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# six times a number is subtracted from eight times its reciprocal. The result is 47. Find the number

six times a number is subtracted from eight times its reciprocal. The result is 47. Find the number

## Research, Knowledge and Information :

### eight times the reciprocal of a number equals 2 times the ...

Three times the reciprocal of a number equals 9 times the reciprocal of 6. Find the number. ... number equals 47 and 10 times ... reciprocal of a number , the result ...

### Three times the reciprocal of a number equals 9 times the ...

The sum of a number and 20 times its reciprocal is 9. Find the number ... 3 times the second number equals 47 and 10 ... number is subtracted from six times the ...

### Three times the reciprocal of a number equals 9 times the ...

Three times the reciprocal of a number equals 9 times the reciprocal of 6 ... times a number is subtracted from ... times its reciprocal the result is 14 find ...

### TRANSLATE WORD SENTENCES INTO ALGEBRAIC EXPRESSIONS

... Eight subtracted from two times a number. ... The sum of a number and its reciprocal is equal to four. ... TRANSLATE WORD SENTENCES INTO ALGEBRAIC ...

### less than or subtracted from - Mt. San Antonio College

greater than ratio of the result is ... “less than ” or “subtracted from ”. ... Twice a number less than four is equal to six times a number plus five. 2 ...

### PRACTICE PROBLEMS INVOLVING RATIONAL EXPRESSIONS

PRACTICE PROBLEMS INVOLVING RATIONAL EXPRESSIONS. ... The sum of a number and its reciprocal is 17/4. Find the ... times a number is subtracted from twice its ...

### Translating Words into Mathematical Symbols

Translating Words into Mathematical Symbols ... The sum of 4 times a number n and 7 4n + 7 ... sum The result of adding numbers

### Translating Verbal Expressions – Terms - Del Mar College

Translating Verbal Expressions – Terms . ADDITION: ... The difference of four times a number and six 4x – 6 ... 2/6/2017 8:47:06 AM ...

## Suggested Questions And Answer :

### six times a number is subtracted from eight times its reciprocal. The result is 47. Find the number

me thank yu tri tu sae (8/x) -6x=47 8 -6x^2-47x=0 or 6x^2 +47x-8=0 quadratik equashun giv roots=0.16666666, & -8

### if eight times a number is subtracted from eleventimes the number,the result is -9.find the number.

This is P.ANDRONICUS so sumprobulums group 4 results so I forgot hall ticket nember so best answers tell me know so I will reqist sir&madam.

### how do i add fractions

To add or subtract fractions, obtain a least common denominator. Subtract the numerators in the correct order and retain the same least common denominator for your answer. Simplify. To multiply fractions, multiple the numerators. The product will be the numerator of your answer. Repeat with denominators. Simplify. To divide fractions, take the reciprocal of what you are dividing by. Multiply the reciprocal with the initial number (see above for multiplication process). Simplify. Evaluate means to solve. You can solve fraction problems using the above processes. You can only simplify if both the numerator and denominator are divisible by the same number. If the denominator is odd, you can only simplify it if the numerator also is divisible by a same number. Ex. 88/33. Although the denominator is odd, both the numerator and denominator are divisible by 11 resulting in 8/3 as the simplified answer. To pace yourself during a test do the following. Find out how long you have for the test. Divide this by the total number of problems on the test. Example. 1 hour for 20 problems on your test. This means you have 3 minutes per problem. If you spend more than 3 minutes on a problem, skip it. Continue until you attempt all the problems. Go back with the remainder of the time to retry these problems you skipped. Most likely they are the most difficult, hence why you spent alot of time on them. This method of pacing allows you to skip the hard problems at first, attempt all problems, and finish the easier problems for sure.

### hpw do you estimate an answer to a problem with a remainder?

if 4 is multiplied times the sum of a number and 6, the result is 28 less the number. what is the number?   As an equation i think this would be: 4(x + 6) = x - 28 4x + 24 = x - 28   Now you can subtract 24 frm both sides of the equation: 4x + 24 - 24 = x - 28 - 24 4x = x - 52   Now you can subtract x from both sides of the equation: 4x - x = x - 52 - x 3x = - 52   Now you can divide both sides of the equation by 3 to find the value of x on it's own: 3(x)/3 = - 52/3 x = - 52/3   So the number you wanted to find is -52/3

