S   1800S+ 2400L = 48000 <= eq1 L + S = 21 L = 21 - S <= eq2   1800 / (12 - S)+ 2400 / S = 48000 / (L+S) 1800S + 2400 L  = 48000 18S + 24L = 480 from eq2 18S + 24(21-S) = 480   18S + 24(12) - 24S)  = 480 - 6S + 504 = 480 6S = -(480 - 504) 6S = 24 Small Type (S) = 4 ◄ Ans  
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Lin can type 192 words in 6 min. Hoi can type 112 words in 4 min. Which statement is true?

Lin: 192/6=32 words per min. Hoi: 112/4=28 w/m, 4 words fewer than Lin per minute. So the answer is B.
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typing questions

???? wot sorta kerv fit du yu want ???? sumthun like this, me assume strate line fit "after 2 more weeks" his faster bi 2 werds/min so strate line fit=1 per week 4 weeks is 1 more week, so him faster bi 1...him du 31 werds/minut
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probability question

Out of 50 students, X=30, Y=15, making up 90% of the students. a) Tree diagram consists at the top of the 50 students, branching out to the second level 30, 15 and 5 for the three disciplines. The project team tree has three branches but, because students are randomly chosen, we cannot say what disciplines they represent, but we can represent the probabilities as another level of branches 1/10, 3/5 and 3/10 corresponding to 10%, 60% and 30% attached to each of the branches for the first level branches. (Strictly speaking, the selection process may change the probabilities, because the first student selected increases the probabilities for the remaining students by reduction of the pool of students to 49. If, for example, an X student was the first to be selected for the project team, then out of the 49 remaining, there would be 29 X students, changing the probabilities to 29/49, 15/49 and 5/49.) b) The joint probability distribution can be represented binomially as (p+(1-p))^3=p^3+3p^2(1-p)+3p(1-p)^2+(1-p)^3, where p=0.90 (for combined decision sciences and industrial statistics majors). So 1=0.729+0.243+0.027+0.001. The terms in this series separately show the make up of the project team as probabilities of all X or Y, 2 X or Y plus a business mathematics student, 2 of the latter and one X or Y, or all business maths students, c) If X=1 then 49 students remain, consisting of 29 X type, 15 Y type and 5 business maths majors. The binomial distribution of selecting Y is given by (p1-(1-p1))^2=p1^2+2p1(1-p1)+(1-p1)^2, where p1=15/49, the probability of selecting a Y student, and 1-p1=34/49 is the probability of selecting another X or a business maths student. So 1=0.0937+0.4248+0.4815. That means 9.37% probability of 2 Y students, 42.48% probability of 1Y and either of the other two types, and 48.15% probability of no Y type students. d) The mean in a binomial distribution is np, where n in this case is 3 (size of the project team) and p=3/5 or 0.6, so the mean is 1.8. This assumes that the mean applies before any member of the team has been selected, rather than when X=1, after a selection has already been made. e) For Y the mean is 3*15/49=0.92 approx., given that X=1. f) Before any member of the team has been selected, the probabilities are independent. The only dependence X and Y share is that once a team member has been selected, and is found to be X, for example, the probability changes because there is one fewer of that type left in the pool of students.
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what are 3 types of systems in two variables?

var fctb_tool=null; function W_CV_cM0QzB_(t) { fctb_tool=t; start(fctb_tool); }
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how could I make this problem into two linear equations for graphing...

Let the x-axis represents the number of days Bob trains, and the y-axis represents the amount of money he needs to pay. The 2 equations will be: y = 360 + (466/30)x y = 480 + (118.5/7)x Note that you can modify the equations so that the x-axis represents the number of days, weeks, or even years.
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using this number 732,410,956, Type the number that is 1,000,000 less.

Problem: using this number 732,410,956, Type the number that is 1,000,000 less. Using the number 732,410,956, follow these instructions. Type the number that is 1,000,000 less. 732,410,956 - 1,000,000 = 731,410,956  
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The probability of a Type I error is least for which one of the following: .100, .010. .050, .001?

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If the length if one edge if a cube is 2 radical 2 ,what is the volume if the cube?

????????????? "raduikal" ????????????? kube volume=side^3 =[2root(2)]^3 =2^3 * root(2)^3 =8*2*root(2) =16root(2)
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