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What is 20.889934 rounded to three decimal places

I just need to know what 29.889934 is rounded to three decimal places

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Rounding Numbers | Purplemath


Rounding Numbers. General Sig-Digs More ... I count off three decimal places, ... Otherwise, it looks like you rounded to one decimal place, or to the tenths place, ...
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Rounding decimal numbers - MathWizz.com


Example 1: Round 0.1284 to 2 decimal places. Solution: The 3rd decimal number, 8, is bigger than 4, so we add 1 to the 2nd decimal number 2, and ...
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How to Round Numbers to Three Decimal Places | Sciencing


How to Round Numbers to Three Decimal Places By Kristy Wedel; Updated April 24, 2017 . Decimal places have names associated with their positions.
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Rounding Numbers - Math is Fun - Maths Resources


Rounding Numbers What is "Rounding" ? ... To round to "so many decimal places" count that many digits from the decimal point: 1.2735 rounded to 3 decimal places is 1.274.
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How To Round Any Number Off To 3 Decimal Places ... - YouTube


Jun 25, 2014 · In this video you will learn how to round any number off to 3 decimal places. To do this put a line in after the third number from the decimal point ...

How to round off a decimal. How to express the quotient as a ...


Learn how to round off a decimal. ... To round off to three decimal digits, then, ... "8 goes into 20 two (2) times (16) ...
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Rounding Numbers - Calculator Soup


Online calculator for rounding numbers. How to round numbers and decimals. ... Rounding calculator to round numbers up or down to any decimal place.
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Round a number to the decimal places I want - Office Support


Round a number to the decimal places you want by using formatting and how to use the ROUND function ... if you want to round 3.2 up to zero decimal places ...
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Suggested Questions And Answer :


solve the equation 3 log(base 2)(x-1)+log(base 2)4=5

The equation is equivalent to log (base 2 ) (X-1)^3 (4) = 5 , therefore , log(base 2)[X^3-3X^2+3X-1](4) = 5 , so , 2^5 = 4X^3-12X^2+12X-4 , we simplify a little bit more , then 32 = 4(X^3 - 3X^2 + 3X - 1) , then : 8 = X^3 - 3X^2 + 3X - 1 , putting the whole thing in standard form yuo get X^3 - 3X^2 + 3X - 9 = 0 , which you factorize in this way : X^2(X-3) 3(X-3) = 0 , (X-3)(X^2 +3) =0 , implying that X = 3 , X = 3^(1/2) i and X = -3^ (1/2)i three roots because is a third degree equation . Because we were asked to express the irrational answer rounded up to the third place , then we add : 3^(1/2) i = 1.732 i and its pair ( every irrational root comes in pairs ) would be -1.732 i
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solve -x-3y+4z=3, 5x-8y+5z=27,5x-2y+6z=1 with matrix

