Guide :

# Find the slope between the following points.  (1, -1) and (-1, 1)

Find the slope between the following points.  (1, -1) and (-1, 1)

## Research, Knowledge and Information :

### How use the slope formula and find the slope of a line ...

The slope of a line going through the point (1,2) ... Can you catch the error in the following problem Jennifer was trying to find the slope that goes through the ...

### Find the slope between the following points 4 -1 and -1 4

Find the slope between the following points 4 -1 and -1 4? ... Points: (2, 1) and (-4, -5) Slope: (1--5)/(2--4) = 1 Edit. Share to: Liam Frayne. 27,068 Contributions.

### Find the slope between the following points: (-6,0) and (1 ...

Find the slope between the following points: (-6,0) and (1,-14) - 3298477. 1. Log in ... Write the slope-intercept form of the line that has a slope of 2 and ...

### What is the slope between the following points: (8, –1) and ...

What is the slope between the following points: (8, –1) and (–7, 4)?. . . A.1/3. B. 3. C. -1/3. D. -3 - 1527998. 1. ... where m is the slope, ...

### Find the slope between the following points: (-1 , 2) and (3 ...

Find the slope between the following points: ... Find the slope between the following points: (-1 , 2 ... find a. the distance between the points b. the slope of the ...

### Finding the Slope of a Line from Two Points 1 | Coolmath.com

Finding the Slope of a Line from Two Points. ... Finding the Equation of a Line Given a Point and a Slope. Finding the Equation of a Line Given Two Points. Parallel ...

### Write the equation from points (3,1) & (4,2) in slope ...

Write the equation from points (3,1) & ... we can find the slope (m) of the line using the following ... the difference between "Slope Intercept Form" and "Point ...

## Suggested Questions And Answer :

### find the slope of the following line. 5y=x+5 the slope is...

find the slope of the following line. 5y=x+5 the slope is... 5y = x + 5 Divide by 5. y = 1/5 x + 1 The slope is 1/5

### how to find slope and y-intercept of y=3x-5

Any line equation which is in the form y=m*x + b is called slope-intercept form. What that gives you is the slope is the number which is multiplied by X (called the coefficient) while the slope intercept is the Y value when X=0. So if we take your first equation: y = 3x - 5 The slope (or m) = 3 The Y intercept = -5 Slope is defined as either "the change in y divided by the change in x" or "rise over run", so that 3, really can be considered as 3/1. Each change in X of 1 will change Y by 3. So slope = 3/1. Graphing any line can come from 2 methods. 1) create a table of values or 2) calculate a single point (x,y) and then apply the slope to find a second coordinate pair (x,y). For the equation y=3x - 5: y = 3x - 5 x y 0 -5 1 -2 Replacing the values for X into the original equation, will come out to the values for Y. So when X=0, y = 3*0 - 5, or simply -5.  When X = 1, Y = 3*1 -5 or simply -2. With these two coordinate pairs of points, you can plot a dot on your graph at each (0,-5) and (1, -2) then draw a straight line which goes through each point and continues straight in each direction, probably ending each end of this line with an arrow to show it continues. I do not have a way to include a picture here of a graph. The second way to graph a line is as follows. You need a starting point that will be on the line. Given the form of y=mx + b, you have a simple point which can be used at the y-intercept. The point is always in the form of (0, b), so in this case it is (0,-5). From that first point, you will apply your slope. The slope is 3 (or technically 3/1 which is a big help). From the initial point (0,-5) you will go UP 3 and RIGHT 1 and that will be the next point that is easy to find. Connect those two points and continue the line in each direction and that will be a graph of your line. Anytime your slope is positive, you will use it by going UP the top number (numerator of the slope) and going RIGHT the bottom number (denominator of the slope). But if your slope is negative (like your second problem is) you will use it by going DOWN the numerator and then RIGHT the denominator. The equation is y= -2/3x + 4 ( / = divided). I need to state the slope and y-intercept. I will not walk through the details on the second equation, but you should have enough information to get the answer from the above example.

