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the GCF 28 and 42

please list all the factors until the last one possible.

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Greatest Common Factor (GCF) of 28 and 42 - Get Easy Solution


Greatest Common Factor (GCF) of 28 and 42 . If it's not ... Greatest Common Factor (GCF) of 17 and 42 | | Greatest Common Factor (GCF) of 78 and 143 ...
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What is the greatest common factor of 28 and 42 - Answers


The greatest common factor of 42 and 375 is 3. ... What is the greatest common factor of 56 42 28 and 98? 14. Edit. Share to: Eric Barnes. 390,655 Contributions.
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Greatest Common Factor of 28 and 42 - Times Table


The gcf of 28 and 42 is the largest positive integer that divides the numbers 28 and 42 without a remainder. Spelled out, it is the greatest common factor of 28 and 42.
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GCF and LCM of 28 and 42 - YouTube


Sep 03, 2013 · GCF and LCM of 28 and 42 Glennan Saraceno. Loading ... 42. Lisa De Bartolo 8,167 views. ... How to find the greatest common factor ...

GCF(28, 42) - coolconversion.com


What is the greatest common factor (GCF) of 28, 42. ... GCF(28, 42) or what is the highest common factor (HCF) of 28, 42? What is the GCF of 28 and 42?
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Greatest Common Factor of 28 and 42 GCF(28,42)


Greatest Common Factor of 28 and 42. Greatest common factor ... So the greatest common factor 28 and 42 is 14. Also check out the Least Common Multiple of 28 and 42.
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What is the GCF of 28 42 70 - Answers.com


What is the GCF of 28 42 and 98? 14 6 people found this useful Edit. Share to: Sabrina Martins. 8 Contributions. What is the GCF Of 35 and 42?
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What is the greatest common factor of 28 and 42?


You have reached us maybe looking for answers to the questions like: What is the greatest common factor of 28 and 42? or what is the highest common factor ...
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What is the GCF of 28 and 42? A. 2 B. 4 C. 7 D. 14 - Brainly.com


What is the GCF of 28 and 42? A. 2 B. 4 C. 7 D. 14 1. Ask for details ; Follow; Report; by lharada2978 10/06/2016. Log in to add a comment Answers itssjustinn09 ...
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Suggested Questions And Answer :


what is the gcf of 3x+18?

If you mean "what is the GCF of 3x + 18?," 3x + 18 is only one thing, so the GCF is just 3x + 18. . If you mean "what is the GCF of 3x and 18?" then: 3x = 3 * x 18 = 2 * 3 * 3 The GCF is made of the factors that appear in both 3x and 18.  In this case that's just 3, so the GCF is 3. Answer:  The GCF of 3x and 18 is 3.
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How do you factor the sum of terms as a product of the GCF and a sum?

It took me a while to interpret your question, and I came up with a polynomial that had a GCF, but it doesn't have to be a polynomial: 36x^2+45x+63 simplifies when we note that the GCF of the numbers 36, 45 and 63 is 9. That means 9 is the largest integer to divide into the numbers: 36=9*4, 45=9*5 and 63=9*7. This means we can rewrite the polynomial as the product of a GCF and a sum: 9(4x^2+5x+7). It utilises the distributive property of numbers. Another example: abc+ace-ca^2. In this case the GCF is algebraic: ac, because all the terms contain ac, so we can factorise: ac(b+e-a). This is the product of the GCF ac and the sum b+e-a. Another example: 4x^2+2xy+6x=2x(2x+y+3). This time the GCF is 2x because the GCF of the numbers is 2 and of the algebraic quantities is x, so we just combine the two GCFs to make 2x. Does this help you in time? If you still don't understand send me a private message explaining your difficulties and providing examples.
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1. Find the GCF of 54a^2, 84ab and 10c 2. Find GCF of 14a^2b^4c and 56ab^2c^2.

1. Find the GCF of 54a^2 = 2*3*3*3*a*a 84ab  = 2*2*3*7*a*b 10c  =2*5*c 2 is the only factor in all three numbers so that is the GCF.   2. Find GCF of 14a^2b^4c  = 2*7*a*a*b*b*b*b*c 56ab^2c^2 = 2*2*2*7*a*b*b*c*c 2*7*a*b*b*c is common or 14ab^2c
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what is the LCM and the GCF of 125, 235 and 270

