Guide :

Explain how can 9x4 help you get 9x8

Explain how 9x4 can help you get 9x8? because i have no idea thank you!!!!!!.

Research, Knowledge and Information :


Explain how 9*4 can help you find 9*8. - Brainly.com


Explain how 9*4 can help you find 9 ... 9x4 can help you find 9x8 because after you find your answer all you have to do is add 9 four more times to get the sum of 9x8.
Read More At : brainly.com...

Explain how 9x4 can help you find 9x8 - Brainly.com


Explain how 9x4 can help you find 9x8 2. Ask for details ... you can get the answer of 9×4 which is 36 and add it to itself which is ... You can do 9x4 which ...
Read More At : brainly.com...

What is 9x4 - Answers.com


What is 9x4? SAVE CANCEL ... How can 9X4 help you find 9X8? 9x4 doubled = 9x8 4 people found this useful Edit. Share to: Eric Barnes.
Read More At : www.answers.com...

Explain how you can break a part 3 x 9 to help you multiply?


Explain how you can break a part 3 x 9 to help you multiply? SAVE CANCEL. already exists. Would you like to merge this ... Name and explain the 3 parts of interphase?
Read More At : www.answers.com...

Grade 4: Distributive Property of Multiplication: Overview


Distributive Property of Multiplication: Overview. ... You can see that there are now three groups of 4 ... you can apply the property to help you “condense” the ...
Read More At : www.eduplace.com...

Math Properties - McGraw Hill Education - Engrade Wikis


Review Of The Definitions & Examples of Math Properties. ... Help Engrade › Wikis › Math Properties Ms. Smith. 22 Likes Options. Print. More from Ms. Smith.
Read More At : wikis.engrade.com...

Suggested Questions And Answer :


Explain how can 9x4 help you get 9x8

9*8=9*4*2 =2*(9*4) .....
Read More: ...

What equation models the data? What are the domain and range of the equation? Do you think your equation is a good fit for the data? Explain how you determined your answers.

Look first at the differences between the data. Call these D1, D2, etc. No need for $ sign. All figures in cents. D1: 31, 23, 45, 109, 43, 75, 27, -11, -38, -108 D2: -8, 22, -36, 34, 32, -48, -38, -27, -70 D3: 30, -58, 70, -2, -80, 10, 11, -43 D4: -88, 128, -72, -78, 90, 1, -54 No pattern, so perhaps statistical analysis will help. Linear regression, perhaps. Mean is $2.892 for money data (Y). Mean is 2010 for other data (X). A table will help: X Y XY X^2 2005 2.27 4551.35 4020025 2006 2.58 5175.48 4024036 2007 2.81 5639.67 4028049 2008 3.26 6546.08 4032064 2009 2.35 4721.15 4036081 2010 2.78 5587.80 4040100 2011 3.53 7098.83 4044121 2012 3.60 7243.20 4048144 2013 3.49 7025.37 4052169 2014 3.11 6263.54 4056196 2015 2.03 4090.45 4060225 TOTAL: 22110 31.81 63942.92 44441210 From these totals the slope=(11*(3rd column)-(1st col)*(2nd col))/(11*(4th col)-(1st col)^2)= (11*63942.92-22110*31.81)/(11*44441210-488852100)=0.04382. Intercept=((2nd col)-slope*(1st col))/11=(31.81-0.04382*22110)/11=-85.1827. The equation is Y=0.04382X-85.1827, which represents the best model to fit the data, assuming a linear relationship. Using this equation we get (2005,2.67), (2006,2.72), (2007,2.76), (2008,2.80), (2009,2.85), (2010,2.89), (2011,2.94), (2012,2.98), (2013,3.02), (2014,3.07), (2015,3.11) as the pairs of (X,Y) values. If the relation is non-linear, plotting the values may give us a clue. If we omit figures for 2009 and 2010, the graph resembles a parabola. We can find the average slope between consecutive pairs of points, ignoring 2009 and 2010: 2005-2006: 31; 2006-2007: 23; 2007-2008: 45; 2008-2011: 27/3=9; 2011-2012: 7; 2012-2013: -11; 2013-2014: -38; 2014-2015: -108. If this were a parabola, we would expect the negative and positive slopes to be opposites after the maximum at 2012, but this doesn't appear to be the case. However, this points to a maximum for the range at $3.60. The domain goes from 2005 to 2015 and we don't have a satisfactory model for the figures.
Read More: ...

