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what does 3p^0 equal to?

What does 3p to the power of 0 equal to?

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4 -3p >19 What does it equal too? - Brainly.com


4 -3p >19 What does it equal too? 2. Ask for details ; Follow; Report; by JEMALDONADO 04/15/2016. ... 0. Thanks. 0. This question is archived. Ask new question. The ...
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What does p equal........ - Brainly.com


What does p equal ..... Download ... 13-12p+4p=-2-5p 13-8p=-2-5p 15=3p p=5 Thus,p is equal to 5. Comments; ... Section A is from x = 0 to x = 1 and Section B is from ...
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3p-5 equals 9-4p p equals - Answers.com


Answers.com ® WikiAnswers ® Categories Science Math and Arithmetic Mathematical Finance 3p-5 equals 9-4p p equals? ... What is equal to 5c? ... Ob pigman10.0.
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1/3p + 7 = 12 - 2/3p what does P equal first check how Avril ...


1/3p + 7 = 12 - 2/3pwhat does P equal first check how Avril did it on her question ... 3 i say yes k is greater than or equal to 5; 0 i say no 3z is less than ...
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What does (x^2+4x+4) / (x+2) equal? | Socratic


What does # (x^2+4x+4) / (x+2) # equal? ... If #2.50x10^3# grams excess #Ca_3P_2O_8# are ... If the frequency of a homozygous dominant genotype is 0.49, ...
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Powers 2 - Laboratory for Atmospheric and Space Physics


... well 2 × 2 gives 4 and so does ... So the square root of 4 is equal to ±2 (the ... Algebraic Rules for Working with Fractional Powers. Defining ...
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15 Answers - UMass Amherst


The number of ways of selecting 10 items from a batch of 100 items equals ... We can answer the problem ... (the number does not matter). Then 10;000 0:05 D ...
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Why does 0 factorial equal 1? - The Math Forum at NCTM


Why does 0! = 1? Is this like ... Why does 0 factorial equal 1? Date: 03/18/98 at 13:10:04 From: Denise Chavis Subject: 0 factorial = 1 Why does 0! = 1?
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Suggested Questions And Answer :


How do you find the interval of increase and decrease on a graph?

~~INFORMATION OF THE GRAPH: Domain: IR Range: y ≤  2     <- is the range the y from your vertex?  how would you know what sign to put (greater than or equal to/ less than or equal to) Vertex: (-3 , 2) Zeros: x = -1 , -5 Interval of increase: x ≤ -3        <-  how do you knonw what sign it is (greater than or equal to/ less than or equal to) and is it always going to be x greater/less than or equal to? or will it sometimes be y greater/less than or equal to? Interval of decrease: x  ≥ -3       <- how do you know what sign to put for this one as well?   Okay think about the function.  The vertex is (-3,2), and the x values are -1 -5.  since there are two x-values that means the function is in the format of x^2.  it tells me that it is a parabola.  it faces down because the vertex is the highest point. the range ("Y" values) are less than equal too. the domain ("X" values) is infinity all "X"values. to find the increase or decrease you take the derivitive and the slope at that point is the increase or decrease.
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how can i tell what number to add or subtact from when solving varibals

Go to each side of the equal sign and combine your x's (or variables of like kind) then your numbers (constants) without x's (or other variables of like kind) and use the sign in front of the term, and when there is no sign, it may be positive or + in most cases! How does this answer your question? If you have two terms one has an "x" and the other just a number, alone those are not "like kind" (one is a constant(for example "5") and the other a variable(Ffor example "x")) and should not be combined because one is part of the variables and the other is part of the constants. When I say "combine" this is where you "add or subtract" those variables or like terms. In the example you provided the variable with the equal sign, erasing the rest of the problem reads "2x+3x=" Notice how they are both on the same side of the equal sign, in this case you just do as it reads "2x+3x=" or "5x=" do not forget to keep that equal sign so you can determine where the rest of the terms go. Sometimes you will encounter variables or other terms on the other side of the equal sign, in a case like this simply combine like terms on one side of the equal sign and then  do the same to the other, no particular order but some say it is easier to use a method or pattern. EXAMPLE 2x+5x+5+2= -5x-13x+32. Do not get scared it only looks more challenging then it is. IF you picture your variables with everything else other than the equal sign erased you will have "2x+5x=-5x-13x" I know this will not work out as a problem, just use it as a visual. and combine. You should get "7x=-18x". You could go even further and move your x's to one side or just wait until that step. In the example I provided it requires an extra step that some call reversing/negating the terms and others in your book call it something similiar. Just a thought!! Lastly, move your variables to one side of the equal sign and your constants to the other side of the equal sign. It really does not matter what side unless you see an easy way to solve, but variables must always be on that one side of the equal sign you pick and constants on the other side of the equal sign. Usually 25x=25 or x=1, and 25=x or 1=x no matter what order if you do not mind the multiplication rule of multiplying negatives and positives. that is where you create you easy method.
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How do the corollaries to the Isosceles Triangle Theorem and it's converse follow from the theorems?

