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in the number 463,211,889, which digit has the greatest value? explain.

What number wil be the greastest value

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Which digit in 456,802 has the greatest value?

Which digit in 456,802 has the greatest value? ... MK in the value ... has been the winner of quite a ... What Whole number less than 15 and divisible by 3?

Digit Values - Super Teacher Worksheets

Digit Values What is the value of the underlined digit? ... which digit has the greatest value ... In the number above, which digit has the greatest value? 4 j.

Digit Values - Super Teacher

In the number 21,354, which digit has the greatest value? _____ j. In the ... has the greatest value? 2 j. In the number 76,129, which digit

Place Value of a Number - WebMath

Place Value of a Number ... This selection will help you to find what the place value is of a particular digit in a number. Type your number here, ...

9 - Wikipedia

Nine is the highest one digit number . Alphabets and codes. In the NATO ... In addition, the word Bahá' in the Abjad notation has a value of 9, ...

Comparing Numbers: Greater Than and Less Than

Home > By Subject > Place Value > Comparing Numbers Numbers are used ... Explain that the smallest that a number with 3 tens could ... If one number has more ...

arrange fraction from least to greatest 6/7 7/8 4/5 9/12

... 0.89(repeating 89), 0.889( repeating ... to least . both times the same number was third in order . explain how ... has the greatest value and how ...

How do I find thr greatest place value in a number for a fourth graders math assignment?

The greatest place value in a number is the place value of the digit on the far left. Example: 123.456 The digit on the far left is 1. The 1 is in the hundreds place. The greatest place value in 123.456 is the hundreds place. . Note:  Special Condition:  The greatest place value in a number is the place value of the non-zero digit on the far left. We don't usually write things with 0's on the left (00037 vs. 37), but if we do, the greatest place value in a number is the place value of the digit on the far left, ignoring any 0's to the left of the leftmost non-0 digit. Example: 0007.89 Ignore the 0's on the left 7.89 7 is on the far left 7 is in the ones place The ones place is the greatest place value in 0007.89 . Example: 00012300.456 We only remove the 0's on the far left 12300.456 The far left digit is 1 The 1 is in the ten thousands place The ten thousands place is the greatest place value in 00012300.456

What is the greatest place value in a number, how do you find it?

The greatest place value in a number is the place value of the digit on the far left. Example: 123.456 The digit on the far left is 1. The 1 is in the hundreds place. The greatest place value in 123.456 is the hundreds place. . Note:  Special Condition:  The greatest place value in a number is the place value of the non-zero digit on the far left. We don't usually write things with 0's on the left (00037 vs. 37), but if we do, the greatest place value in a number is the place value of the digit on the far left, ignoring any 0's to the left of the leftmost non-0 digit. Example: 0007.89 Ignore the 0's on the left 7.89 7 is on the far left 7 is in the ones place The ones place is the greatest place value in 0007.89 . Example: 00012300.456 We only remove the 0's on the far left 12300.456 The far left digit is 1 The 1 is in the ten thousands place The ten thousands place is the greatest place value in 00012300.456

