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can u please help me solve [3(8×4)•6÷(4-2)

Algebra 1 equation on my way to school needs help now

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Can you please help me solve each inequality and help me ...


Can you please help me solve each inequality and help me graph each solution set ... and help me graph each solution set.. can u please help me with #5,#6,#7,#8 ...
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Can someone please help me solve 3? Thank you!! (: - Brainly.com


Can someone please help me solve 3? Thank you!! (: Download png. 2. ... The 10 comes from the amount of letters and the 2 comes from the 2 As and the 3 comes from the ...
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Mathway | Math Problem Solver


Please try again. Please ... you must allow Mathway to ... Visa and MasterCard security codes are located on the back of card and are typically a separate group of 3 ...
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Please help me solve: 6(2x+4)=10x+24+2x? | Socratic


... (2x + 4) = 6 * 2x + 6 * 4 = 12x + 24 The equation now looks like this 12x + 24 = 10x + 24 + 2x Notice ... Please help me solve: 6(2x+4) ... Please explain why or ...
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Please help me solve and explain so I can actually learn ...


Please help me solve and explain so I can actually learn! Thanks!! 1) ...
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PLEASE HELP :3 Solve 2x + 5y = −13 3x − 4y = −8... - OpenStudy


PLEASE HELP :3 Solve 2x + 5y = −13 3x − 4y = −8 (4, 1) (−4, 1) (4, −1) (−4, −1) Mathematics ...
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Math Help 1) Solve the triangle. A = 46, a = 31, b = 27 a) B ...


Answer to Math Help 1) Solve the triangle. A = 46, a = 31, ... Solve the triangle. A = 54°, b = 11, c = 8 a) ... Can you please help me with my assignment. please ...
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Please help me solve 4 square root of 64x^8 y^10 Thank you?


Please help me solve 4 square root of 64x^8 y^10 Thank you? Find answers now! ... Quadratic equation PLEASE HELP? ... (5 + i √39) / 4 To make leading coefficient ...
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Suggested Questions And Answer :


solve x²+7x+12= 0

solve x²+7x+12= 0 I need to know how to work it out - please help!!!!! x² + 7x + 12 = 0 We need to find factors of 12 that add up to 7. They must be 3 and 4 (x + 3)(x + 4) = 0 One, or both, of those factors on the left must equal zero. (Multiplying by zero produces a zero result.) Set each one to zero and solve for x. (x + 3) = 0 x = -3 (x + 4) = 0 x = -4 Check both answers using the original equation. x² + 7x + 12 = 0 -3² + 7(-3) + 12 = 0 9 - 21 + 12 = 0 0 = 0 x² + 7x + 12 = 0 -4² + 7(-4) + 12 = 0 16 - 28 + 12 = 0 0 = 0 So, x = -3 and x = -4 are solutions. If you graph this equation, you will get a parabola that crosses the x axis at two points: (-3, 0) and (-4, 0)  
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solve y= 5x+2, x=6-3y. this is systems of equations :)

Problem: solve y= 5x+2, x=6-3y. this is systems of equations :) please help me l0l 1) y = 5x + 2 2) x = 6 - 3y Substitute the value of y, from equation 1, into equation 2. x = 6 - 3y x = 6 - 3(5x + 2) x = 6 - 15x - 6 x + 15x = 6 - 15x - 6 + 15x 16x = 6 - 6 16x = 0 x = 0 Use that to solve for y. y = 5x + 2 y = 5(0) + 2 y = 0 + 2 y = 2 Check. x = 6 - 3y 0 = 6 - 3(2) 0 = 6 - 6 0 = 0 Answer: x = 0, y = 2  
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how can you get the answer 7 while only using the number 2,0,1, and 2?

