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# which one is bigger between -(3) and -(-3)?

First frog jumps -(3) and second frog jumps -(-3). Which one is bigger?

## Research, Knowledge and Information :

### The fraction 2/3 is found between which pair of fractions on ...

The fraction 2/3 is found between which pair of fractions on the ... You know that 2/3 is bigger than 1/2 ... One circle could be divided into 3 equal pie ...

### How to compare irrational numbers? For example, which one is ...

For example, which one is bigger between ³√5 and ⁴√2? Update Cancel. Answer Wiki. 5 Answers. Anthony Clohesy, ... (one which is a multiple of 3 and 4) ...

### How do you find the fraction between 1/3 and 1/4? | Socratic

How do you find the fraction between 1/3 and 1/4? ... All of these are found between #1/3# and #1/4#. ... Write a one sentence answer ...

### Which is greater, 1/4 or 2/3? (fraction form) - YouTube

Feb 29, 2008 · Which is greater, 1/4 or 2/3? Find the lowest common denominator to solve

### What Number is halfway between 1/2 and 3/4 on a ... - Socratic

What Number is halfway between 1/2 and 3/4 on a number line? Algebra Properties of Real Numbers Properties of Rational Numbers. ... Write a one sentence answer...

### The Difference Between 5/8- and 3/4-Inch Garden Hose | Hunker

The Difference Between 5/8- and 3/4 ... the 5/8-inch and 3/4 ... remember that a 5/8-inch hose is 0.625 inches in diameter while a 3/4-inch hose is slightly bigger at ...

### Which one is bigger? 3^pi or pi^3? How can I do mental math ...

Which one is bigger? 3^pi or pi^3? How can I do mental math with this? ... That's a little bigger than the right answer for Pi^3 but 3 ... 4/3, which one is bigger ...

### Which number is smaller 0.34 or 0.3 - Answers.com

Which number is smaller 0.34 or 0.3? ... and simplify: 25/100 = 1/4 Any decimal number that repeats one or more digits forever ... 0.38 is larger than 0.3. Edit.

## Suggested Questions And Answer :

### What is the area of the bigger triangle?

What is the area of the bigger triangle? the smaller triangle has an area of 315 inches squared.  the similar triangle has sides one and one third times bigger than the other triangle. a = 1/2(bh) = 315 sq in A = 1/2(4/3 b)(4/3 h) A = (4/3)(4/3)(1/2(bh) A = (4/3)(4/3)a A = (16/9) * 315 A = 16 * 35 A = 560 sq in

### Which inequality is true?

When comparing negative numbers, the smaller one is the leftmost one. When comparing negative and positive numbers, the positive numbers are all to the right so positive numbers are always bigger than negative numbers. 1/4 is positive so it is bigger than every negative number. It's one division to the right of zero while -1 2/4 is to the left meaning that 1/4>-1 2/4. So first answer is false. -2 3/4 is to the left of -1 1/2 so it's smaller. This answer is true. -2 1/4 is left of -1 1/4, not to the right. This answer is false. 1 3/4 is positive so it is bigger than all negative numbers. This answer is false. -3/4 is not bigger.

### How can you tell before doing the actual operation if a quotient of two fractions will be greater or less than one?

If the fraction is a/b, then if a>b the fraction is bigger than 1; if ab, if negative then ab and the quotient will be bigger than 1. You can also convert the fractions to decimal or percents to see which is bigger: 2/3=0.67 (67%) approx and 3/5=0.60 (60%) making 0.67 bigger than 0.60, or 2/3>3/5.

### 64239 is divided by a certain number.while dividing the number 175,114 and,213 appears as three successive remainders.find the divisor ?