-x -3y +4z = 3 5x -8y +5z = 27 5x -2y +6z = 1 0 is neither + nor -, but I used +0 below to make the matrix line up better. The solution below looks a bit messy because fractions and exact numbers are being used.  If you use decimals the matrix will look prettier and won't have as many big numbers, but the answer will be slightly off due to rounding errors. matrix -1   -3   +4   |   +3 +5   -8   +5   |   +27 +5   -2   +6   |   +1 on the third row, subtract out the 2nd row -1   -3   +4   |   +3 +5   -8   +5   |   +27 +0   +6   +1   |   -26 multiply the top row by 5 -5   -15   +20   |   +15 +5   -8   +5   |   +27 +0   +6   +1   |   -26 in the top row, add the bottom row +0   -23   +25   |   +42 +5   -8   +5   |   +27 +0   +6   +1   |   -26 multiply the bottom row by -25 +0   -23   +25   |   +42 +5   -8   +5   |   +27 +0   -150   -25   |   +650 in the bottom row, add the top row +0   -23   +25   |   +42 +5   -8   +5   |   +27 +0   -127   +0   |   +692 multiply the top row by -127 +0   +2921   -3175   |   -5334 +5   -8   +5   |   +27 +0   -127   +0   |   +692 multiply the bottom row by 23 +0   +2921   -3175   |   -5334 +5   -8   +5   |   +27 +0   -2921   +0   |   +15916 add the bottom row to the top row +0   +0   -3175   |   +10582 +5   -8   +5   |   +27 +0   -2921   +0   |   +15916 multiply the middle row by -2921 +0   +0   -3175   |   +10582 -14605   +23368   -14605   |   -78867 +0   -2921   +0   |   +15916 multiply the bottom row by 8 +0   +0   -3175   |   +10582 -14605   +23368   -14605   |   -78867 +0   -23368   +0   |   +127328 add the bottom row to the middle row +0   +0   -3175   |   +10582 -14605   +0   -14605   |   +48461 +0   -23368   +0   |   +127328 multiply the top equation by -14605 +0   +0   +46370875   |   -154550110 -14605   +0   -14605   |   +48461 +0   -23368   +0   |   +127328 multiply the middle equation by 3175 +0   +0   +46370875   |   -154550110 +46370875   +0   +46370875   |   +153863675 +0   -23368   +0   |   +127328 add the top equation to the middle equation +0   +0   +46370875   |   -154550110 +46370875   +0   +0   |   -686435 +0   -23368   +0   |   +127328 divide the top equation by 46370875 +0   +0   +1   |   -154550110/46370875 +46370875   +0   +0   |   -686435 +0   -23368   +0   |   +127328 divide the middle equation by 46370875 +0   +0   +1   |   -154550110/46370875 +1   +0   +0   |   -686435/46370875 +0   -23368   +0   |   +127328 divide the bottom equation by -23368 +0   +0   +1   |   -154550110/46370875 +1   +0   +0   |   -686435/46370875 +0   +1   +0   |   -127328/23368 put the middle equation on top and the top equation on bottom +1   +0   +0   |   -686435/46370875 +0   +1   +0   |   -127328/23368 +0   +0   +1   |   -154550110/46370875 that's an answer, but the fractions on the right can be reduced. factor a 5 out from the top and bottom equations and a 4 out from the middle equation +1   +0   +0   |   -137287/9274175 +0   +1   +0   |   -15916/2921 +0   +0   +1   |   -30910022/9274175 factor a 23 out of all three equations +1   +0   +0   |   -5969/403225 +0   +1   +0   |   -692/127 +0   +0   +1   |   -1343914/403225 factor a 127 out of the top and bottom equations +1   +0   +0   |   -47/3175 +0   +1   +0   |   -692/127 +0   +0   +1   |   -10582/3175 Answer:  x = -47/3175, y = -692/127, z = -10582/3175 or, in decimal rounded to 4 places after the decimal Answer:  x = -0.0418, y = -5.4488, z = -3.3329
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10 vedic maths rules for class IX