Simplifying Ratios

For the first question you need to find the greatest common factor. Start by trying 2 and work your way up. 2 does not work because it will not go into 35 or 63. 3 does not go evenly into 35. 4 also will not work. 5 does not work. 6 also will not work. . .Then we come to 7. . .if we divide each number by 7 we get the following: 6:5:9 We know this is in lowest simplist form because 5 is a prime number. Next we need to convert kilograms to grams by multiplying by 1000 to get 35000 g : 1400 g in this case the greatest common factor is 1400 which if we divide both numbers we get 25 g : 1 g For the final question we should convert to mm 2.5m=2500mm 75cm=750mm 350 mm : 2500 mm : 750 mm We know that 50 will go evenly into each of these and we know that 350/50 is 7 which is prime. So 50 must be the greatest common factor.  Divide all 3 terms by 50 and we get 7 mm : 50 mm : 15 mm
Read More: ...

flipping two coins, what is the probability of getting two heads

how bout if yu flip 1 koin 2 times??? chans=1/4   (assume "unbiased or faer" koin) eech flip, hav 50% chans yu get hed 2 times=50% av 50%
Read More: ...

Explain the results of the following options: Option 1: 6% compound interest quarterly for 5 years. Option 2: 8% compound interest annually for 5 years. Option 3: 14.5% simple interest for 10 years.

MEMO TO CLIENT Simple interest applies the interest rate proportionately, so the amount of interest on a particular investment is directly proportional to the length of time invested. This means that, for example, if the investment period is 5 years, the interest is 5 times the interest earned in one year; for 10 years it is 10 times that earned in a year. It is also easy to calculate because of this simple proportion. Compound interest is more rewarding to the investor. After a period of time, for example, a year, the interest earned in the year is added to the original amount invested. So at this point, it is the same as simple interest. But what happens next is different. The investment plus the interest becomes the invested amount for the next period, the next year, for example. At the end of this period the process continues, and the interest is again added and becomes the investment amount for the next period. So it is clear that over a period of time more and more interest is earned. An important feature that investors need to be aware of is: how regularly is compound interest added? The shorter the period, the bigger the interest earned. Interest can be compounded annually, quarterly, monthly, daily or continuously. So, if the investor is quoted a particular annual rate of interest, then the largest amount of interest gained will correspond to the shortest compound interest period. As an example, take 6% per annum, or annual interest rate. After a year with interest compounded annually, 6% interest will be earned. If interest is compounded quarterly, then each quarter the interest will be added at a rate of 1.5% each quarter, but by the end of a year, the effective interest will be more than 6.1%. If interest is compounded monthly, the monthly rate would be 0.5% and after a year would be effectively closer to 6.2%. Interest compounded daily would be even closer to 6.2% and continuously would be slightly more. Growth is a convenient way of expressing the factor by which an investment increases over time, and companies will often publish tables to simplify calculations of expected returns on investments at fixed rates. The time periods will be typically 5, 10, 15, 25 years for a range of annual rates. So investors can quickly calculate the returns on varying amounts of money. As an example, take 15 years. The growth rates at 6% per annum would be: 1.9 (simple interest); 2.40 (compounded annually); 2.44 (compounded quarterly); 2.45 (compounded monthly); 2.46 (compounded daily or continuously). Option 1 6% annually is 1.5% quarterly, so growth is 1.015^20=1.3469, where 20 is 20*(1/4)=5 years. $500000*1.3469=$673,427.50 to best accuracy. Option 2 8% compounded annually: growth=1.08^5=1.4693 and amount is $500000*1.4693=$734,664.04. Option 3 14.5% simple interest for 10 years: 145% interest=1.45*500000=$725,000 interest+500000=$1.225 million. The first two options have the same investment time period, and option 2 is better. Option 3 has double the time period. If option 3 were to be applied over 5 years instead of 10, the interest would have been $362,500 (half of $725,000) and the total amount would have been $862,500. However, the investment is over ten years so the investor would need to wait 10 years before taking full advantage of the investment. Take option 2 over 10 years and we get a growth rate of 2.1589 making the investment worth $1,079,462.50, which is still smaller than option 3, which had a growth rate of 2.45 (1.45+1) because of the higher interest rate.  
Read More: ...

how do you get the answer to 2/5ths of 12

I need to know how to show her how to get the answer so I can help her
Read More: ...

whats the answer to -2x + 3 > 3(2x - 1)

We need to expand the brackets on the right: -2x+3>6x-3. Add 2x to each side of the inequality: 3>8x-3 and add 3 to each side: 6>8x. Another way of writing this is 8x<6. Divide through by 2: 4x<3 and divide through by 4: x<3/4. We added 2x to each side because that helps us to bring the x's together. We added 3 to each side to bring the numbers together. Now we've ended up with x's on one side and a number on the other. Just what we want. 2 is common to 6 and 8 so we simplify the inequality by dividing through by it. Then to get x instead of 4x we divided through by 4. Why is 6>8x the same as 8x<6? Well, think about it. 2<3, isn't it? So 3>2. That's true. If Jack is taller than Jill, then Jill is shorter than Jack. See how it works? You just reverse the inequality when the quantities swap sides. It's a good idea to check your answer by substituting a value for x in the original inequality, just to make sure we haven't made a mistake. The answer was that x must be less than 3/4 so let's try x=1/2. -2x+3 is -1+3=2. Now the right side: 2x-1 is 1-1=0 multiplied by 3 is still zero. Is the inequality correct? Yes it is, because 2 is greater than zero. If we put x=1 we should find that the inequality doesn't work out because x is bigger than 3/4. Let's see. The left is 3-2=1 and the right is 3. 1 isn't bigger than 3, so the inequality is false, as expected. If we put x=3/4 we will find that the left equals the right when it should be bigger than it. Looks like x<3/4 is right!
Read More: ...

