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# How many 3/4 are in 3

## Research, Knowledge and Information :

### How many ounces does 3/4 cup equal? | Reference.com

How many ounces does 3/4 cup equal? A: ... How many cups are equal to 4 ounces? A: When measuring volume, 4 ounces equals 1/2 cup. A full cup contains 8 ounces.

### How many atoms are in Al(PO4)3? | Socratic

... (PO_4)_3 contains the elements Aluminum, ... How many atoms are in Al(PO4)3? ... How many liters of carbon dioxide can be ...

### data wiring - How many CAT6 cables can fit in 3/4 conduit ...

Just how many CAT6 cables can safely fit into 3/4" conduit? current community. chat. ... How many CAT6 cables can fit in 3/4 conduit? up vote 3 down vote favorite. 1.

### MAFS.6.NS.1.1 - Interpret and compute quotients of fractions ...

MAFS.6.NS.1.1. x. x ... (2/3) ÷ (3/4) and use a visual fraction model to show the quotient; ... How many 3/4-cup servings are in 2/3 of a cup of yogurt?

### What is 3/4 of a cup doubled? | Reference.com

When 3/4 of a cup is doubled, ... What is 3/4 of a cup doubled? A: Quick Answer. ... How many cups are equal to 4 ounces? A: ...

### Fractions - Math is Fun - Maths Resources

The top number says how many slices we have. ... Equivalent Fractions. Some fractions may look different, but are really the same, ... 3 / 4 + = = Adding Fractions ...

### Chemistry ch. 1-3 Green Flashcards | Quizlet

Chemistry ch. 1-3 Green. STUDY. ... (4.3 - 3.7) × 12.3= 1. The ... How many times more expensive it is to buy the 12-oz can of pop compared to buying it in a 2.00 L ...

### 6.NS.A.1 - Common Core State Standards Initiative

... (2/3) ÷ (3/4) = 8/9 because 3/4 of 8/9 is 2/3. (In general, (a/b) ÷ (c/d) = ad/bc.) ... How many 3/4-cup servings are in 2/3 of a cup of yogurt?

### Fractions - Grade 5 Math Questions With Solutions and ...

Fractions 4/3 and 8/6 are equivalent because when written ... are all smaller than 1. 7/6 is the largest fraction. The remaining 3 ... How many minutes in 2/3 of ...

## Suggested Questions And Answer :

### Eight horses are entered in a race...(Have more)

1(a) How many different orders are possible for completing the race? 8*7*6*5*4*3*2*1=8!=40,320 (b) In how many different ways can first, second, and third places be decided? (Assume there is no tie.) (8*7*6)=P(8,3)=336 or 6*C(8,3) where 6=3*2*1 the number of ways of arranging three items 2.)Telephone numbers consist of seven digits; the first digit cannot be 0 or 1. How many telephone numbers are possible? 8*10^6=8,000,000  3.)In how many ways can five people be seated in a row of five seats? 5*4*3*2*1=5!=120 4.)In how many ways can five different mathematics books be placed next to each other on a shelf? 5!=120 5.)In a family of four children, how many different boy-girl birth-order combinations are possible? (The birth orders BBBG and BBGB are different.) 16=2*2*2*2 from BBBB to GGGG 6.)Two cards are chosen in order from a deck. In how many ways can this be done if (a) the first card must be a spade and the second must be a heart?  13*13=169 (b) both cards must be spades? 13*12=156 7.)A company’s employee ID number system consists of one letter followed by three digits. How many different ID numbers are possible with this system? 26*10*10*10=26,000 Continued in comment...

### 120 fl oz = how many gallons

1 gallon (US)=128 fluid owns 100/128=0.78125...100 fluid=0.78125 gallon

### How many Quarters? How many Pennies? How many dimes? Solve by using systems of equations by substitution

Q, D, P = numbers of quarters, dimes and pennies. Q+D+P=20. P=5D, so Q+D+5D=20 and Q+6D=20. Value=25Q+10D+P=230 pennies, so 25Q+10D+5D=230, 25Q+15D=230, so 25Q=230-15D, 5Q=46-3D. Q=20-6D, so 5Q=100-30D=46-3D. 54=27D, D=2, P=5*2=10 and Q=20-6*2=8. CHECK: Q+D+P=8+2+10=20. VALUE=8*0.25+2*0.10+0.10=\$2.30. Solution: 8 quarters, 2 dimes, 10 pennies.

### assume that 50 of each of ticket were sold. The amount taken is 87.50

assume that 50 of each of ticket were sold. The amount taken is 87.50 extension of problem: 100 tickets were sold for a total of \$85.00 how many adult and how many adult and how many student tickets were sold Not enough information given for this problem and the total amount differs we can only assume that \$85 / 50 = the cost of one adult and one student ticket combined.

