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Using Newton’s method, solve the system is xyz-x^2+y^2=1.34  x y-z^2=0.09 e^x+e^y+z=0.41  by newton method to obtain a solution near (1,1,1) use three iteration only

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statistic probability

i. All the possible answers in Quiz 1 by chance can be represented by the terms in the expansion of (0.25+0.75)^8, where 0.25 is the probability of a correct choice of answer for each individual question and 0.75 is the probability of an incorrect choice of answer. The binomial expression has a value of 1, which is a probability of 1, i.e., certainty, made up of the sum of all the terms. Let p=0.25 and 1-p is 0.75. The expansion is p^8+... + 8Cr*p^r(1-p)^(8-r), where r indicates the rth term between r=0 and 8 and 8Cr is the combination function nCr for n=8. The value of 8Cr is given by (8*7*...*(8-r+1))/(1*2*...*r). The coefficients are, in order: 1, 8, 28, 56, 70, 56, 28, 8, 1, the 8th row of Pascal's triangle. The binomial terms start with the probability of 8 correct answers, then 7 correct 1 incorrect, 6 correct 2 incorrect, 5 correct 3 incorrect, and so on. The probability of answering incorrectly 3 question is (3/4)^3=27/64, so the probability of answering at least one question in 3 correctly by chance is 1-27/64=37/64, in other words, this is the probability that at most 3 questions are attempted before obtaining a correct answer. This is better than an evens chance (50%), so is more likely than unlikely. ii. In Quiz 2 p=1/5 or 0.20 and n=15. The probability of less than 4 correct answers is the sum of the last four terms of the binomial series for 15, which give all incorrect, 1, 2, 3 correct. The coefficients are respectively 1, 15, 105, 455. The p terms alone are 0.03518, 008796, 0.002199 and 0.0005498. When we multiply by the coefficients and add the terms together we get 0.6482 or 64.82% probability. iii. The probability of 6 or more correct answers in Quiz 1 is 1-(probability of up to 2 incorrect answers)=1-(0.75^8+8*0.75^7*0.25+28*0.75^6*0.25^2)=1-0.6785=0.3215 or 32.15%. This is less than 1/3, so the odds are 2:1 against Siti getting 6 or more correct answers by chance alone, which makes it reasonably unlikely. iv and v. The problem says "before the 8th question", so there need to be 5 correct answers within the first 7 questions. Using p=0.2, the probability of getting 5 correct answers out of 5 is 0.2^5=0.00032; the probability of getting 5 correct out of 6 is 6*0.2^5*0.8=0.001536; and the probability of 5 out of 7 is 21*0.2^5*0.8^2=0.0043008. Therefore the probability of getting 5 correct before the 8th question is the sum of these=0.0061568 or 0.62%, a most unlikely occurrence, less than 1 in 162.
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I need the answers for this question please : show that 2^(1/4) (1-i) is a fourth root of -2?

I need the answers for this question please : show that 2^(1/4) (1-i) is a fourth root of -2? There is a problem here. If you take 2^(1/4) (1-i) to the 4th power you get: {2^(1/4) (1-i)}^4 = 2*(1-i)^4 And (1 – i)^4 = {(1 – i)^2}^2 = {1 - 2i + (i)^2}^2 = (1 – 2i – 1)}^2 = {-2i}^2 = -4 i.e. (1 – i)^4 = -4, not -1 as needed. Your expression would need to be 2^(1/4) (1-i)/√2 to give (-2) when taken to the fourth power. Assuming the typo ... Let z = -2 i.e. z = -2(cos(2nπ) + i.sin(2nπ)),   n = 0,1,2,3, ... or, z = 2(cos(π + 2nπ) + i.sin(π + 2nπ)),   n = 0,1,2,3, ... z = 2.e^(i.(π + 2nπ))   ---- Euler’s formula Taking the fourth root of z, as Z4 = z^(1/4) Z4 = (2)^(1/4).e^(i(π/4 + nπ/2)) Z4 = (2)^(1/4). (cos(π/4 + nπ/2) + i.sin(π/4 + nπ/2)) Letting n =  0,1,2,3 Z41 = (2)^(1/4). (cos(π/4) + i.sin(π/4)) = (2)^(1/4). (1/√2 + i. 1/√2) Z41 = (2)^(1/4)(1 + i)/√2 Z42 = (2)^(1/4). (cos(π/4 + π/2) + i.sin(π/4 + π/2)) Z42 = (2)^(1/4). (cos(3π/4) + i.sin(3π/4)) = (2)^(1/4). (-1/√2 + i. 1/√2) Z42 =  (2)^(1/4). (-1 + i)/√2 Z43 = (2)^(1/4). (cos(π/4  + π) + i.sin(π/4  + π)) Z43 = (2)^(1/4). (cos(5π/4) + i.sin(5π/4)) = (2)^(1/4). (-1/√2 –  i. 1/√2) Z43 = (2)^(1/4). (-1 –  i)/√2 Z44 = (2)^(1/4). (cos(π/4 + 3π/2) + i.sin(π/4 + 3π/2)) Z44 = (2)^(1/4). (cos(7π/4) + i.sin(7π/4)) = (2)^(1/4). (1/√2 –  i. 1/√2) Z44 = (2)^(1/4). (1 –  i)/√2 The final expression, Z44, shows that the 4th fourth root of (-2) is (2)^(1/4). (1 –  i)/√2, as required
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What is 5/3 divide by 1/3?