2 instead of 5: 34/5 can be calculated by multiplying 34 by 2 instead of dividing by 5. 34*2=68. We just move the decimal point one place to the left: 34/5=6.8. 124/5=24.8 because 124*2=248. Move the decimal point: 248 becomes 24.8. 34*5 is the same as 34/2=17 but we add a zero to make 17 into 170. 73*5 is the same as 73/2=36.5 then move the decimal point one place to the right (or add zero): 36.5 becomes 365=73*5. So we only need to know how to multiply and divide by 2 to divide and multiply by 5. We just move the decimal point. Divisibility by 9 or remainder after dividing by 9. All multiples of 9 contain digits which added together give 9. As we add the digits together, each time the result goes over 9 we add the digits of the result together and use that result and continue in this way up to the last digit. Is 12345 divisible by 9? Add the digits together 1+2+3=6. When we add 4 we get 10, so we add 1 and zero=1 then we add 5 to get 6. The number is not exactly divisible by 9, but the remainder is 6. We can also ignore any 9's in the number. Now try 67959. We can ignore the two 9's. 6+7=13, and 1+3=4; 4+5=9, so 67959 is divisible by 9. Multiplying by 11. Example: 132435*11. We write down the first and last digits 1 ... 5. Now we add the digits in pairs from the left a digit step at a time. So 1+3=4; 3+2=5: 2+4=6; 4+3=7; 3+5=8. Write these new digits between 1 and 5 and we get 1456785=132435*11. But we had no carryovers here. Now try 864753*11. Write down the first and last digits: 8 ... 3. 8+6=14, so we cross out the 8 and replace it with 8+1=9, giving us 94 ... 3. Next pair: 6+4=10. Again we go over 10 so we cross out 4 and make it 5. Now we have 950 ... 3. 4+7=11, so we have 9511 ... 3. 7+5=12, giving us 95122 ... 3; 5+3=8, giving us the final result 9512283.  Divisibility by 11. We add alternate digits and then we add the digits we missed. Subtract one sum from the other and if the result is zero the original number was divisible by 11. Example: 1456785. 1 5 7 5 make up one set of alternate digits and the other set is 4 6 8. 1+5+7=13. We drop the ten and keep 3 in mind to add to 5 to give us 8. Now 4 6 8: 4+6=10, drop the ten and add 0 to 8 to give us 8 (or ignore the zero). 8-8=0 so 11 divides into 1456785. Now 9512283: set 1 is 9 1 2 3 and set 2 is 5 2 8; 9+1=0 (when we drop the ten); 2+3=5; set 1 result is 5; 5+2+8=5 after dropping the ten, and 5-5=0 so 9512283 is divisible by 11. Nines remainder for checking arithmetic. We can check the result of addition, subtraction, multiplication and (carefully) division. Using Method 2 above we can reduce operands to a single digit. Take the following piece of arithmetic: 17*56-19*45+27*84. We'll assume we have carried out this sum and arrived at an answer 2365. We reduce each number to a single digit using Method 2: 8*2-1*9+9*3. 9's have no effect so we can replace 9's by 0's: 8*2 is all that remains. 8*2=16 and 1+6=7. This tells us that the result must reduce to 7 when we apply Method 2: 2+3+6=11; 1+1=2 and 2+5=7. So, although we can't be sure we have the right answer we certainly don't have the wrong answer because we arrived at the number 7 for the operands and the result. For division we simply use the fact that a/b=c+r where c is the quotient and r is the remainder. We can write this as a=b*c+r and then apply Method 2, as long as we have an actual remainder and not a decimal or fraction. Divisibility by 3. This is similar to Method 2. We reduce a number to a single digit. If this digit is 3, 6 or 9 (in other words, divisible by 3) then the whole number is divisible by 3. Divisibility by 6. This is similar to Method 6 but we also need the last digit of the original number to be even (0, 2, 4, 6 or 8). Divisibility by 4. If 4 divides into the last two digits of a number then the whole number is divisible by 4. Using 4 or 2 times 2 instead of 25 for multiplication and division. 469/25=469*4/100=1876/100=18.76. 538*25=538*100/4=134.5*100=13450. We could also double twice: 469*2=938, 938*2=1876, then divide by 100 (shift the decimal point two places to the left). And we can divide by 2 twice: 538/2=269, 269/2=134.5 then multiply by 100 (shift the decimal point two places left or add zeroes). Divisibility by 8. If 8 divides into the last three digits of a number then the whole number is divisible by 8. Using 8 or 2 times 2 times 2 instead of 125 for multiplication and division. Similar to Method 9, using 125=1000/8. Using addition instead of subtraction. 457-178. Complement 178: 821 and add: 457+821=1278, now reduce the thousands digit by 1 and add it to the units: 278+1=279; 457-178=279. Example: 1792-897. First match the length of 897 to 1792 be prefixing a zero: 0897; complement this: 9102. 1792+9102=1894. Reduce the thousands digit by 1 and add to the result: 894+1=895. Example: 14703-2849. 2849 becomes 02849, then complements to 97150. 14703+97150=111853; reduce the ten-thousands digit by 1 and and add to the result: 11854. Squaring numbers ending in 5. Example: 75^2. Start by writing the last two digits, which are always 25. Take the 7 and multiply by 1 more than 7, which is 8, so we get 56. Place this before the 25: 5625 is the square of 75. The square of 25 is ...25, preceded by 2*3=6, so we get 625. All numbers ending in 0 or 5 are exactly divisible by 5 (see also Method 1). All numbers ending in zero are exactly divisible by 10. All numbers ending in 00, 25, 50 or 75 are divisible by 25. Divisibility by 7. Example: is 2401 divisible by 7? Starting from the left with a pair of digits we multiply the first digit by 3 and add the second to it: 24: 3*2+4=10; now we repeat the process because we have 2 digits: 3*1+0=3. We take this single digit and the one following 24, which is a zero: 3*3+0=9. When we get a single digit 7, 8 or 9 we simply subtract 7 from it: in this case we had 9 so 9-7=2 and the single digit is now 2. Finally in this example we bring in the last digit: 3*2+1=7, but 7 is reduced to 0. This tells us the remainder after dividing 2401 by 7 is zero, so 2401 is divisible by 7. Another example: 1378. 3*1+3=6; 3*6=18 before adding the next digit, 7 (we can reduce this to a single digit first): 3*1+8=3*1+1=4; now add the 7: 4+7=4+0=4;  3*4=12; 3*1+2+8=5+1=6, so 6 is the remainder after dividing 1378 by 7.  See also my solution to: http://www.mathhomeworkanswers.org/72132/addition-using-vedic-maths?show=72132#q72132
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Round off 9704.8372 to the: nearest thousand,nearest whole number , two decimal places , three significant figures