seven times a two digit number

Short answer:  The two digit number is 36. Long answer: 7 * x1x2 = 4 * x2x1 "If the difference between the number is 3. . ." Last digits: x2: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 7*x2:  0, 7, 4, 1, 8, 5, 2, 9, 6, 1 x1:  0, 1, 2, 3, 4, 5, 6, 7, 8, 9 4*x1:  0, 4, 8, 2, 6, 0, 4, 8, 2, 6 The only way this works is when these last digits for 7*x2 and 4*x1 are the same.  That means the 7*x2 line can only be: 7*x2:  0, 4, 8, 2, 6 Which means the possible values for x2 are: x2:  0, 2, 4, 6, 8 Now let's look at x1.  Right now the possible values for x1 are: x1:  0, 1, 2, 3, 4, 5, 6, 7, 8, 9 But we have to end up with a choice from x1 and x2 having a difference of 3 (odd number).  There is no way to get an odd number by subtracting an even number from an even number.  That means x1 has to be odd.  Our possible values for x1 are now: x1:  1, 3, 5, 7, 9 And our possible values for x2 are: x2:  0, 2, 4, 6, 8 The possible combinations for x1x2 and x2x1 are: 10, 01 12, 21 14, 41 16, 61 18, 81 30, 03 32, 23 34, 43 36, 63 38, 83 50, 05 52, 25 54, 45 56, 65 58, 85 70, 07 72, 27 74, 47 76, 67 78, 87 90, 09 92, 29 94, 49 96, 69 98, 89 We want 7*x1x2 = 4*x2x1, so we can do 7 * the first column and 4 * the second column: 70, 4 84, 84 98, 164 112, 244 126, 324 210, 12 224, 92 238, 172 252, 252 266, 332 350, 20 364, 100 378, 180 392, 260 406, 340 490, 28 504, 108 518, 188 532, 268 546, 348 630, 36 644, 116 658, 196 672, 276 686, 356 But since we want 7*x1x2 to equal 4*x2x1, that list reduces to: 84, 84 252, 252 The corresponding x1 and x2 values are: 12, 21 36, 63 But the difference between x1 and x2 is 3, so we can't use x1 = 1, x2=2.  We have to use x1 = 3, x2 = 6. Answer:  The two digit number is 36. Check:  7 * 36 = 4 * 63 252 = 252 good. 6 - 3 = 3 good.

in the number 802, which digit has the least value?

In the number 802, which digit has the least value? All digits are single numbers. There are 10 digits, from 0 to 9, inclusive The number 802 has 3 digits in it, 8, 0, and 2. The smallest of these digits is 0

Genet multiplied a 3-digit number by 1002 and got AB007C, where A, B, and C stand for digits. What was Genet's original 3-digit number?

Write the three digit number as 100a+10b+c, where a, b and c are the digits. Write 1002 as 1000+2, now expand (100a+10b+c)(1000+2)= 100000a+10000b+1000c+200a+20b+2c=100000A+10000B+70+C. I found it easier to equate digits by comparison by arranging this sum as a layout in long multiplication: ............................................1 0 0 2 ...............................................a b c ...........................................c 0 0 2c ........................................b 0 0 2b 0 .....................................a 0 0 2a 0 0 .....................................A B 0 0 7 C We should be able to equate the digits by position by comparisons. C must be an even number 0, 2, 4, 6 or 8. But in the tens we have 7, so c is 5, 6, 7, 8 or 9, to produce a carryover converting 6 to 7 in the tens. That tells us that b must be 3 or 8 because 2*3+1=7 or 2*8+1=17. But in the hundreds we have 0, so b can't be 8 because there would be a carryover, so b=3. And we can see that 2a must be a number ending in zero, so a=0 or 5. But a can't be zero because we would have a 3-digit number starting with zero making it a 2-digit number so a=5, and 2a=10, which is a carryover to the thousands where c is. But the thousands digit is zero, so c=9. We have all the digits: a=5, b=3 and c=9 making the number 539. 539*1002=540078.

find all reconstuctions of the sum: ABC+DEF+GHI=2014 if all letters are single digits