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Help understanding the quadratic equation

if the quadratic eqn is ax^2 + bx+c = 0 you can use the formula -a +/- sqrt(b^2-4ac) / (2a) in your case, all can be factored 1. (x-5)(x+1) = 0 2. (z-5)(z+3) = 0 3. (y-3)(y+1) = 0 4. (r+5)(r-1) = 0
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PLEASE HELP ME, THANKS A LOT: solve for X: x – 3 = - sqrt(25-12x)

x-3=-sqrt(25-12x)... (x-3)^2=(25-12x) x^2 -6x +9 -25+12x=0 x^2 +6x -16=0 (x-2)(x+8)=0 #### go bak tu top...(25-12x) gotta be >=0, so x gotta be < 25/12...2.083333333... ok, x=2 & x=-8 pass
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please explain 5sinx+5=0

please explain 5sinx+5=0 i came across this problem studying level 5 mathematics and was unsure how to solve it please help It is solved the way any algebra problem is solved. Add, subtract, multiply and divide as necessary to get the x term alone on the left side of the equation. 5 sinx  + 5 = 0 5 sinx + 5 - 5 = 0 - 5 5 sinx = -5 (5 sinx) / 5 = -5 / 5 sin x = -1 At this point, we don't have x, we have the sine of x. By using the inverse sin function, we can find what x is. x = arcsine -1 x = 90 degrees
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Guys can you help me solve these following equations

This should help: Simplifying 3p + -1 = 5(p + -1) + -2(7 + -2p) Reorder the terms: -1 + 3p = 5(p + -1) + -2(7 + -2p) Reorder the terms: -1 + 3p = 5(-1 + p) + -2(7 + -2p) -1 + 3p = (-1 * 5 + p * 5) + -2(7 + -2p) -1 + 3p = (-5 + 5p) + -2(7 + -2p) -1 + 3p = -5 + 5p + (7 * -2 + -2p * -2) -1 + 3p = -5 + 5p + (-14 + 4p) Reorder the terms: -1 + 3p = -5 + -14 + 5p + 4p Combine like terms: -5 + -14 = -19 -1 + 3p = -19 + 5p + 4p Combine like terms: 5p + 4p = 9p -1 + 3p = -19 + 9p Solving -1 + 3p = -19 + 9p Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '-9p' to each side of the equation. -1 + 3p + -9p = -19 + 9p + -9p Combine like terms: 3p + -9p = -6p -1 + -6p = -19 + 9p + -9p Combine like terms: 9p + -9p = 0 -1 + -6p = -19 + 0 -1 + -6p = -19 Add '1' to each side of the equation. -1 + 1 + -6p = -19 + 1 Combine like terms: -1 + 1 = 0 0 + -6p = -19 + 1 -6p = -19 + 1 Combine like terms: -19 + 1 = -18 -6p = -18 Divide each side by '-6'. p = 3 Simplifying p = 3
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please help solve (-12x+7)(6x-3)

(yx-3)(-12x +7) =-72x^2 +36x +42x -21 =-72x^2 +78x -21 if set it=0, get zeroes...(x-0.5)*(x-0.583333333)=0
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please help solve this quadartic problem step by step 26r-2=3rto the 2nd power also to simlify it in the end

26r-2=3r^2. The standard quadratic form is ax^2+bx+c=0, where x is the unknown and a, b and c are numbers. The unknown is r in this problem, so let's put the equation into quadratic form: 3r^2-26r+2=0. Note the sign changes as terms are transferred from one side to another, and also note that, in order to preserve the 3r^2 on the right I've brought all the terms over to the right to bring them all together. In doing so, which would have made the equation 0=3r^2-26r+2, I've moved the equals and zero over to the right to get it into quadratic form. I can do this because if A=B then it's true that B=A. This equation doesn't factorise, so we need the formula to solve it: r=(26+sqrt(26^2-4*3*2))/6 (this is the quadratic formula x=(-b+sqrt(b^2-4ac))/2a). So r=(26+sqrt(676-24))/6=(26+sqrt(652))/6=8.589 or 0.0776.
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Please help to solve for K: D=3K/K-8P. Desperate for help!

me assume that stuf shood be . . . d=3k/ (k-8p) . . . d(k-8p)=3k . . . dk -8pd -3k=0 . . k(d-3)-8pd=0 . . . k(d-3)=8pd . . . k=8pd/(d-3)
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