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a sum less than 10 and greater than 4 and each addend is less tham 5.

Sue wrote a doubles fact. It has a sum less than 10 and greater than 4. The addends are each less than 6. What fact might she have written?

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Sue wrote a double fact. It has a sum less than 10 and ...


Sue wrote a double fact. It has a sum less than 10 and greater than 4. The addends are each less than 5. What fact might she have written? - 119858
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Sue wrote doubles but it has a sum less then 10 and greater ...


Sue wrote doubles but it has a sum less then 10 and greater than 4 the addends are each less than 5. what might she have written - 1857694
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Sue wrote a double facts. It has a sum less than 10 and ...


Sue wrote a double facts. It has a sum less than 10 and greater than 4. The addends are each less than 5. What fact might she have written? Find answers now! No. 1 ...
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How to count/sum the cells greater than but less than a number?


How to count/sum the cells greater than but less than a number? There is a range of data in a worksheet as shown below, and now you want to count or sum the cells ...
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English Terms to Algebraic Expressions | Breakthru


English Terms to Algebraic Expressions. ... 5 less than 10: 10 ... Five times the sum of x and 2: 5(x = 2) Seven is greater than x: 7>x:
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How to use SUMIF for a greater-than AND less-than condition ...


Aug 18, 2010 · How to use SUMIF for a greater-than AND less-than ... to work for numbers greater than -10: ... example to sum the values from -10 to -19 ...
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Integers - Math League


... 4, 5, ... . Negative integers are all the opposites of these whole numbers: ... If an integer is greater than zero, ... If an integer is less than zero, ...
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How to find numbers in an array that are greater than, less ...


How to find numbers in an array that are greater than, less ... {2, 4, 6, 8, 10, 12, 14, 16}; int sum = 0 ... less than 5"). Something that happens after each ...
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Count numbers greater than or less than a number - Excel


View an example of how to use the COUNTIF function to count numbers greater than or less than a number in Excel 2007.
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Suggested Questions And Answer :


a sum less than 10 and greater than 4 and each addend is less tham 5.

????????????? "addend" ????????? ???????? "dubels fakt" ????? 2*x ?????? ????? maebee yu add tu integers ????
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what number am i

i am a number greater than 40.000 and less than 60.000 my ones digit and my tens digit are the same. my ten-thousands digit is 1 less than 3 times the sum of my ones digit and ten digit. my thousands digit is half my hundreds digit, and the sum of those two digits is 9 the ones and tens have to be 4 or 5. ( it need to greater than 40 and less than 60) (3 * (5 + 5)) = 29 so the tenths is 2, or (2 * (4 + 4)) - 1 = 23 same answer 2 the ten-thousanths number is 2 (i believe the teacher meant that the tenths digit not the ten-thousandths hundredths is 4, 6 or 8 we need to take half so it needs to be even thousandths is 2, 3 or 4 so the number is either 44.263
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it has a sum that is greater than the sum of 6+4 but less than the sum of 8+5

If the sum is greater than 6+4 it is greater than 10; and if it's less than 8+5 it's less than 13; so the sum must be 11 or 12. A sum implies the addition of two numbers so Max is probably thinking of 7+5 or 6+5. I'd go for 7+5 because 7 is between the 6 of the first sum and 8 of the second.
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I am greater than 4 tens and less than 5 tens. Ihave 9 ones. what number am i?

49 = 40 + 9 ones 44 = greater than 43 that means 40 +4= 8 the total of the digits 58 = number in 50's 50 + 8 =13 the total of teh digits
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# between 70 & 90. Sum of digits less than 12. Product of digits greater than 25. What is #?

kloesest me kan kum be..... number=93...sum=12, produkt=27 92 dont werk...produkt=18 . . . 83 produkt=24
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im less than 2500 and greater than 220. i am a multiple of 5. i am odd. the sum of my digits is 10.

won possabel=1405...1+4+5=10...... how bout 1315, 1405, 1225, 915, 825, 735, 645, 550
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finding sums of numbers

if you add 50 to a certain number the sum is less than 3  times the number. what is the smallest number for which this is true? Let the certain number be N. Then N + 50 is less than three times N N + 50 < 3N 50 < 2N 25 < N i.e. the number N must be greater than 25 So, the smallest value for N is 26
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prove that [1(2)+..... (elementary algebra)

The general term is n(n+1)=n^2+n. The sum is therefore the sum of the natural numbers up to n=n(n+1)/2 plus the sum of their squares=n^3/3+n^2/2+n/6. Therefore combined, these are n^2/2+n/2+n^3/3+n^2/2+n/6=n^3/3+n^2+2n/3. This can be written n(n^2+3n+2)/3=n(n+1)(n+2)/3=S, where S is the sum of the series. S/(n(n+3))=(n+1)(n+2)/(3(n+3)). What is the value of (n+2)/(3(n+3))? The minimum value is when n=1, (3)/(3(4))=1/4. So S/(n(n+3)) is less than or greater than (n+1)/4. When n>>1 (very much greater than 1), this expression gets closer to 1/3 and 1/3>1/4, so S/(n(n+3))>(n+1)/4.
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If the Mean is 40, the mode is 10, the range is 10, and the median is 5, what is the number sequence

If the data is in order and is represented by a1, a2, ..., an for dataset size n, where n is an odd number then a[(n+1)/2]=5. Also an=a1+10. It's also clear that a1<5 and an<15 since 5 is the median and the range is 10. If n is even then the median is the average of a[n/2] and a[(n+2)/2]. The mode is 10 and that implies at least two tens in the dataset. Mean, median and mode are different versions of the average, but mean=40. This is not consistent with the requirements, particularly because the range is 10 and the lowest datum has to be less than 5, the median. All the data values "left" of the median must be less than the median and those to the "right" of the median must be greater, by definition of the median. If we assume that the range at best is approximately 5 to 15, then the mean=40 lies outside the range which suggests an error in the question. The mean, or average, has to be within the range of the data. TENTATIVE SOLUTIONS Let us suppose that 40 is the sum of the data rather than the mean, which is the sum of the data divided by the size of the dataset. If the least of the data is a1 then the greatest is a1+10. We know that a1<5 so a1+10<15 and ≥10 so a1≥0. There have to be at least 2 tens in the data because the mode is 10. The minimum size of the data is 7 consisting of a1, a2, a3, 5, 10, 10, a1+10. We assumed the sum was 40 so 2a1+a2+a3+35=40 making 2a1+a2+a3=5. If a1=0, then a2+a3=5 and we know a3>a2>a1, so a2 and a3 could be 1 and 4, 2 and 3, 1.5 and 3.5, etc. This gives us the data: 0, 1, 4, 5, 10, 10, 10 where the median is 5, the mode is 10, the range is 10 and the mean is 40/7. We could also have: 0, 2, 3, 5, 10, 10, 10, etc. If we put a1=0.5 then a2 and a3 could be 1 and 3, 1.5 and 2.5, etc., giving us, for example: 0.5, 1.5, 2.5, 5, 10, 10, 10.5. This also meets all requirements with a mean of 40/7. If we keep the mean at 40 then we need to adjust the range. For the sake of illustration let the range be 100, so the greatest data value is 100+a1. More to follow... ​
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I'm a 5-digit number > 60k but < 70k. My 100s digit is 3 < my ones. D sum is 31. What number am I?

61996
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