If the question had been: what's 5 apples divided by one apple you would have said 5, wouldn't you? The question has thirds instead of apples, but the answer is still 5. Don't forget that to divide by a fraction you invert the fraction and multiply: 5/3 times 3 is 5, because 3 cancels out the denominator in 5/3. I'm sorry you didn't get your answer in 10 minutes as you wished, but I've only just seen it! There are thousands of questions coming in and questions cannot always be answered just as they come in, and you have to remember that the website is available all over the world, which is split into many time zones. Add to that the fact that the questions are answered by users, like me, who have a life outside answering and asking questions! There are meals to eat, shopping to be done, going to the office or factory, going to school, you know the sort of thing. And, of course, while your question is coming in, a user may be answering another question, perhaps a harder one. I'm sure everyone does their best to help people who have questions to answer. But, be assured that there are many users who will be only too pleased to help you. It's just a question of when. Here's a clue that may help you. Below your question you will usually find a list of similar questions, many of which will probably have been answered (shown in green with the number of answers), so if you look at them, you may well find out how to do your own question. Now that will save everyone's time!  
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What is an integer repesented 25 feet above sea level

25 feet above sea level = +25 feet up from sea level = -25 feet down from sea level Note: Positive distance upward = up Positive distance downward = down Negative distance upward = down Negative distance downward = up
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15 × [(112 - 2 × 5)2 + 14 × (37 - 26) ÷ 11] ÷ 5 - 4,605

15 × [(112 - 2 × 5)2 + 14 × (37 - 26) ÷ 11] ÷ 5 - 4,605 PLEASE HELP I HAVE A PROJECT ON STUDY ISLAND DO AND I REALLY NEED THE ANSWER ITS MY LAST QUESTION ON THERE AND IM DONE!! hELP IS NEEDED!! 15 × ((112 - 2 × 5)2 + 14 × (37 - 26) ÷ 11) ÷ 5 - 4,605 15 × ((112 - 10    )2 + 14 × (11)         ÷ 11) ÷ 5 - 4,605 Divide 11 by 11. 15 × ((102           )2 + 14 × 1                    ) ÷ 5 - 4,605 15 × ((102           )2 + 14                          ) ÷ 5 - 4,605 At this point, I'm going to make a hazardous assumption. You have used symbols to indicate both multiplication and division. However, the (102)2 does not include a symbol, so it PROBABLY means 102 squared. You COULD HAVE used ^2: ((112 - 2 × 5)^2 + 14 15 × ((102          )2 + 14                 ) ÷ 5 - 4,605 15 × ((10,404     )   + 14                 ) ÷ 5 - 4,605 15 × ( 10,418                                 ) ÷ 5 - 4,605 Here, you can divide the 15 by the 5.  3 × ( 10,418                                  )       - 4,605      ( 31,254                                    )       - 4,605 Answer: 26,649  
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how come i cant answer anymore questions?

You can only answer 10 questions at a time. It means you have to wait 1 hour to able to answer questions again. That happen to me when I asked questions. I only had to add 10 questions at a time and wait 1 hour. It depends.
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you need to say the questions first though and then people can answer it the questions you need help with
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factor the polynomial x2+9x+20

Problem: factor the polynomial x2+9x+20 i need to find the answer to thos qustion ,this question is pre-algebra ,i need to know how to factor ploynomials,what is a polynomial♦ A polynomial is an expression (as given in your statement) with one or more unknowns (in this case, x), co-efficients (the numbers that multiply the unknowns) and positive exponents (the 2 in x squared). Find factors of the constant (20) which add up to the co-efficient of x (9). x^2 + 9x + 20 = (x + 5) * (x + 4)  
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round 58.7694 to the nearest tenth?

The 7 is in the tenths place.  The next digit to the right (6) is greater than or equal to 5, so the 6 rounds up. Answer:  58.8 . Whining and complaining = no one answers your question for 2  1/2 years.
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How do i resolve these?

The whole number is hours, so that's 1 hr. Subtract 1 to give 0.666... and multiply by 60=40 min. The seconds will be zero. To solve in general: example 2.345 hr. Whole number is hrs: 2. Subtract 2: 0.345, multiply by 60=20.7; whole number is minutes: 20. Subtract 20: 0.7, multiply by 60=42; this is the number of seconds, so the conversion is 2hr:20m:42s.   Multiply through by 4: 4C=s(t-d); divide through by s: 4C/s=t-d; add d to each side: (4C/s)+d=t so t=(4C/s)+d. The brackets aren't absolutely necessary, but they prevent ambiguity in interpretation.  
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