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What is an equation for three times the sum of a number and 4 is the same as 18 more than the number

three times the sum of a number and 4 us the same as 18 more than the number

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Three times the sum of a number and 4 is the same as 18 more ...


... times the number and 4 is 3xx x+4=3x+4 18 more than the number is 18+x As the two are same, we have 3x+4=18+x or 3x ... Three times the sum of a number and 4 is ...
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Write an equation to represent each relationship. Then solve ...


Write an equation to represent each relationship. ... Three times the sum of a number and 4 is the same as 18 more ... Two less than 2 times a number is the same as ...
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What is the equation to the sum of a number and 4 ... - Answers


What is the equation to the sum of a number and 4, ... No. 1 Questions & Answers Place. More questions about ... three times the sum of a number and 16 17. 18 ...
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Three multiplied by the sum of 4 and a number is the same as ...


Three multiplied by the sum of 4 and a number is the same as 18 more than the number. ... as 18 more than the number. If n is "the number," which equation could be ...
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The sum of twice a number and 4 times the same number?


Let's call the number XTwice the number would be 2XFour times the same number would be 4XThe sum ... sum of three times a number and 7 more than ... number is 18 ...
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Writing Algebraic Equations for word sentences - Math Goodies


Writing Algebraic Equations is presented ... An algebraic equation is an equation that includes one or more ... Five less than three times a number is ...
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writing one-operation equations, expressions, statements


writing one-operation equations, expressions, statements ... four more than a number: x + 4 or 4 + x ... the opposite of the sum of a number and three -(x+3) or - ...
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Translating Verbal Expressions – Terms - Del Mar College


Translating Verbal Expressions – Terms . ... increased by a number . increased by. three . n + 3. more than ... Six plus five times a number is less than the sum of ...
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Writing Expressions and Equations


Lesson 7.1 Writing Expressions and Equations 317 Word Watch ... The sum of 4 times a number and 3 is 27. ... 2. 4 more than a number A. 4 x 3.
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Algebraic Translations - MathBitsNotebook(A1 - CCSS Math)


... algebraic expressions do not contain an equal sign. ... sum increased by more than exceeds total ... Three times a number, ...
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Suggested Questions And Answer :


The sum of two numbers is 73. Find the numbers if one number is 15 less than three times the other.

The sum of two numbers is 73. Find the numbers if one number is 15 less than three times the other. x + y = 73 (x-15) = 3y  ------> x = 3y + 15 Substitute (3y + 15) + y = 73 Collect like terms 3y + y = 73 -15 ------> 4y = 58 Divide by 4 to isolate y 4y/4 = 58/4 ------------> y = 14.5 Substitute into given equation x + y = 73 x + 14.5 = 73 ---------------> x = 73 - 14.5 -------> x = 58.5 Thus y = 14.5 and x = 58.5  
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1. Set up the following word problem as an equation and solve. Then write your answer as a complete sentence. The ratio of two numbers is 3 to 5. Their sum is 136. Find the two numbers.

Let the 2 numbers be A and B. A/B=3/5; A+B=136. So B=136-A and we can substitute B in the other equation: A/(136-A)=3/5. Cross-multiply: 5A=3(136-A)=408-3A. 8A=408, A=408/8=51. B=136-51=85. Check the answer: A/B=51/85=3/5.  In words: This is a problem with two unknowns, A and B, and two equations. We use one equation to write one unknown in terms of the other (B is 136 less A), then we substitute for that unknown in the other equation to give A divided by (136 minus A). That gives us one equation and one unknown, A, where the quotient is equal to three fifths. By cross-multiplying to get rid of the fraction, we arrive at five times A is equal to 3 times B which is known to be 136 less A. Now we collect the A terms together to give 8 times A equal to the product of 3 and 136, that is 408. From this we simply divide 408 by 8 to get A equal to 51, then, by subtracting this value from 136 we get B equal to 85. 51 is 3 times 17 and 85 is 5 times 17 so the quotient is three fifths.
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the sum of two numbers is 7.2. the second number is 9.6 less than three times the first. what are the numbers?