### what is 2/3 of 27

Jim has three times as many comic books as Charles. Charles has 2/3 as many books as Bob. Bob has 27 books. How many comic books does Jim have?*

### how many graph if linear equation in two variable can pass through the point(-3,0)

Think of the point (-3,0) and imagine it's the centre of a bicycle wheel. Think of the spokes of the wheel and, for the sake of illustration, imagine every one of them goes through the centre of the wheel. How many spokes? How many spokes could there be? If all the spokes were very thin, there would be many, many spokes. Each spoke is a straight line. So each spoke would be like a linear equation, one for each spoke. How many equations? Countless numbers. y=ax+b is the standard form for a linear equation. Put y=0 and x=-3: 0=-3a+b, so b=3a. Therefore y=ax+3a=a(x+3), where a is any number. So this equation passes through the point (-3,0). There are an infinite number of values for a, so there are an infinite number of lines, an infinite number of spokes. A few examples are y=x+3; y=-x-3 or x+y+3=0; y=2x+6; y=10x+30; y=(x/3)+1;...

### How many packages have been delivered ?

Problem: How many packages have been delivered ? At work one day, Erica Franz received 7 packages. Speedy delivery delivered twice as many as Ralph's Express, while Ralph's Express delivered one more package than SendQuick package service. how many packages did each deliver ? s = 2r r = q + 1 s = 2(q + 1) s = 2q + 2 s + r + q = 7 (2q + 2) + (q + 1) + q = 7 4q + 3 = 7 4q = 4 q = 1 r = q + 1 = 1 + 1 = 2 s = 2r = 2 * 2 = 4 Speedy Delivery delivered 4 Ralph's Express delivered 2 SendQuick Package Service delivered 1

### How to factor this trigonometry problems. MANY thanks to those who can help me.

2csc2 A – 32 =                  3cot2 B – 27 =                                          3(cot^2 - 9)= (2csc^2 - 32) =                 3( cot^2 - 3^2) 2(csc^2 - 16 )=                3( cot - 3)( cot + 3) 2(csc^2 - 4^2) = 2(csc - 4)( csc + 4)   Sin2 Ө – 18sin Ө + 81 = ( sin - 9)( sin - 9) 5cos3 w – 15 = 5(cos^3 - (3^(1/3))^3= 5(cos - 3)( cos^2  + 3^(1/3)*cos + 3^(1/3)^2 )

### how many ways can you have coins that total 18p using 1p , 2p, 5p, and 10p coins

in how many ways can you have coins that total exactly 18pence using 1p, 2p, 5p and 10p coins but you may wish to use as many of each sort as you wish. Start with the biggest coin, then the next biggest, etc. This is so that you always end up adding on just single coins of 1p. 10    we can only have 1*10 because 2*10 is greater than 18. 10 + 5   we can only add on 1*5 because adding on 2*5 will make the sum greater than 18 10 + 5 + 2   again we can only add on 1*2 10 + 5 + 2 + 1   our first arrangement  (1*10, 1*5, 1*2, 1*1) Now we modify the 2p intp 2*1p, the 5p into 2*2p + 1p and the 10 p into 2*5p (as well as 2p's and 1p). 10 + 5 + (1+1) + 1    our 2nd arrangement   (1*10, 1*5, 0*2, 3*1) Now modify the 5, in the 1st arrangement. 10 + (2+2+1) + 2 + 1    3rd arrangement    (1*10, 0*5, 3*2, 2*1) 10 + (2+2+1) + (1+1) + 1    etc.   (1*10, 0*5, 2*2, 4*1) 10 + (2+(1+1)+1) + (1+1) + 1    etc.  (1*10, 1*5, 1*2, 1*1) 10 + ((1+1)+(1+1)+1) + (1+1) + 1     (1*10, 0*5, 0*2, 8*1) Now modify the 10, in the 1st arrangement. (5+5) + 5 + 2 + 1   our 7th arrangement     (0*10, 3*5, 1*2, 1*1) (5+5) + 5 + (1+1) + 1               (0*10, 3*5, 0*2, 3*1) (5+5) + (2+2+1) + (1+1) + 1      (0*10, 2*5, 2*2, 4*1) (5+5) + (2+(1+1)+1) + (1+1) + 1    (0*10, 2*5, 1*2, 6*1) (5+5) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 2*5, 0*2, 8*1)  -- 11th arrangment (5+(2+2+1)) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 1*5, 2*2, 9*1) (5+(2+(1+1)+1)) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 1*5, 1*2, 11*1) (5+((1+1)+(1+1)+1)) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 1*5, 0*2, 13*1)   --- 14th arrangememt ((2+2+1)+((1+1)+(1+1)+1)) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 0*5, 2*2, 14*1) ((2+(1+1)+1)+((1+1)+(1+1)+1)) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 0*5, 1*2, 16*1) (((1+1)+(1+1)+1)+((1+1)+(1+1)+1)) + ((1+1)+(1+1)+1) + (1+1) + 1    (0*10, 0*5, 0*2, 18*1) --17th arrangement So, in total there are 17 arrangements of 1p, 2p, 5p and 10p coins to give 18p

### Discuss at least three applications of graph theory in the field of computer sciences?

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