Guide :

how do you tell the number of sides on a paralellagram if the number of the sides is n

the number of sides

Research, Knowledge and Information :


Parallelogram - Wikipedia


The congruence of opposite sides and opposite angles is a direct ... and the leading factor 2 comes from the fact that the number of congruent ...
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Parallelogram - Math is Fun


Opposite sides are parallel: ... A parallelogram where all angles are right angles is a rectangle! Area of a Parallelogram : The Area is the base times the height:
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Parallelograms. Properties, Shapes, Sides, Diagonals and ...


Number Line Maker; Inquality Number Line Maker ; Math Worksheets; Chart Maker; ... Since opposite sides are congruent you can set up the following equations: ...
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How To Find if Triangles are Congruent - Math Is Fun


exactly the same three sides and ; exactly the same three angles. ... This is not enough information to decide if two triangles are congruent!
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What is the difference between a parallelogram and a ...


A parallelogram is a figure with four straight sides whose ... What is the difference between a parallelogram and ... What is a landmark number? Q: How do you find ...
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Geometry Questions including "What is the value of a Charles ...


Geometry Questions including "What is the value of a Charles ... phone number. They do not ... manipulte both sides. Let's begin with the identity you wish ...
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Properties of Parallelograms | Wyzant Resources


Properties of Parallelograms: Sides and Angles. ... Please provide a valid phone number. App for Students App for Tutors ...
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Areas of Parallelograms and Triangles | Wyzant Resources


Areas of Parallelograms and Triangles. While you may not see the similarities ... quadrilateral whose opposite sides do not ... number of congruent triangles ...
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Lesson Answer ch15 - ~ Ms. Xiong's 5th Grade Class~ - Home


Here is an activity you can do together ... Identify the number of sides and discuss what makes each figure ... Lesson Answer ch15.docx
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Suggested Questions And Answer :


how do you tell the number of sides on a paralellagram if the number of the sides is n

parallelogram alwaes hav 4 sides & it gotta hav 2 sets av EQUAL sides
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how can i tell what number to add or subtact from when solving varibals

Go to each side of the equal sign and combine your x's (or variables of like kind) then your numbers (constants) without x's (or other variables of like kind) and use the sign in front of the term, and when there is no sign, it may be positive or + in most cases! How does this answer your question? If you have two terms one has an "x" and the other just a number, alone those are not "like kind" (one is a constant(for example "5") and the other a variable(Ffor example "x")) and should not be combined because one is part of the variables and the other is part of the constants. When I say "combine" this is where you "add or subtract" those variables or like terms. In the example you provided the variable with the equal sign, erasing the rest of the problem reads "2x+3x=" Notice how they are both on the same side of the equal sign, in this case you just do as it reads "2x+3x=" or "5x=" do not forget to keep that equal sign so you can determine where the rest of the terms go. Sometimes you will encounter variables or other terms on the other side of the equal sign, in a case like this simply combine like terms on one side of the equal sign and then  do the same to the other, no particular order but some say it is easier to use a method or pattern. EXAMPLE 2x+5x+5+2= -5x-13x+32. Do not get scared it only looks more challenging then it is. IF you picture your variables with everything else other than the equal sign erased you will have "2x+5x=-5x-13x" I know this will not work out as a problem, just use it as a visual. and combine. You should get "7x=-18x". You could go even further and move your x's to one side or just wait until that step. In the example I provided it requires an extra step that some call reversing/negating the terms and others in your book call it something similiar. Just a thought!! Lastly, move your variables to one side of the equal sign and your constants to the other side of the equal sign. It really does not matter what side unless you see an easy way to solve, but variables must always be on that one side of the equal sign you pick and constants on the other side of the equal sign. Usually 25x=25 or x=1, and 25=x or 1=x no matter what order if you do not mind the multiplication rule of multiplying negatives and positives. that is where you create you easy method.
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how to solve this quadratic equation x^2-2^x-13=0

I think you may have typed this in wrongly because the term 2^x is not a permitted term in a quadratic equation. As it stands the solution to the equation is about -3.6168. Let's say you made a mistake in typing and the middle term is 2*x or 2x, then the solution exists but it is irrational (involves square roots). The easiest way to solve x^2-2x-13=0 is to complete the square: (x^2-2x+1)-1-13=0, which is (x-1)^2-14=0, so (x-1)^2=14. Take square roots of each side: x-1=+sqrt(14)=+3.7417 approx. A square root always has two solutions, one positive and one negative, but the same magnitude number. So x has two possible values: x=1+3.7417=4.7417 or x=1-3.7417=-2.7417. If you meant the question to be x^2-12x-13=0, then the solution is (x-13)(x+1)=0 and x=13 or -1. To work this out we ask: what are the factors of 1 (x^2 coefficient) and 13 (the constant term). The factors of 1 are 1 and 1 because only 1 times 1 make 1; and the factors of 13 are only 1 and 13. The coefficient of the x^2 term tells is how many x's go in each bracket. That's 1x or just x in each bracket. And the factors of 13 tell us what. Numbers to write in each bracket, so that's 1 and 13. So we have (x 1)(x 13). What about the signs between them? We look at the sign in front of 13 in the quadratic. It's minus, and that means there will be a plus in one bracket and a minus in the other. But which way round? Well, there's one more test: we take the factors of 13 and subtract them because the minus sign in front of 13 tells us we need to subtract. If it had been plus, we would have added the factors. 13-1=12. If 12 is the coefficient of the x term then the quadratic can be solved. (If the number had not been 12 we could not have solved the quadratic this way.) The sign in front of 12x is the sign that goes in front of the larger number in the brackets, so minus goes in front of 13. So we have (x+1)(x-13)=0. One or other of these factors is zero, so x+1 or x-13 is zero. x+1=0 means x=-1 and x-13=0 means x=13. These are the solutions or roots.
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How do I read Stem and Leaf plots?