Nearest thousand is 10000, which is nearer than 9000. 9704.8372 is 704.8372 away from 9000; but only 295.1628 away from 10000. The guide is usually the digit in the hundred position: if it's 5 or more then we go up to the next thousand (9 to 10 in this case), otherwise we just take the thousand digit as it is (9 in this case). 7, the hundred digit, is bigger than 5, so we take 10 thousand. Nearest whole number is 9705, which is nearer than 9704, because the next digit 8 is bigger than 5 and the 4 in the ones position goes up to 5. 2 dec places is 9704.84, which is nearer than 9704.83. 3 sig figures is 9700. The 3 figures are 9, 7 and 0, because the zero is occupying a place separating it from the next digit 4, so it is significant. The 4 would make it 4 sig figures. The size of the number has to be preserved because, for example, 970 would not suggest the right number of thousands. Leading zeroes in whole numbers or mixed numbers are always discounted because they do not have any effect on the magnitude of the number.
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What is 20.889934 rounded to three decimal places

Third decimal place: 20.889934 Next digit over is a 9, which is greater than or equal to 5, so the 9 in the third decimal place rounds up. 20.890
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round 4.53417968617328e-05 to 4 decimal places in decimal form

4.53417968617328 * 10^-5 0.0000453417968617328 Here's the 4th decimal place:  0.0000453417968617328 The next digit over (4) is less than or equal to 5, so the 0 doesn't round up. 0.0000 or just 0 Answer:  0
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0.3867 to three decimal places

The 4th decimal place, 7, is ≥ 5, so increment the 3rd decimal place. Answer: 0.3867 = 0.387 to three decimal places
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what is 0.26. rounded three decimal places?

yu dont hav 3 desimal points, so kant round it
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Find the approximate solutions of the equation 2x^2+4x+1=0 (Round up to two decimal places)

2x^2 +4x+1=0 quadratik equashun giv roots=-0.2928932 & -1.7071068
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what is 259,345,278 rounded to the nearest ten thousandths

259,345,278 = 259,345,278.00000 I know it's all 0's after the decimal, but let's write it like this just for now:  259,345,278.abcde (that's so we can tell the difference between which 0 we're talking about) The 0 sitting on the d is in the ten thousandths place.  The next digit over is 0, which is less than 5, so the 0 in the ten thousandths place doesn't round up. Answer: 259,345,278.abcd = 259,345,278.0000 = 259,345,278 259,345,278 is already rounded to the nearest ten thousandth.
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