Guide :

choose one card from each of the four suits in a standard deck of playing cards.

how many ways can four queens be chosen?

Research, Knowledge and Information :


Playing Card Frequencies - Milefoot


Playing Card Frequencies. A standard deck of 52 playing ... that are face cards, in four suits each. ... for the single card, then one of the 13 cards in ...
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How many cards are in a deck? Also, how many of each card ...


How many cards are in a deck? Also, how many of each card ... A standard deck has 52 cards (4 suits ... A card is missing from a deck of cards. If I pull one card ...
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Homework 2 Solutions - Computer Science and Engineering


Homework 2 Solutions ... cards which have 52 cards, with 13 of each of the four suits ... and then choose one card from each of the the remaining 3 suits.) (b) ...
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Why was it decided to have four suits of thirteen cards each ...


... thirteen cards each in the standard playing card deck? ... four suits of a standard deck of playing ... each 13 cards. How many ways can you choose 2 kings ...
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Using a standard deck of cards, find the probability that: 1 ...


... You choose two cards and one is a face card and ... that utilizes a standard 52-card deck containing four suits ... a deck of playing cards. Each flips ...
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A standard deck of 52 playing cards contains 13 cards in each ...


A standard deck of 52 playing cards ... cards contains 13 cards in each of four suits: ... of picking either one club or one spade as the next card ...
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Four ways to use playing cards for decision making


Four ways to use playing cards for simple decision ... The first thing to understand is the structure of a standard deck of cards. ... Choose one card for each option.
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Choosing a Perfect Deck of Playing Cards Made Easy!


Choosing a Perfect Deck of Playing Cards ... A Pinochle deck has six fewer cards than a standard deck of cards. ... Queen, Jack and Nine for each of the four suits.
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a standard deck of cards contains 52 cards in four suits of ...


A standard deck of playing cards contains 52 ... of 52 playing cards. The deck has four 13−card suits ... choose two cards and one is a face card and the ...
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How do you use regular playing cards for fortune telling ...


Use regular playing cards to tell the future by associating the four suits ... use regular playing cards ... deck of standard playing cards. Each card in ...
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Suggested Questions And Answer :


choose one card from each of the four suits in a standard deck of playing cards.

If the order doesn't matter (Qspades, Qhearts, Qclubs, Qdiamonds = Qhearts, Qspades, Qclubs, Qdiamonds), then there's only 1 way because you're choosing exactly 4 cards and there are exactly 4 queens. If the order does matther (Qspades, Qhearts, Qclubs, Qdiamonds does not = Qhearts, Qspades, Qclubs, Qdiamonds), then there are 4 * 3 * 2 * 1 = 24 ways because there are 24 ways to arrange the different queens among themselves.  There are 24 ways to shuffle a deck of 4 different cards.
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Count the number of elements in the event

Let's call the valued cards royal. In a pack of 52 cards there will be 16 royals. The odds of picking one of them is 16 in 52. That leaves 51 cards containing 15 royals. So the odds of picking another royal is 15 in 51. So we continue until only 37 remain, one of which is the remaing royal. The odds of picking all 16 royals in any order is therefore 16/52*15/51*...1/37 to 1 against. The number of events is the reciprocal of this which is 52C16 in nCr format. This evaluates to 10,363,194,502,115. Go for it - you can't lose!! Not!
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What is the probability of red cards to diamonds in a standard deck of cards?

The probability of diamond being red is 1 (certainty) because all diamonds (in cards) are red. However, the probability of a red card being a diamond is 1/2 because there are as many hearts as diamonds. The probability of a card being red is 1/2 because half the cards in a pack are black and half red. The probability of a card being a diamond is 1/4 because there are four different suits. I hope this helps.
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Find the number of ways four cards of the same suit can be drawn from a 52-card deck of cards.

a. Since there are four suits, there are four ways of choosing the suit. b. The number of ways of picking 4 cards out of 13 of the same suit is 13*12*11*10/1*2*3*4=715. c. The number of ways of picking 4 cards out of 52=270,725. It is assumed that the order is unimportant.
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What is the probability that a total of 2 spades will be chosen

The chances of picking 2 spades from Decks 1 and 2 (scenario 1) is 1/4*1/4=1/16. The chances of not picking a spade first then picking two spades from Decks 2 and 3 in scenario 2 is 3/4*1/4*1/4=3/64. Since the two scenarios are mutually exclusive the probability of either one is 1/16+3/64=7/64.
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2.if a card is drawn at random from a well-shuffled standard deck of cards,what is the probability that it is not a face card? a.4/3 b.6/11 c.7/11 d.9/13

There are 3 face cards in a suit of 13 cards, or 12 in a standard pack of 52. The aces are not usually included as face cards. Therefore there are 10 non-face cards in a suit, making the probability of randomly drawing one of these 10/13. If the ace is included as a face card then the probability of a non-face card is 9/13.
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nick chooses one card from a standard deck of cards and then rolls a number cube. what is the probability that nick chooses a heart and rolls a 2?

The probability of picking a heart is 1 in 4 and the probabiloty of rolling a 2 is 1 in 6, so the combined probability is 1/4*1/6=1/24 (answer D).
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probability of getting 6 of clubs

There is only one 6 of Clubs in a standard pack of 52 playing cards, so the probability of selecting it is 1/52, the same as selecting any other specific card. There are 4 suits so there is a probability of 13/52=1/4 of selecting any Club; and a probability of 1/13 in selecting a 6 of any suit. The probability of selecting a Club and a 6 is 1/4*1/13=1/52. The probability of selecting a diamond or a 3 is 1/4+1/13=13/52+4/52=17/52.
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if 4 cards are drawn from a deck without replacement what is the probability one is a spade

There is a probability of 1/4 that the first card drawn is a spade. That leaves 51 cards, including the 12 remaining spades. The chance that the second card drawn is not a spade is 39/51; then this goes to 39/50 for the third card; and for the fourth card it is 39/49. So the total probability we have: 1/4*39/51*39/50*39/49=0.118685 approx. But we can also have the probability of not drawing a spade as the first card=3/4; the second card is a spade=13/51; the third card not a spade=39/50 (as before); the fourth card not a spade=39/49 (as before). But 1/4*39/51=3/4*13/51, so the probability of drawing just one spade within 4 cards is 4*0.118685=0.4747 or 47.47% approx., because any of the four cards can be the spade.
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Three cards are drawn in sequence from a deck of cards without replacement. Find the probability distribution for the number of spades.

There are 4 suits so the chances of picking a spade initially are 1/4. There are 13 of each suit in a pack. No spades: 39 other cards so if the first card is not a spade the probability is 39/52=3/4. Now there are 51 cards left, 13 of which are spades. The probability of no spade next is 38/51, then for the third card 37/50. The combined probability for no spades is 703/1700. One spade: if a spade is drawn first the chances are 1/4. The next card is not a spade, chances are 39/51, and the third 38/50. Overall: 247/1700. Suppose the spade was drawn second: overall: 3/4 * 13/51 * 38/50=247/1700, and the same probability applies if the spade was third. So we have 3*247/1700=741/1700. Two spades: this is similar to the non-spade being drawn in 1st, 2nd or 3rd position. We multiply one probability by 3. First two are spades: 1/4 * 12/51 * 39/50=39/850. Multiply by 3: 117/850. Three spades: 1/4 * 12/51 * 11/50=11/850. So we have: #spades Probability 0             703/1700 1             741/1700 2             117/850 3               11/850 TOTAL:        1
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