Stem and Leaf plots are just a method of ordering data in a dataset to produce a frequency chart. The usual way this is done is to use part of each datum to create a data bin. Let's imagine a dataset where all the data consists of numbers between 1 and 99. It doesn't matter how big the dataset is or if there are duplicates. Now imagine 10 bins. The first bin is for numbers between 1 and 9; the second for numbers between 10 and 19, and so on. The numbers of the bins will be labelled 0 to 9. The bins are the stems. So we just go through all the data and put each datum into its appropriate bin. But we don't have to put the whole of the data into each bin, because the bin number is already numbered with the first digit of the data. So the contents of each bin just contain the second digit of the data. The bins (stems) are lined up in order 0 to 9 and we can also stack their contents so that the single digits are in order inside the bins. These are the leaves. Imagine the bins are made of glass. We can look at the bins and the heights of the stacks of contents. The heights of the contents form a shape as we run down the line of bins. These heights tell us how many data there are in each bin and indicate where the most data is and where the least data is. This is is a frequency distribution. It's the basis of the Stem and Leaf plot and can be represented by a table or chart. Each row of the table starts with the bin number (STEM) and along the row we have the contents of the bin (LEAVES). Turn the table on its side and we have a chart with the stem running along the bottom and the leaves forming towers over the stems. The chart resembles the row of bins with the stack, or column, of contents over them, but the bins are now invisible, and only their labels remain as regular horizontal divisions on the chart. But it doesn't stop there. This frequency chart tells us where most of the data can be found, where its middle is and the general shape of the data. These are important statistical observations. Not all the bins may have data in them, and some will have lots of data. Random data will produce no particular shape, but in many cases there will be a pattern. We've considered numbers from 1 to 99, but the data can have any range as long as the data is binned carefully to reflect the relative magnitude of the data. If the data were between 250 and 400, for example, we might take the first 2 digits as the bin label: 25 to 40 and the contents would be the third digit. So you need to make a decision based on the range of data values to decide how the data is going to be binned. I hope this helps you to understand Stem and Leaf plots.
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What is a stem and leaf plot and when would I use one?

Stem and Leaf plots are just a method of ordering data in a dataset to produce a frequency chart. These plots are used in statistical analysis to draw conclusions about a dataset. The usual way this is done is to use part of each datum to create a data bin. Let's imagine a dataset where all the data consists of numbers between 1 and 99. It doesn't matter how big the dataset is or if there are duplicates. Now imagine 10 bins. The first bin is for numbers between 1 and 9; the second for numbers between 10 and 19, and so on. The numbers of the bins will be labelled 0 to 9. The bins are the stems. So we just go through all the data and put each datum into its appropriate bin. But we don't have to put the whole of the data into each bin, because the bin number is already numbered with the first digit of the data. So the contents of each bin just contain the second digit of the data. The bins (stems) are lined up in order 0 to 9 and we can also stack their contents so that the single digits are in order inside the bins. These are the leaves. Imagine the bins are made of glass. We can look at the bins and the heights of the stacks of contents. The heights of the contents form a shape as we run down the line of bins. These heights tell us how many data there are in each bin and indicate where the most data is and where the least data is. This is is a frequency distribution. It's the basis of the Stem and Leaf plot and can be represented by a table or chart. Each row of the table starts with the bin number (STEM) and along the row we have the contents of the bin (LEAVES). Turn the table on its side and we have a chart with the stem running along the bottom and the leaves forming towers over the stems. The chart resembles the row of bins with the stack, or column, of contents over them, but the bins are now invisible, and only their labels remain as regular horizontal divisions on the chart. But it doesn't stop there. This frequency chart tells us where most of the data can be found, where its middle is and the general shape of the data. These are important statistical observations. Not all the bins may have data in them, and some will have lots of data. Random data will produce no particular shape, but in many cases there will be a pattern. We've considered numbers from 1 to 99, but the data can have any range as long as the data is binned carefully to reflect the relative magnitude of the data. If the data were between 250 and 400, for example, we might take the first 2 digits as the bin label: 25 to 40 and the contents would be the third digit. So you need to make a decision based on the range of data values to decide how the data is going to be binned. I hope this helps you to understand Stem and Leaf plots.
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what is the answer to 18-4t/0.5=20 ?