### how do you find the equation of a line given a point and what it is perpendicular too?

how do you find the equation of a line given a point and what it is perpendicular too? i have a point and an equation in slope intercept form and i have to find the equation thats perpendicular to the eqution given . How do i do that? The equation of a line that is perpendicular to the given line has a slope that is the negative inverse of the given slope. E.G., if the given equation were y = 1/2 x + 7, the new equation would be y = -2x + b, understanding that b is the y-intercept of the new equation. Now, take the x and y values of the point you have been given and plug them into the new equation to find the value of b. If the point were (7, -10), you would have -10 = -2(7) + b. Solve that and you would find that b = 4. So, in this case, the equation would be y = -2x + 4. Follow the same steps, using the values from your equation and point. You will end up with the correct equation for your problem.

### (-4,-2) (0,0) and (2,7) (k,5) what is k

(-4,-2) (0,0) and (2,7) (k,5) what is k i have to find the value of k, so that the two lines will be parallel. The first observation to make is that parallel lines have the same slope. We can determine the slope of the first line and use that to find the unknown x value for the second line. Let's give identities to the points so we can refer to them by name. P1 is (x1, y1)   (-4,-2) P2 is (x2, y2)   (0, 0) P3 is (x3, y3)   (2, 7) P4 is (x4, y4)   (k, 5) The x and y designations are so you can follow along with the general equation to calculate the slope, m. 1) m = (y2 - y1) / (x2 - y2) 2) m = (0 - (-2)) / (0 - (-4)) 3) m = (0 + 2) / (0 + 4) 4) m = 2 / 4 = 1/2 Now that we know the slope of the two lines, we can use the second set of points to find the value of k. 5) m = (y4 - y3) / (x4 - x3)   Of couse, x4 is k. 6) m = (5 - 7) / (k - 2) We know that m is 1/2, so we will now substitute that into the equation. 1/2 = (5 - 7) / (k - 2) 1/2 = -2 / (k - 2) We multiply both sides by (k - 2) 1/2 * (k - 2) = (-2 / (k - 2)) * (k - 2) 1/2 * (k - 2) = -2 Multiply both sides by 2 1/2 * (k - 2) * 2 = -2 * 2 (k - 2) = -4 Add 2 to both sides (k - 2) + 2 = -4 + 2 k = -2 Substitute that value into equation 6, for the slope. m = (5 - 7) / (k - 2) m = (5 - 7) / (-2 - 2) m = -2 / -4 m = 1/2 When k is -2, the second line segment has the same slope as the first line segment, therefore, the two lines are parallel.

### Find the slope between the following points.  (1, -1) and (-1, 1)

strate line tween 2 points: (-1,1) & (1,-1) deltax=2, deltay=-2 slope=deltay/deltax=-2/2=-1....-45 degree

### show the equation of the line meeting. put the equation in standard form. Containing A(1, 3) and B(0, 2)

Equation of the line in standard form with points A(1, 3) and B(0, 2). Standard form is the following y = mx + b; m is the slope of the line and b is the y offset ------------- Step 1: Determine the slope of the line at points: A(1, 3) and B(0, 2) The formula to find the slope of a line is the following m = (y1-y2)/(x1-x2) where m is the slope from points A(x1,y1) and B(x2,y2) A(1, 3) and B(0, 2) y = mx + b m = (3 - 2)/(1-0) = (3-2)/(1) =(1)/(1) m = 1; The standard equation is as follows now: y = mx + b; m = 1 y = x + b ------------- Step 2: Determine the value of b from the points A(1, 3) or B(0, 2) y = x + b; B(0,2); x = 0 and y = 2 y = x + b 2 = (0) + b 2 = b Thus; y = x + b; y = x + 2 ------------- Step 3: Validate that y = x + 2 is valid by using point A(1,3) and B(0,2) y = x + 2; A(1,3) x=1 and y = 3 y = x + 2 -> 3 = 1 + 2 = 3 True for A(1,3) B(0,2) x=0 and y=2 y = x + 2 -> 2 = 0 + 2 True for B(0,2) --------------- Our Line in Standard Form is y = x + 2

