Guide :

how do i solve then graph 2≤x -3≤6

I can't figure out the steps to solve then graph 2≤x -3≤6

Research, Knowledge and Information :

3.1 Inequalities - Solve and Graph Inequalities

Inequalities - Solve and Graph Inequalities Objective: Solve, ... − 2 − 2 Dividebyanegative− ﬂipsymbol! x 6 − 3 Graph, startingat− 3, goingdownwith] ...

Graphing Rational Functions: Another Example - Purplemath

Uses worked examples to demonstrate how to graph rational functions, ... x 2 + 5x + 6 = 0 (x + 3)(x + 2) = 0 ... then this graph has a slant asymptote. I'll ...

How do you graph g(x) = (x+3)(x+2)? + Example - Socratic.org

... Pick a few more points and connect to form graph. If g(x)=(x+3)(x+2) then when g(x) ... How do you graph the parabola # y=x^2-4x+5# using vertex, ...

6.3 Graphing Linear Equations - McGraw Hill Education

6.3 Graphing Linear Equations ... Given these values for x, we can substitute and then solve for the corresponding value for y. So ... Graph 2x y 6, using the steps ...

How do I solve f(x) = 4/7x - √(2) I need to make a ...

Get an answer for 'How do I solve f(x) = 4/7x - √(2) I need to make a representation table of f for x = -3, -3, -1,....,3 Then graph f in the window [-6,6,1] by [-4 ...

How do I solve f(x)=(x^3-8)/(x^2+5x+6) on a TI-84? | Socratic

Graph the function! When you are solving an equation, you are setting it equal to 0 and solving for where x is equal to 0. Therefore, with your calculator you should ...

find three points that solve the equation, then plot on graph ...

find three points that solve the equation, then plot on graph x+y=-2 - 2948055

Solve each inequality, then graph the solution. a 8x&gt;16 b ...

Solve each inequality, then graph the solution. - 2487604

Solving Equations - Math Is Fun

Some equations are true for all allowed values and are then called ... 2x + 3(x−3) − 6 = 0. Expand and solve: ... be solved by having x=3. Let us check: 2 × 3 3 ...

How do i solve simultaneous equation 5x+9y=-8 and x-y=10 in a graph?

Ok.  The graphing method is really easy.  Your equations are easy.  I'll tell you as cleary as possible how to graph it.  Ok.  First, you have to solve for each variable for each equation.  You can solve for y if x = 0, and solve for x if y = 0.  The answers will come out as a fraction, so just take a good guess where the plotted point should be.   After you have solved the first equation, draw a straigh line between them.   For the second equation, do the same thing.  However, YOU NEED TO PAY ATTENTION TO THE MINUS SIGN.  The minus sign makes y NEGATIVE Y.   Continuing, solve for x and y.  If y = 0, what does x equal and vice versa.  This answer will be a whole number.  Remember, Y IS NEGATIVE.  Make sure you plot them correctly on the graph.  The only reason I am not giving you the answer is because that would be cheating.  If you are still confused, view this video. It is exactly how I learned it when I was studying this topic. https://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/systems-through-examples/v/graphings-systems-of-equations

How do I solve y=-x-4

How do I solve y=-x-4 I need to be able to plot these points on a graph but i don't know how to solve the problem.   make an x & y axis. ( like a cross one line goes vertical an the other horizontal) put equal dimention for x & y line From center line moving to the left is negative line moving down is negative Just assign values for x & y then locate it at the x & y axis.                                                                                                                                                            SOLVE Y                                                                                        POINTS X Y 1 0 SOLVE Y 2 SOLVE X 0 3 1 SOLVE Y 4 SOLVE X 1 5 2 SOLVE Y 6 SOLVE X 2 7 -1 8 SOLVE X -1 9 -2 SOLVE Y 10 SOLVE X -2 11 3 SOLVE Y y=-x-4 sample: in point 1 => if  x = 0 y = - (0) - 4 y = - 4 in point 2 => if y = 0 0 = - x - 4 x = - 4 in point 7 => if x=-1 y = -x -4 y =-(-1) -4 y = +1 - 4 y = - 3 at point 8 => if y = -1 -1 = -x -4 x = -4 + 1 x = - 3 - 3 POINTS X Y 1 0 - 4 2 - 4 0 3 1 - 5 4 - 5 1 5 2 - 6 6 - 6 2 7 -1 8 - 3 -1 9 -2 - 2 10 - 2 -2 11 3 - 7 if you have done the 1 to 4 then you can plot the points from 1 to 11 and there is your graph.