Let the numbers be a and b and let b be the second number, so b=3a-9.6 and a+b=7.2, and b=7.2-a. Substitute this in the other equation: 7.2-a=3a-9.6; 4a=7.2+9.6=16.8, so a=16.8/4=4.2. Therefore b=7.2-4.2=3. Check these values for a and b: b=3a-9.6: 3=3*4.2-9.6=12.6-9.6=3. Correct!
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a two digit number in base ten is equal to 5 times the sum of the digits. it is 9 less than the number formed when the digits are interchanged. find the number

a two digit number in base ten is equal to 5 times the sum of the digits. it is 9 less than the number formed when the digits are interchanged. find the number Let the two digits be a and b, such that the number n = ab, meaning n = 10a + b, then n = 5(a + b)        (a two digit number in base ten is equal to 5 times the sum of the digits) n = (10b + a) - 9      (it is 9 less than the number formed when the digits are interchanged.) Our three equations then are, n = 10a + b     ------------------------ (1) n = 5a + 5b     ------------------------ (2) n = a + 10b - 9    --------------------- (3) 2*(2) - (1), 5*(3) - (2) n = 9b 4n = 45b - 45 substituting for n = 9b, 36b = 45b - 45 9b = 45 b = 5, a = 4 ​Ans: number is n = 45
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The sum of two numbers is 84 but one number is three times the other so what are the numbers?

1.....x+y=84 2....y=3x so x+3x=84 4x=84 x=84/4 x=21 y=36
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need perimeter & area..help

I answered this question a few days ago, and at that time the dimensions of the water cases were accidentally given in feet instead of inches. I can see that's been coorected now. I'll go over the solution again, and give some answers on the perimeter and area. First, the volume of a case: 10.2*15.1*8.3=1,278.366cu in=0.74cu ft (approx). Each crate has three dimensions, but the way to lay out the crates to circumscribe the earth with the minimum number of crates is by their lengths. 2.6*10^9 (2.6 billion) laid lengthwise is 3.926*10^10 inches=619,633.8 miles=24.88 equators approx. The volume of that number of cases is 2.6*10^9*1,278.366=3.32375*10^12cu in=1.92347 billion cu ft=0.01307 cu miles. The perimeter of the cases if laid in a long line with the bottles upright would be 2*(3.926*10^10+8.3)in=7.852*10^10in=1,239,267.7 miles approx (the case width is so small in comparison the length of all those crates can be ignored). The surface area would be the sum of the areas of the three visible sides. We can ignore the areas of the exposed ends of the first and last cases compared to the rest of the surface areas. Total exposed surface areas: 2.6*10^9(2*15.1*10.2+15.1*8.3)=2.93*10^21 sq in=2.034*10^19 sq ft=7.30*10^11 sq miles.
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Add three to a number, then multiply your number by 4

y=4*(x+3) ....................
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10-5+4+1-10+5-2=10?

Assuming that addition and subtraction are the only allowable operations, we can see that the equality cannot be realised, because on the left-hand side there are an even number of even numbers and an odd number of odd numbers. No combination of addition and subtraction can produce an even number. So if brackets are used to group the operands on the left, the result will nevertheless be an odd number, and the right-hand side is even. The next plan is to change the base of the numbers to the lowest odd number. The largest digit is 5. The nearest odd number to 5 is 7. Therefore 10 represents the decimal number 7. So to base 7 we have 5 odd numbers and two even numbers. The result will therefore be odd. But this time the right-hand side is odd, because 10 represents the number 7. The sum becomes 7-5+4+1-7+5-2=7, which is still not correct. But if we insert brackets to group some of the numbers together we can write: 7-(5+4+1-7)+5-2=7. This is an exact equation. The three 7's can now be replaced by 10 and the equation interpreted by calculating in base 7 instead of in decimal.
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how to factorise fully