### Solve {3x-2y+2z=30, -x+3y-4z=-33, 2x-4y+3z=42}

Solve {3x-2y+2z=30, -x+3y-4z=-33, 2x-4y+3z=42} Please just solve the set provided above!!!! This will be a bit more involved than the systems with two unknowns, but the process is the same. The plan of attack is to use equations one and two to eliminate z. That will leave an equation with x and y. Then, use equations one and three to eliminate z again, leaving another equation with x and y. Those two equations will be used to eliminate x, leaving us with the value of y. I'll number equations I intend to use later so you can refer back to them. That's enough discussion for now. 1)  3x-2y+2z=30 2)  -x+3y-4z=-33 3)  2x-4y+3z=42 Equation one; multiply by 2 so the z term has 4 as the coefficient. 3x - 2y + 2z = 30 2 * (3x - 2y + 2z) = 30 * 2 4)  6x - 4y + 4z = 60 Add equation two to equation four:   6x - 4y + 4z =  60 +(-x + 3y - 4z = -33) ----------------------   5x - y       = 27 5)  5x - y = 27 Multiply equation one by 3. Watch the coefficient of z. 3 * (3x - 2y + 2z) = 30 * 3 6)  9x - 6y + 6z = 90 Multiply equation three by 2. Again, watch the coefficient of z. 2 * (2x - 4y + 3z) = 42 * 2 7)  4x - 8y + 6z = 84 Subtract equation seven from equation six.   9x - 6y + 6z = 90 -(4x - 8y + 6z = 84) ----------------------   5x + 2y      =  6 8)  5x + 2y = 6 Subtract equation eight from equation five. Both equations have 5 as the coefficient of x. We eliminate x this way.   5x -  y = 27 -(5x + 2y = 6) ---------------       -3y = 21 -3y = 21 y = -7  <<<<<<<<<<<<<<<<<<< At this point, I am confident that I followed the correct procedures to arrive at the value for y. Use that value to determine the value of x. ~~~~~~~~~~~~~~~ Plug y into equation five to find x. 5x - y = 27 5x - (-7) = 27 5x + 7 = 27 5x = 27 - 7 5x = 20 x = 4  <<<<<<<<<<<<<<<<<<< Plug y into equation eight, too. 5x + 2y = 6 5x + 2(-7) = 6 5x - 14 = 6 5x = 6 + 14 5x = 20 x = 4    same value for x, confidence high Proceed, solving for the value of z. ~~~~~~~~~~~~~~~ Plug both x and y into equation one. We will solve for z. Equation one: 3x - 2y + 2z = 30 3(4) - 2(-7) + 2z = 30 12 + 14 + 2z = 30 26 + 2z = 30 2z = 30 - 26 2x = 4 z = 2  <<<<<<<<<<<<<<<<<<< Continue using the original equations to check the values. Equation two: -x + 3y - 4z = -33 -(4) + 3(-7) - 4z = -33 -4 - 21 - 4z = -33 -25 - 4z = -33 -4z = -33 + 25 -4z = -8 z = 2   same value for z, looking good Equation three: 2x - 4y + 3z = 42 2(4) - 4(-7) + 3z = 42 8 + 28 + 3z = 42 36 + 3z = 42 3z = 42 - 36 3z = 6 z = 2  satisfied with the results We have performed several checks along the way, thus proving all three of the values. x = 4, y = -7 and z = 2

### Five times the difference of twice a number and eight is negative ten. Find the number.

call the number you are looking for x times=multiply difference=subtract twice a number=times 2 is=Equals   5(2x-8)=-10   Solve this for x to get your answer 10x-40=-10 10x=30 x=3

### what is 5 1/8-3 2/3

5 1/8-3 2/3  You first need to find the L.C.D. (Lowest Common Denominator), since you can't subtract with different denominators. The easiest way to do this is to multiply the denominators. 8 X 3 = 24 Let's start with 1/8. The denominator - 8 goes into 24 THREE times. 3 times the numberator - 1 equals 3. So, the first number becomes 5 3/24. Now, let's work with 2/3. 3 goes into 24 EIGHT times. 8 times 2 equals 16. So the second number becomes 3 16/24. Now the problem is 5 3/24 - 3 16/24. Normally, you just subtract the numerators, & solve the problem. BUT you can't subtract 16 from 3 in te numerators, so you need to add to 3/24. You take 1 from 5, which makes it 4. Then you change the 1 to the equivalent we can work with here, which is 24/24. Now we add 24/24 to 3/24 to get 27/24. Now the problem becomes: 4 27/24 - 3 16/24 NOW we can subtract the numerators: 27 - 16 = 11. then we subtract the whole numbers: 4 - 3 = 1 This gives us the answer of: 1 11/24