### find the solpe intercept

The line x - 4y = 7 has slope. . . x - 4y = 7 -4y = -x + 7 y = (1/4)x - 7 slope = 1/4 . Perpendicular lines have slopes that are flipped as fractions (1/4 becomes 4/1) and as +- signs (4/1 becomes -4/1). Our new slope is -4/1 or just -4. . So our goal is to find the slope intercept form of the line passing through (3,4) with slope -4. Point-slope form: y - y1 = m(x - x1) y - 4 = -4(x - 3) y - 4 = -4x + 12 y = -4x + 16

### Find the slope - intercept equation of the line with the following properties:

x=konst=vertikal line... vertikal line thru (-7, sumthun) is x=-7

### find the quadratic spline S(x) that interpolates the following data (0,0),(1,3),(2,3)

Question: find the quadratic spline S(x) that interpolates the following data (0,0),(1,3),(2,3) The data points are: (0,0),(1,3),(2,3) The quadrtic spline is: S(x) = |a1x^2 + b1x + c1, 0 ≤ x ≤ 1            |a2x^2 + b2x + c2, 1 ≤ x ≤ 2 We have 6 unknowns, so we need 6 equations. Set up the eqns 1st apline:  a1(0)^2 + b1(0) + c1 = 0                    a1(1)^2 + b1(1) + c1 = 3 2nd spline: a2(1)^2 + b2(1) + c2 = 3                   a2(2)^2 + b2(2) + c2 = 3 Common slope (derivative) at (1,3)                   2a1(1) + b1 = 2a2(1) + b2 The 3nth eqn                  Let a1 = 0 Our system of linear equns then is,         c1 = 0 b1 + c1 = 3   -> b1 = 3 a2 + b2 + c2 = 3 4a2 + 2b2 + c2 = 3 The last two eqns, along with the common slope eqn give us, a2 = -3, b2 = 9, c2 = -3 The 6 unknowns are: a1 = 0, b1 = 3, c1 = 0, a2 = -3, b2 = 9, c2 = -3 Giving the quadratic spline as: S(x) = |3x                   , 0 ≤ x ≤ 1            |-3x^2 + 9x - 3 , 1 ≤ x ≤ 2

### solve [(2\3(x+h)-4)-(2/3x-4)]/h Find the derivative of f'(x) where x=2, and g(x)=2/3x-4

g(x) = 2 / (3x - 4) g'(x) = lim(h->0) [[g(x + h) - g(x)] / h] = lim(h->0) [[(2 / (3(x + h) - 4)) - (2 / (3x - 4))] / h] = lim(h->0) [[2(3x - 4) - 2(3(x + h) - 4)] / [h(3x - 4)(3(x + h) - 4]] = lim(h->0) [6x - 8 - 6x - 6h + 8] / [h(3x - 4)(3(x + h) - 4)] = lim(h->0) [-6h] / [h(3x - 4)(3(x + h) - 4)] = lim(h->0) -6 / [(3x - 4)(3(x + h) - 4)] = -6 / [(3x - 4)(3x - 4)] = -6 / (3x - 4)^2 Thus, slope at x = 2 will be = g'(2) = -6 / (3(2) - 4)^2 = -6 / (6 - 4)^2 = -6 / 2^2 = -6 / 4 = -3/2 Also, when x = 2, we will have: y = g(2) = 2 / (3(2) - 4) = 2 / 2 = 1 Using the slope formula, we have: (y - 1) / (x - 2) = -3/2 (y - 1) = (-3/2)(x - 2) y - 1 = (-3/2)x + 3 y = (-3/2)x + 4, which is the equation of the tangent line.

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