Perhaps it was the fraction that put you off, or was it the decimal in the denominator. I guess you want to find the value of t. Let's get rid of the fraction by multiplying both sides of the equation by 0.5. It's not clear in the question whether the problem is 18-(4t/0.5)=20 or (18-4t)/0.5=20. The brackets tell us what has to be worked out first. I'm going to provide solutions whichever one of these is the problem. First, 18-(4t/0.5)=20 Multiplying both sides by 0.5 we get 18*0.5-4t=20*0.5 giving us 9-4t=10. The decimals have been swallowed up in the multiplication. 0.5 is the same as 1/2, but if you didn't know that, multiply by 5 and move the decimal point back one place. So, for example, 5*18=90. The decimal point invisibly sits after 90, so moving it back a place makes it 9.0 which is just 9. So 9-4t=10. We need to get the numbers on one side of the equation and the unknown on the other side. At this stage we don't want to separate 4 from 4t. OK, let's keep the unknown on the left, so we get -4t=10-9, giving us -4t=1. When we move things from one side of an equation to the other plus becomes minus, and minus becomes plus, multiply becomes divide, and divide becomes multiply. So this is the same as 4t=-1, and t=-1/4. Second, (18-4t)/0.5=20 Multiply both sides by 0.5 and we get 18-4t=20*0.5, in other words 18-4t=10. Let's separate the unknown from the numbers, but this time we'll take the unknown over to the right (it doesn't matter which side really). So we get 18-10=4t. Therefore 8=4t, the same as 4t=8, so t=2. That looks like the simpler of the two answers, so my guess is that it's what the question really was, don't you think? It's important that questions are written correctly because, as you can see, we came up with two quite different answers.
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make two magical square with single digit

3 x 3 MAGIC SQUARE SOLUTIONS Represent square using letters: A B C D E F G H I A+B+C=S=D+E+F=G+H+I; A+B+C+D+E+F+G+H+I=3S. A+E+I=B+E+H=C+E+G=D+E+F=S (A+B+C+D+E+F+G+H+I)+3E=4S; 3S+3E=4S, E=S/3. A+E+I=S, I=S-E-A, I=2S/3-A. H=S-E-B, H=2S/3-B. C=S-(A+B). G=2S/3-C=2S/3-S+(A+B), G=A+B-S/3. D+G=B+C=B+S-(A+B)=S-A; D=S-A-G=S-A-A-B+S/3, D=4S/3-(2A+B). F=2S/3-D=2S/3-4S/3+2A+B, F=2A+B-2S/3. Completed square:           A            B             S-(A+B) 4S/3-(2A+B)    S/3    2A+B-2S/3    A+B-S/3    2S/3-B      2S/3-A So A and B are arbitrary; S must be a multiple of 3 if square is to be whole numbers only. EXAMPLE: A=1, B=5, S=18:   1  5  12 17  6  -5   0  7  11 Single digits can be 1 to 9 (sum=45) or 0 to 8 (sum=36). The common sum is 45/3=15 or 36/3=12. In one case the middle digit is 5 (15/3)  and in the other it's 4 (12/3). In the first case, 5 must be in the middle of the square, and we need to see where 9 fits in. The common sum is 15 so 15-9=6 and the other two numbers must be (1,5) or (2,4). This tells us that 9 can only participate in two sums and therefore it must be in the middle of a side with 2 and 4 on either side of it. So B=9 and A=2. 2 9 4 7 5 3 6 1 8 is a solution. In the case for 0-8 we simply subtract 1 from each square: 1 8 3 6 4 2 5 0 7 and we can reorientate this: 7 2 3 0 4 8 5 6 1 There we have it: two solutions. 
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Math Summary

I need to work out this problem x^2 - 14x + 74 = 0 We're going to use a method called completing the square. Begin by subtracting 74 from both sides of the equation. x^2 - 14x + 74 - 74 = 0 - 74 x^2 - 14x = -74 Next, we divide the coefficient of x by the coefficient of x^2, then take 1/2 of that, and square it. We add that result to both sides of the equation. 14/1 = 14 14 * 1/2 = 7 7 * 7 = 49 x^2 - 14x + 49 = -74 + 49 x^2 - 14x + 49 = -25 We can factor the left side of the equation. (x - 7)(x - 7) = -25 The right side is a negative number. For this problem, it means there are no real roots, i.e., the graph of this equation does not cross the x-axis. There are imaginary roots, though. In order to obtain the square root of a negative number, we introduce i, which is the square root of -1. Using that, the answer to this problem becomes x - 7 = ±5i. Which means that x = 7 + 5i  and x = 7 - 5i.  
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calculate area with sides having 45.6 feet, 52.6 feet, 25 feet and 28 feet

???????????????? wot sorta shape is it ???????????? yu giv 4 numbers wich impli sumthun hav 4 sides yer 4 numbers differ, so not a regular shape gotta hav detaels, such as the (x,y) av all 4 points
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in, 7x+6=x-6, how come you subtract 7x and x and -6 and 6

7x+6=x-6.....the idea is tu get all x's on 1 side & all numbers on other side av "="..... . . so subtrakt x from both sides...7x-x+6=(x-x)-6=-6 . . . . bukum 6x+6=-6 . . . . Then du same thang with the numbers . . . 6x=-12 . . . .
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