LCM of 125, 235, 270 Factor each into primes: 125 = 5 * 5 * 5 235 = 5 * 47 270 = 2 * 3 * 3 * 3 * 5 The LCM is the product of the minimum list of primes needed to make all of those numbers (125, 235, 270). For instance, there's a factor of 2 in 270, so the LCM has to have a factor of 2. There are three 3's as factors in 270, so the LCM has to have a factor of three 3's. There are three 5's as factors in 125, so the LCM has to have a factor of three 5's.  There's a 5 in 235, but that's already covered by one of the three 5's. There's a 47 in 235, so the LCM has to have a factor of 47. Basically you start with this: 125 = 5 * 5 * 5 235 = 5 * 47 270 = 2 * 3 * 3 * 3 * 5 Then make a list like this: 2 * 3 * 3 * 3 * 5 * 5 * 5 * 27 Then multiply it together like this: 2 * 3 * 3 * 3 * 5 * 5 * 5 * 27 = 182250 Answer:  The LCM of 125, 235, and 270 is 182250 . GCF of 125, 235, and 270 Start with a list of primes: 125 = 5 * 5 * 5 235 = 5 * 47 270 = 2 * 3 * 3 * 3 * 5 The GCF is the product of the list of primes that appear in all of those numbers (125, 235, 270). 47 only appears as a factor in 235, so 47 does not appear in the GCF. The only number that appears in all three numbers (125, 235, 270) is 5. 5 appears in 125 three times, but it only appears once in all three numbers (125, 235, 270), so the GCF only includes one 5. Answer:  The GCF of 125, 235, and 270 is 5.
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What is the greatest common factor of 24x^2yz^3-(-9xyz^2)?

Simplify the expression: 24x^2yz^3+9xyz^2. If we factorise this, the GCF goes outside the brackets: First we look for the numerical common factor: 24 and 9 have a GCF of 3. Next we have x and x^2: GCF=x; then y and y: GCF=y. Finally z^3 and z^2: GCF=z^2. Combine all these GCFs: 3xyz^2. Rewrite the expression: 3xyz^2(8xz+3).
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Whats the gcf of 12x and 27x^3?

The GCF of 12x and 27x^2  is 3x. 12 = 3 * 4. 27 = 3 * 7. Shows that GCF is 3. And there is at least one x on both of them so add the x to the 3. Reason for GCF  3x.
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GCF of 43 and 387

43 is a prime, so its only factors are 1 and 43. If 387 is not divisible by 43, then the GCF has to be 1. 387 / 43 = 9, which means that 387 is divisible by 43. Hence, the GCF of 43 and 387 is 43.
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9v^6w^3+33v^4w^5

​There are so many questions like this that perhaps it would be easier to describe the method of solution and let the user work out the answer for himself/herself. I'll use this question as an example.  The question contains two terms added together. But they have factors in common. The idea is to find the largest common factor by inspecting the two terms and looking for everything they have in common. A term is made up of plain numbers and variables. In this case, the variables, v and w, are raised to certain powers, but as long as we're dealing with the same variables we can combine powers (exponents). Look at the numbers first. We have 9 and 33 only, because the others are exponents. What's the gcf of these? Break them down into factors: 9=3*3; 33=3*11, so gcf=3, because it's the only common factor in this case. Note this. Now take the v terms: what's the lowest exponent? v^4. Note that; now we have 3v^4 so far as the gcf. Now w: the lowest exponent is w^3. We have the gcf: 3v^4w^3. When we factorise the expression we get: 3v^4w^3(3v^2+11w^2). expand the brackets: 3*3 * v^4*v^2 * w^3 + 3*11 * v^4 * w^3*w^2 = 9v^6w^3+33v^4w^5, the original expression. When we multiply the same variables with exponents we add the exponents together to get the product. Now try answering your own gcf questions! It should be easy!
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What is the GCF of 24x^2 and 40x^3?

24x^2 = 2 * 2 * 2 * 3 * x * x 40x^3 = 2 * 2 * 2 * 5 * x * x * x The GCF is made of the factors that appear in both 24x^2 and 40x^3.  Both of those have three 2's and two x's, so the GCF is 2 * 2 * 2 * x * x = 8x^2. Answer:  The GCF of 24x^2 and 40x^3 is 8x^2.
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Write each rational expression in lowest terms(20 r+10)/(30r+15)

(20r+10)/(30r+15) Factor out the GCF of 10 from each term in the polynomial. (10(2r)+10(1))/(30r+15) Factor out the GCF of 10 from 20r+10. (10(2r+1))/(30r+15) Factor out the GCF of 15 from each term in the polynomial. (10(2r+1))/(15(2r)+15(1)) Factor out the GCF of 15 from 30r+15. (10(2r+1))/(15(2r+1)) Reduce the expression (10(2r+1))/(15(2r+1)) by removing a factor of 5 from the numerator and denominator. (2(2r+1))/(3(2r+1)) Reduce the expression by canceling out the common factor of (2r+1) from the numerator and denominator. (2(2r+1))/(3(2r+1)) Reduce the expression by canceling out the common factor of (2r+1) from the numerator and denominator. (2)/(3)
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