The theorems and corollaries I can think of are: If two sides of a triangle are of equal length then the two angles they make with a common base are also equal. The triangle is isosceles. If two angles of a triangle are equal then the sides forming these angles have equal length. The triangle is isosceles. The converses and their corollaries are: if no sides of a triangle are equal in length then none of its angles are equal and it is not an isosceles triangle. Also, if no angles of a triangle are equal, none of its sides have equal length and it is not an isosceles triangle. The triangle is scalene. An isosceles triangle with all three angles the same is an equilateral triangle. An isosceles triangle with all sides the same length is an equilateral triangle. The corollaries usually follow through proofs using congruency of triangles, more specifically by splitting the isosceles triangle into two back-to-back right-angled triangles, which are congruent.
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Urgent! Please help!

y=sqrt(x)-4x, 0<=x <=4 max: at x=0, y=0 . . min: at x=4, y=2-8=-6
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ABCD is a parallelogram. EF has been drawn parallel to BD such that it intersects the side AB at E and the side AD at F.

In the parallogram triangles ABC and ACD are equal in area because they're congruent: AB=DC and AD=BC (opposite sides have equal length and both triangles ar between the same parallel lines AB and DC so they have equal area. Area of ACD=CDF+ACF and ABC=BCE+ACE. So (i) and (ii) are related by this commonality. (i) DF/AD=FG/AH (reduction in height CDF and ACD), BE/AB=EQ/AP (reduction in height BCE and ABC). Area BCE/area ABC=EQ/AP=BE/AB (triangle ABP), Area CDF/area ACD=FG/AH=DF/AD (triangle ADH). AE+BE=AB, AF+DF=AD. AF/AD+EQ/AP=AE/AB+BE/AB=(AE+BE)/AB=AB/AB=1. AE/AB+FG/AH=AF/AD+DF/AD=(AF+DF)/AD=AD/AD=1. EQ/AP=1-AF/AD and FG/AH=1-AE/AB. But AE/AB=AF/AD therefore EQ/AP=FG/AH. Since the heights of the triangles (of equal area initially) are reduced by the same amount, their areas are also so reduced. This makes them equal in area. In the picture, the heights of the triangles are shown by the perpendiculars FG, AH, EQ, AP. For part (ii), having established (i) and knowing that the area of ACD=CDF+ACF and ABC=BCE+ACE, the areas of ACF and ACE are also equal.  
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solve: the absolute value of 2x minus 5 is greater than or equal to seven.


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How to solve 4(x-2)+4>or equal to sign 12?

4(x - 2 ) + 4  > or equal 12 4x - 8 + 4  > or equal 12 4x > or equal 16 x >  or equal 16/4 x > or equal 4
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if 33% equals 1,000,000 what does 1% equal?

33% equals 1,000,000 what does 1% equal   1000000/33=30303.03
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show that the function f(x)= sqrt (x^2 +1) satisfies the 2 hypotheses of the Mean Value Theorem

f(x) = sqrt(x^2 + 1) ; [(0, sqrt(8)] Okay, so for the Mean Value Theorem, two things have to be true: f(x) has to be continuous on the interval [0, sqrt(8)] and f(x) has to be differentiable on the interval (0, sqrt(8)). First find where sqrt(x^2 + 1) is continous on. We know that for square roots, the number has to be greater than or equal to zero (definitely no negative numbers). So set the inside greater than or equal to zero and solve for x. You'll get an imaginary number because when you move 1 to the other side, it'll be negative. So, this means that the number inside the square root will always be positive, which makes sense because the x is squared and you're adding 1 to it, not subtracting. There would be no way to get a negative number under the square root in this situation. Therefore, since f(x) is continuos everywhere, (-infinity, infinity), then f(x) is continuous on [0, sqrt(8)]. Now you have to check if it is differentiable on that interval. To check this, you basically do the same but with the derivative of the function. f'(x) = (1/2)(x^2+1)^(-1/2)x2x which equals to f'(x) = x/sqrt(x^2+1). So for the derivative of f, you have a square root on the bottom, but notice that the denominator is exactly the same as the original function. Since we can't have the denominator equal to zero, we set the denominator equal to zero and solve to find the value of x that will make it equal to zero. However, just like in the first one, it will never reach zero because of the x^2 and +1. Now you know that f'(x) is continous everywhere so f(x) is differentiable everywhere. Therefore, since f(x) is differentiable everywhere (-infinity, infinity), then it is differentiable on (0, sqrt(8)). So the function satisfies the two hypotheses of the Mean Value Theorem. You definitely wouldn't have to write this long for a test or homework; its probably one or two lines of explanation at most. But I hope this is understandable enough to apply to other similar questions!
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2x=3(x-4)=2(x-3)

2x=3(x-4)=2(x-3) How can I solve this? You can't. Even though it is possible to string together multiple equalities, that requires ALL of them to be equal. In this string, the second may in fact be considered to be equal, and you could use the first and second quantities to calculate a value for x. However, the third quatity obviously cannot equal the first quantity. Take those two and try to solve. 2x = 2(x-3) 2x ≠ 2x - 3 I changed the sign to an inequality, because there is no number in existence that is equal to a number that is smaller, or larger, than itself. For the sake of clarity, solve the first equation formed by the first two quantities. 2x = 3(x - 4) 2x = 3x - 12 2x - 3x = 3x - 12 - 3x -x = -12 x = 12 If you try to use that to solve the second "equation," you will see the obsurdity of it. 3(x - 4) = 2(x - 3) 3(12 - 4) = 2(12 - 3) 3(8) = 2(9) 24 = 18 If you believe that 24 equals 18, you are a victim of Common Core.
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