It's not clear what "successive remainders" means. There is only one remainder after a division: (dividend)=(quotient)*(divisor)+(remainder). For example, if 175 is the remainder after division then 286 divides into 64239 224 times, remainder 175. The largest remainder is 213, implying that the divisor is bigger than 213. It's clear that the divisor cannot be divided again by the same divisor to yield a remainder in excess of the divisor. In the example 286 will not divide into 224, so 224 would be a second remainder. If the divisor has to be used three times to divide successively into each quotient to obtain each remainder then the divisor cannot exceed 40 (the approximate cube root of 64239) and therefore the remainders cannot exceed 40. See explanations in square brackets below. The only other interpretation I can find to the question is that in the process of long division, we have the successive remainders as we proceed with the division. But that doesn't seem to work either. [The numbers a, b and c are integers and b=cx+213; a=bx+114; 64239=ax+175, making ax=64064. Combining these equations we get: a=64064/x=bx+114, so b=64064/x^2-114/x=cx+213, and c=64064/x^3-114/x^2-213/x. Because 64064=ax, we see that 64064 must be divisible by x. 64064 factorises: 2^6*7*11*13. Because the largest remainder is 213, x>213, because x must be bigger than any remainder it creates. But the first term 64064/x^3 can only yield an integer value if x^3<64064, that is, x<40, which contradicts the requirement x>213.] [If the successive remainders appear in the long division, and the divisor has 3 digits as expected, and three remainders suggest that the other factor also has 3 digits, then if 175 is the first remainder it must be the result of dividing the divisor into 642. Therefore the multiple of the divisor =642-175=467. Since 467 is prime then the first digit of the other factor must be 1. 64239 divides by 467 137 times with 260 as the remainder. This is not one of the three remainders, so 175 cannot be the first remainder. Try 114: 642-114=528=2^4*3*11. We need a factor >213. 264, 352. This time we appear to have partial success, because 176 (less than 213, but half of 352) goes into 64239 364 times with a remainder of 175! So we have two of the three required remainders. Unfortunately the third remainder is 87, so 114 cannot be the first remainder. Finally, try 213: 642-213=429=3*11*13. The only factor bigger than 213 is 429 itself, and the final remainder after dividing 64239 by 429 is 318, not included in the three remainders given. So the assumption that the remainders arise during long division is also false.] 64064=2^6*7*11*13. Leaving aside the powers of 2, and just looking at combinations of 7, 11 and 13, we get 7*11=77; 7*13=91; 11*13=143, and 7*11*13=1001. By progressively doubling these products we can discover factors bigger than 213: 308=4*77; 364=4*91; 286=2*143, etc. We can also take 7, 11 and 13 and multiply them by powers of 2: 224=32*7; 352=32*11; 416=32*13. We can write the factors of 64064 in pairs, starting with a factor a little bigger than 213: (224,286), (308,208), (352,182), (364,176), (416,154), (448,143), (616,104), (704,91), (1001,64), (1232,52), (2002,32), (2464,26), (4004,16), (4928,13), (8008,8), (16016,4), (32032,2). These are (a,x) or (x,a) pairs. If we take 175 as the remainder, and ignore the other two, then we have a choice of factors. The 3-digit factors are (224,286), (308,208), (352,182), (364,176), (416,154), (448,143), (616,104). The only pair in which each factor is greater than 213 is (224,286).

### David puts 5/7 of a jar on his sandwitch, he also puts 3/9 of a jar on his sandwitch.3 buddies at his house. He wants to give them the same amount. Explain why you should multiply or divide..