find all reconstuctions of the sum: ABC+DEF+GHI=2014 if all letters are single digits

There is no solution if A to I each uniquely represent a digit 1 to 9, because the 9's remainder of ABC+DEF+GHI (0) cannot equal the 9's remainder of 2014 (=7). Let me explain. The 9's remainder, or digital root (DR), is obtained by adding the digits of a number, adding the digits of the result, and so on till a single digit results. If the result is 9, the DR is zero and it's the result of dividing the number by 9 and noting the remainder only. E.g., 2014 has a DR of 7. When an arithmetic operation is performed, the DR is preserved in the result. So the DRs of individual numbers in a sum give a result whose DR matches. If we add the numbers 1 to 9 we get 45 with a DR of zero, but 2014 has a DR of 7, so no arrangement can add up to 2014. If 2 is replaced by 0 in the set of available digits, the DR becomes 7 (sum of digits drops to 43, which has a DR of 7). 410+735+869=2014 is just one of many results of applying the following method. Look at the number 2014 and consider its construction. The last digit is the result of adding C, F and I. The result of addition can produce 4, 14 or 24, so a carryover may apply when we add the digits in the tens column, B, E and H. When these are added together, we may have a carryover into the hundreds of 0, 1 or 2. These alternative outcomes can be shown as a tree. The tree: 04 >> 11, >> 19: ............21 >> 18; 14 >> 10, >> 19: ............20 >> 18; 24 >> 09, >> 19: ............19 >> 18. The chevrons separate the units (left), tens (middle) and hundreds (right). The carryover digit is the first digit of a pair. For example, 20 means that 2 is the carryover to the next column. Each pair of digits in the units column is C+F+I; B+E+H in the tens; A+D+G in the hundreds. Accompanying the tree is a table of possible digit summations appearing in the tree. Here's the table: {04 (CFI): 013} {09 (BEH): 018 036 045 135} {10 (BEH): 019 037 046 136 145} {11 (BEH): 038 047 137 056 146} {14 (CFI): 059 149 068 158 167 347 086 176 356} {18 (ADG): 189 369 459 378 468 567} {19 (BEH/ADG): 379 469 478 568} {20 (BEH): 389 479 569 578} {21 (BEH): 489 579 678} {24 (CFI): 789} METHOD: We use trial and error to find suitable digits. Start with units and sum of C, F and I, which can add up to 4, 14 or 24. The table says we can only use 0, 1 and 3 to make 4 with no carryover. The tree says if we go for 04, we must follow with a sum of 11 or 21 in the tens. The table gives all the combinations of digits that sum to 11 or 21. If we go for 11 the tree says we need 19 next so that we get 20 with the carryover to give us the first two digits of 2014. See how it works? Now the fun bit. After picking 013 to start, scan 11 in the table for a trio that doesn't contain 0, 1 or 3. There isn't one, so try 21. We can pick any, because they're all suitable, so try 489. The tree says go for 18 next. Bingo! 567 is there and so we have all the digits: 013489576. We have a result for CFIBEHADG=013489576, so ABCDEFGHI=540781693. There are 27 arrangements of these because we can rotate the units, tens and hundreds independently like the wheels of an arcade jackpot machine. For example: 541+783+690=2014. Every solution leads to 27 arrangements. See how many you can find using the tree and table!
Read More: ...

how can I get my answer for 2x+5=3

2x+5=3 2x=-2 x=-1
Read More: ...

Step by step explain to me how to solve the following problem please:

y=3x, then put x=2 in equashun & yu get y=6, so (2,3) dont fit tri x=-4 & yu get y=-12...(-4,12) fit
Read More: ...

Tips for a great answer:

- Provide details, support with references or personal experience .
- If you need clarification, ask it in the comment box .
- It's 100% free, no registration required.
next Question || Previos Question
  • Start your question with What, Why, How, When, etc. and end with a "?"
  • Be clear and specific
  • Use proper spelling and grammar
all rights reserved to the respective owners || www.math-problems-solved.com || Terms of Use || Contact || Privacy Policy
Load time: 0.1136 seconds