how do you solve each linear system by graphing y=x+3 y=-2x+6

Problem: how do you solve each linear system by graphing y=x+3 y=-2x+6 solve each linear system by graphing. check your answer As seen on the graph, the point (1, 4) is on BOTH lines. y = x + 3 4 = 1 + 3 4 = 4 y = -2x + 6 4 = -2(1) + 6 4 = -2 + 6 4 = 4

solve the system of equations by graphing 9x-4y=12 and 9x=4y+12

Problem: solve the system of equations by graphing 9x-4y=12 and 9x=4y+12 solve the system of equations by graphing 9x-4y=12 and 9x=4y+12 Both equations are for the same line!

Suppose that in one week, your company takes in \$2,220 in sales at one of its cell phone stores. The price breakdown per phone is as follows: Cell phone model A4: \$35 Smartphone Z20: \$50 Suppose that a total of 51 phones were sold. Set up the system of equations that needs to be solved to determine how many of each type of phone were sold. Give a clear definition of the variables in the system. Solve the system of equations, showing clearly how the solution was determined, and state the results clearly in light of the real-world situation. Verify your results of the 2 linear equations by graphing in the desired graphing program and paste the graph in your assignment document (edit/copy image). Explain how the results are verified by the graph.

x^6+4x^5-3x^4-28x^3-46x^2-72x-72

There's nothing to solve because it's not equal to anything.  You can't solve something like 2x = 6 (x = 3) with the = part. As for graphing, if you want to do that by hand it will be a lot of work.  You'll need to computer a lot of numbers to get something that looks like what the graph actually looks like.  As a 6th degree equation it can have up to 5 humps (like how a 2nd degree equation, a parabola, has 1 hump), so it's going to be a challenge to graph by hand. If you want to see the graph without charting it yourself, just type plot(x^6+4x^5-3x^4-28x^3-46x^2-72x-72) into Google.

y=x^2-4 (find x and y intercepts, vertex and axis) I have the answer, but do not know how to work the problem

You can do this a few different ways. You can graph it on a graphing calculator and use the trace function to find the intercepts.  If you don't have a calculator you can plug in points for y and then solve for x.  You know that this is a parabola because of the x^2.  There are going to be 2 x values because you will have to take the square root. Let's take the example of setting y=0 which will also give us the x intercepts Plug that in and solve for x 0=x^2-4 add 4 to both sides 4=x^2 take the square root of both sides x=+2 and -2 so you have two points 0,2 and 0,-2 Now to find the y intercept you plug in 0 for x and solve for y y=0^2-4 y=-4 you now have a 3rd point -4,0 which is the y intercept.  You can draw the graph with that and see that the parabola is split by the y axis with a vertex at -4,0. Here is the graph.

y=2x+4, y=-5x-3 solve the system by graphing

Problem: y=2x+4, y=-5x-3 solve the system by graphing i just want to know how to solve it and how i can graph it?

how do you graph y=x squared

Problem: how do you graph y=x squared y=x squared how can it be graphed and how would you solve the problem Solve it by picking values for x and squaring them to get the y value.

solve for y=3x+4, and show both ordered sets on graph

The equation is linear in two variables, x and y. It can't be solved, as such, for particular values of x and y, but a straight line graph represents the dependency of one variable on the other. The graph is a mapping of the function in which the range of values of x and y is the set of all real numbers, so the graph maps x values onto y and y onto x in a unique way: there is only one value of x for a particular value of y, and only one value of y for a particular value of x. There is a real value of x for every real value of y and vice versa, subject to the dependency function y=3x+4, and no real values are excluded. The ordered pair (x,y) forms the set of real numbers satisfying the equation. Every point on the line (and there are an infinite number of them) is an ordered pair, and forms an infinite set. Each ordered pair is effectively a solution to the equation, so there are an infinite number of solutions.