There is no solution if A to I each uniquely represent a digit 1 to 9, because the 9's remainder of ABC+DEF+GHI (0) cannot equal the 9's remainder of 2014 (=7). Let me explain. The 9's remainder, or digital root (DR), is obtained by adding the digits of a number, adding the digits of the result, and so on till a single digit results. If the result is 9, the DR is zero and it's the result of dividing the number by 9 and noting the remainder only. E.g., 2014 has a DR of 7. When an arithmetic operation is performed, the DR is preserved in the result. So the DRs of individual numbers in a sum give a result whose DR matches. If we add the numbers 1 to 9 we get 45 with a DR of zero, but 2014 has a DR of 7, so no arrangement can add up to 2014. If 2 is replaced by 0 in the set of available digits, the DR becomes 7 (sum of digits drops to 43, which has a DR of 7). 410+735+869=2014 is just one of many results of applying the following method. Look at the number 2014 and consider its construction. The last digit is the result of adding C, F and I. The result of addition can produce 4, 14 or 24, so a carryover may apply when we add the digits in the tens column, B, E and H. When these are added together, we may have a carryover into the hundreds of 0, 1 or 2. These alternative outcomes can be shown as a tree. The tree: 04 >> 11, >> 19: ............21 >> 18; 14 >> 10, >> 19: ............20 >> 18; 24 >> 09, >> 19: ............19 >> 18. The chevrons separate the units (left), tens (middle) and hundreds (right). The carryover digit is the first digit of a pair. For example, 20 means that 2 is the carryover to the next column. Each pair of digits in the units column is C+F+I; B+E+H in the tens; A+D+G in the hundreds. Accompanying the tree is a table of possible digit summations appearing in the tree. Here's the table: {04 (CFI): 013} {09 (BEH): 018 036 045 135} {10 (BEH): 019 037 046 136 145} {11 (BEH): 038 047 137 056 146} {14 (CFI): 059 149 068 158 167 347 086 176 356} {18 (ADG): 189 369 459 378 468 567} {19 (BEH/ADG): 379 469 478 568} {20 (BEH): 389 479 569 578} {21 (BEH): 489 579 678} {24 (CFI): 789} METHOD: We use trial and error to find suitable digits. Start with units and sum of C, F and I, which can add up to 4, 14 or 24. The table says we can only use 0, 1 and 3 to make 4 with no carryover. The tree says if we go for 04, we must follow with a sum of 11 or 21 in the tens. The table gives all the combinations of digits that sum to 11 or 21. If we go for 11 the tree says we need 19 next so that we get 20 with the carryover to give us the first two digits of 2014. See how it works? Now the fun bit. After picking 013 to start, scan 11 in the table for a trio that doesn't contain 0, 1 or 3. There isn't one, so try 21. We can pick any, because they're all suitable, so try 489. The tree says go for 18 next. Bingo! 567 is there and so we have all the digits: 013489576. We have a result for CFIBEHADG=013489576, so ABCDEFGHI=540781693. There are 27 arrangements of these because we can rotate the units, tens and hundreds independently like the wheels of an arcade jackpot machine. For example: 541+783+690=2014. Every solution leads to 27 arrangements. See how many you can find using the tree and table!

in the number 463,211,889, which digit has the greatest value? explain.

Left-most digit, assuming yu did NOT put "0" at the left end

Tamar is thinking of a number in the hundredths. Her number is greater than 0.8 but less than 0.9. The greatest digit in the number is in the hundredths place. What number is Tamar thinking of?

Tamar is thinking of a number in the hundredths. Her number is greater than 0.8 but less than 0.9. The greatest digit in the number is in the hundredths place. What number is Tamar thinking of? Please explain how you got the answer. Because the larger digit is in the hundredths place, and there is an 8 in the tenths place, the only digit that can be in the hundredths place is a 9. Therefore, Tamar is thinking of 0.89

what fraction of the integers between 0 and 1000 include exactly two 6s

We are looking for 3-digit numbers with 2 of the digits equal to 6. These numbers will be of the form, x66 6x6 66x where, in each case, x is a digit with a value of 0 to 5 and 7 to 9, a total of 9 different values There will be 9 different values for x in each of the three cases, i.e. 27  in total. There are 1001 different integers between 0 and 1000. So the fraction of them that contain exactly 2 sixes is: 2.7%

Write the number as a sum: 100a+10b+c, where a is the digit in the 100s, b the digit in the 10s and c the units. If a=10b, then, unless a and b are both zero, there are four digits in the number. But it says that b is greater than 8, so a must be greater than 80. Also, b must be 9 because they are no more digits greater than 8. The number must end 0, 2, 4, 6 or 8 to be even. The possibilities are 9090, 9092, 9094, 9096 and 9098. If 0 is not a digit but a placeholder, then the number has three digits and 9090 is not a possibility leaving us with the last four numbers.