Let's see how many jars are implied. 5/7 of a jar leaves 2/7 left in the jar. 3/9 or 1/3 taken out of a jar leaves 2/3. Could it be the same jar? In other words, is there enough left in one jar to do this? To answer this question in simple terms, let's divide the jar into 21 portions. 2/7 of 21 is 6 portions and 1/3 of 21 is 7 portions. So it cannot be the same jar because we can't take 7 portions out of it if only 6 portions are available. That means there must be two jars. There will be 6 portions left in one jar and 14 in the other. If he needs to provide his 3 buddies with the same proportion as himself, his buddies will also need 5/7 of 21 portions=15 portions each, so he will need 3*15= 45 portions from one jar, which only has 6 portions left. What about the other jar? After taking 7 portions from the other jar, he's left with 14. His three buddies need 7 portions each, making 21 portions. But there are only 14 left in this jar. He will need more jars! All we've done is use 21 portions instead of fractions of a jar. 1 portion is 1/21 of a jar and 21 is the lowest common denominator of 3 and 7. We could have picked the lowest common denominator of 7 and 9, which is 63, and worked out how many portions. But the conclusions would be the same. 5/7 of 63=45 and 2/7=18. 3/9 or 1/3 of 63=21, and 21 is bigger than 18, so we don't have enough portions left to take out 21. This is another way of saying 1/3 is bigger than 2/7. The only way to split what's left in the jars is to divide the remains equally between the buddies, but that means they all get equal shares between themselves, but no-one gets as much as David. They would get 1/3 of 2/7 from one jar and 1/3 of 2/3 from the other jar: 2/21 and 2/9 respectively, and if the jars had been split into 63 portions, that would be 6 portions and 14 portions each. David's portions would be 45 and 21, a lot more! 45+3*6=63=21+3*14. See how the arithmetic works?

### what happens when you multiply a decimal greater than zero by a decimal greater than one?

A decimal greater than zero but less than 1 is a fraction. For example, 0.25 is a fraction 25/100 which is a quarter. It has the effect in the product of reducing the value of whatever it multiplies or "of-ed". We say a quarter of something meaning a quarter times something. A decimal bigger than 1 makes whatever it multiplies bigger in the product. 1.5 for example times something makes the product half as big again as the number it's multiplying. When we multiply a decimal greater than zero but less than 1 by a decimal bigger than 1, the product may still be bigger than 1.

### What is bigger? 5 and 1/5 OR 5 and 18/60

five and one fith because if the fraction is cut into a smller number it is bigger like one half is bigger then 5/18 because it is not cut into alot of peaces

### whats the answer to -2x + 3 > 3(2x - 1)

We need to expand the brackets on the right: -2x+3>6x-3. Add 2x to each side of the inequality: 3>8x-3 and add 3 to each side: 6>8x. Another way of writing this is 8x<6. Divide through by 2: 4x<3 and divide through by 4: x<3/4. We added 2x to each side because that helps us to bring the x's together. We added 3 to each side to bring the numbers together. Now we've ended up with x's on one side and a number on the other. Just what we want. 2 is common to 6 and 8 so we simplify the inequality by dividing through by it. Then to get x instead of 4x we divided through by 4. Why is 6>8x the same as 8x<6? Well, think about it. 2<3, isn't it? So 3>2. That's true. If Jack is taller than Jill, then Jill is shorter than Jack. See how it works? You just reverse the inequality when the quantities swap sides. It's a good idea to check your answer by substituting a value for x in the original inequality, just to make sure we haven't made a mistake. The answer was that x must be less than 3/4 so let's try x=1/2. -2x+3 is -1+3=2. Now the right side: 2x-1 is 1-1=0 multiplied by 3 is still zero. Is the inequality correct? Yes it is, because 2 is greater than zero. If we put x=1 we should find that the inequality doesn't work out because x is bigger than 3/4. Let's see. The left is 3-2=1 and the right is 3. 1 isn't bigger than 3, so the inequality is false, as expected. If we put x=3/4 we will find that the left equals the right when it should be bigger than it. Looks like x<3/4 is right!

### Which one is bigger 1.4,1.7, or 1

Which one is bigger 1.4,1.7, or 1 1.4 = 1 and 4/10 1.7 = 1 and 7/10 or 1 you choose, remember one decimal place is part of ten, two decimal places is part of 100, etc.

### Which is bigger .17 or .23 acres?

.23 acres same unit of measurement, so you only have to work out which number is bigger