I can offer tips: Look out for constants and coefficients that are multiples of the same number, e.g., if all the coefficients are even, 2 is a factor. If 3 goes into all the coefficients, 3 is a factor. Place the common numerical factor outside brackets, containing the expression, having divided by the common factor. In 2x^2+10x-6 take out 2 to give 2(x^2+5x-3). In 24x^2-60x+36 12 is a common factor so this becomes: 12(2x^2-5x+3). This also applies to equations: 10x+6y=16 becomes 2(5x+3y)=2(8). In the case of an equation, the common factor can be completely removed: 5x+3y=8. Now look for single variable factors. For example, x^2y^3+x^3y^2. Look at x first. We have x^2 and x^3 and they have the common factor x^2, so we get x^2(y^3+xy^3) because x^2 times x is x^3. Now look at y. We have y^2 and y^3 so now the expression becomes x^2y^2(y+x). If the expression had been 2x^2y^3+6x^3y^2, we also have a coefficient with a common factor so we would get: 2x^2y^2(y+3x). If you break down the factors one at a time instead of all at once you won't get confused. After single factors like numbers and single variables we come to binomial factors (two components). These will usually consist of a variable and a constant or another variable, such as x-1, 2x+3, x-2y, etc. The two components are separated by plus or minus. In (2) above we had a binomial component y+x and y+3x. These are factors. It's not as easy to spot them but there are various tricks you can use to help you find them. More often than not you would be asked to factorise a quadratic expression, where the solution would be the product of two binomial factors. Let's start with two such factors and see what happens when we multiply them. Take (x-1) and (x+3). Multiplication gives x(x+3)-(x+3)=x^2+3x-x-3=x^2+2x-3. We can see that the middle term (the x term) is the result of 3-1, where 3 is the number on the second factor and 1 the number in the first factor. The constant term 3 is the result of multiplying the numbers on the factors. Let's pick a quadratic this time and work backwards to its factors; in other words factorise the quadratic. x^2+2x-48. The constant term 48 is the product of the numbers in the factors, and 2 is the difference between those numbers. Now, let's look at a different quadratic: x^2-11x+10. Again the constant 10 is the product of the numbers in the factors, but 11 is the sum of the numbers this time, not the difference. How do we know whether to use the sum or difference? We look at the sign of the constant. We have +10, so the plus tells us to add the numbers (in this case, 10+1). When the sign is minus we use the difference. So in the example of -48 we know that the product is 48 and the difference is 2. The two numbers we need are 6 and 8 because their product is 48 and difference is 2. It couldn't be 12 and 4, for example, because the difference is 8. What about the signs in the factors? We look at the sign of the middle term. If the sign in front of the constant is plus, then the signs in front of the numbers in the factors are either both positive or both negative. If the sign in front of the constant is negative then the sign in the middle term could be plus or minus, but we know that the signs within each factor are going to be different, one will be plus the other minus. The sign in the middle term tells us to use the same sign in front of the larger of the two numbers in the factors. So for x^2+2x-48, the numbers are 6 and 8 and the sign in front of the larger number 8 is the same as +2x, a plus. The factors are (x+8)(x-6). If it had been -2x the factors would have been (x-8)(x+6). Let's look at a more complicated quadratic: 6x^2+5x-21. (You may also see quadratics like 6x^2+5xy-21y^2, which is dealt with in the same way.) The way to approach this type of problem is to look at the factors of the first and last terms. Just take the numbers 6 and 21 and write down their factors as pairs of numbers: 6=(1,6), (2,3) and 21=(1,21), (3,7), (7,3), (21,1). Note that I haven't included (6,1) and (3,2) as pairs of factors for 6. You'll see why in a minute. Now we make a table (see (5) below). In this table the columns A, B, C and D are the factors of 6 (A times C) and 21 (B times D). The table contains all possible arrangements of factors. Column AD is the product of the "outside factors" in columns A and D and column BC is the product of the "inside factors" B and C. The last column depends on the sign in front of the constant 21. The "twiddles" symbol (~) means positive difference if the sign is minus, and the sum if the sign in front of the constant is plus. So in our example we have -21 so twiddles means the difference, not the sum. Therefore in the table we subtract the smaller number in the columns AD and BC from the larger and write the result in the twiddles column. Now we look at the coefficient of the middle term of the quadratic, which is 5 and we look down the twiddles column for 5. We can see it in row 6 of the figures: 2 3 3 7 are the values of A, B, C and D. If the number hadn't been there we've either missed some factors, or there aren't any (the factors may be irrational). We can now write the factors leaving out the operators that join the binomial operands: (2x 3)(3x 7). One of the signs will be plus and the other minus. Which one is which? The sign of the middle term on our example is plus. We look at the AD and BC numbers and associate the sign with the larger product. We are interested in the signs between A and B and C and D. In this case plus associates with AD because 14 is bigger than 9. The plus sign goes in front of the right-hand operand D and the minus sign in front of right-hand operand B. If the sign had been minus (-5x), minus would have gone in front of D and plus in front of B. So that's it: [(Ax-B)(Cx+D)=](2x-3)(3x+7). (The solution to 6x^2+5xy-21y^2 is similar: (2x-3y)(3x+7y).) [In cases where the coefficient of the middle term of the quadratic appears more than once, as in rows 1 and 7, where 15 is in the twiddles column, then it's correct to pick either of them, because it just means that one of the binomial factors can be factorised further as in (1) above.] Quadratic factors A B C D AD BC AD~BC 1 1 6 21 21 6 15 1 3 6 7 7 18 11 1 7 6 3 3 42 39 1 21 6 1 1 126 125 2 1 3 21 42 3 39 2 3 3 7 14 9 5 2 7 3 3 6 21 15 2 21 3 1 2 63 61  
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What is an equation for three times the sum of a number and 4 is the same as 18 more than the number

3(x+4)=x+18 3x+12-x=18 2x=18-12 2x=6 x=3
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