Guide :

108 metres squared carries 0.5 tonnes. How much does 67.5 square centimetres?

A stage of 12 x 9 (108 metres squared) metres has a deck loading of 0.5 tonnes, what is the deck loading of the stage scaled down to 30 x 22.5 centimetres (67.5 centimetres squared)?

Research, Knowledge and Information :


3 Simple Ways to Calculate Square Meters - wikiHow


How to Calculate Square Meters. ... Since 1 square foot = 0.093 square meters, ... 67% of people told us that this article helped them.
Read More At : www.wikihow.com...

5 square metres - Math Central


an area of 5 square metres and an area of 5 m 2 (5 metres squared) mean exactly the same thing. ... The word square or squared refers to the units and not the shape.
Read More At : mathcentral.uregina.ca...

Square Meters to Square Centimeters conversion


Square Meters to Square Centimeters. Bookmark Page Square Centimeters to Square Meters (Swap Units) Format Accuracy Note ... Square Centimeters; 0 m ...
Read More At : www.metric-conversions.org...

CHAPTER 1 - BASIC TERMS AND CALCULATIONS


... BASIC TERMS AND CALCULATIONS. ... The surface of these triangles is expressed in square centimetres ... A = 0.5 x (108 cm + 16 cm) ...
Read More At : www.fao.org...

Convert metric tonnes to tons - Convert Units - Measurement ...


Convert metric tonnes to tons ... equal to 0.001 metric tonnes, or 0.00110231131092 ... 100 kg, US fluid ounce, 6'3", 10 stone 4, cubic cm, metres squared ...
Read More At : www.convertunits.com...

Square Feet to Square Centimeters - Metric Conversion charts ...


Square Feet to Square Centimeters. ... 20438.67 cm ²: 23 ft²: 21367.70 cm² ... In metric terms a square foot is a square with sides 0.3048 metres in length.
Read More At : www.metric-conversions.org...

How do I convert meters to square meters? | Reference.com


How do I convert meters to square meters? A: ... Four millimeters is equal to 5/32 inch, 0.4 centimeters, or 0.004 meters. There are 25.4 millimeters in one inch.
Read More At : www.reference.com...

Aggregate Calculator gravel stone chippings path driveway


Cloburn Quarry Aggregate Calculator ... one tonne will cover 14 square metres. ... Compacted Firechip weighs 2 tonnes per cubic metre.
Read More At : www.cloburn.co.uk...

Calculating gravel tonnage, cubes, and sand and earth.


... What area do I need? How much coverage area is a square ... How much does a ... which does do the math/conversions of US Tons and Metric tonnes ...
Read More At : www.stabiligrid.biz...

Online Conversion - Area calculator


Area Calculator Enter the Length ... Area in Square Feet: Area in Square Meters . Did you find us useful? Please consider supporting the site with a small donation.
Read More At : www.onlineconversion.com...

Suggested Questions And Answer :


108 metres squared carries 0.5 tonnes. How much does 67.5 square centimetres?

??????????????? "tonnes" ???????????????? ??????????? "metres" ???????? ??????? "108 metres squared ????? du yu meen 108 sumthun or iz zat spozed tu be 108^2 ???????????
Read More: ...

HELP ME!!!!!!!!!!!! I'M STUPID

1. maebee yu luv tu be frustrated, thats wot puter is for 2. ?? "chook pen" ??, wot du chook look like? 3. 15&50=750, not 800 4. I take it, yu wanna find biggest area yu kan get with 80 meters for 3 sides me no anser: square...eech side=80/3, area=711.1111111... 5. yu don trust me? length+2*wide=80, so leng=80-2*wide area=length*wide=wide*(80-2wide) =80wide-2*wide^2 tu find max or min, take derivativ...80-4wide & set it tu 0...4(20-wide)=0 or wide=20, leng=40, area=800 the mistreeus math gremlins hit agin
Read More: ...

if a rectangle is 54 sqm and the length is equal to width +5 what is the equation to work out l& w

Note:  I'm not sure what your teacher wants you to do with the 54 m^2 rectangle because an equation below doesn't factor easily and required (for me at least) a formula you shouldn't have yet in Algebra 1.  The answer is correct, but you shouldn't yet know how to get it.  I assume you're talking about area (instead of perimeter) because you mention square meters (measure of area) instead of meters (measure of length, width, perimeter).  The 50 m^2 rectangle (see below) works out nicer. Length = L Width = W W * L = 54 W * (W + 5) = 54 W^2 + 5W = 54 W^2 + 5W - 54 = 0 Quadratic formula If ax^2 + bx + c = 0 then x = (-b +- sqrt(b^2 - 4ac) ) / 2a (I know you shouldn't have this yet in Algebra 1, but W^2 + 5W - 54 doesn't look like it factors nicely, so this is the only other way I know to factor it) W = (-5 +- sqrt (25 + 216) ) / 2 W = (-5 +- sqrt(241) ) / 2 You can't have negative width, so: W = (-5 + sqrt(241) ) / 2 W = about about 5.26 L = W + 5 L = about 10.26 . If the rectangle inside is 2 x 2 meters smaller, that's 4 m^2 smaller, 54 - 4 = 50 m^2. Length = L Width = W W * L = 50 W * (W + 5) = 50 W^2 + 5W = 50 W^2 + 5W - 50 = 0 (W - 5)(W + 10) = 0 W = 5, -10 But we can't have negative width, so: W = 5 L = W + 5 L = 10 Answer:  Width is 10, length is 5. (much easier answer)
Read More: ...

10 vedic maths rules for class IX

2 instead of 5: 34/5 can be calculated by multiplying 34 by 2 instead of dividing by 5. 34*2=68. We just move the decimal point one place to the left: 34/5=6.8. 124/5=24.8 because 124*2=248. Move the decimal point: 248 becomes 24.8. 34*5 is the same as 34/2=17 but we add a zero to make 17 into 170. 73*5 is the same as 73/2=36.5 then move the decimal point one place to the right (or add zero): 36.5 becomes 365=73*5. So we only need to know how to multiply and divide by 2 to divide and multiply by 5. We just move the decimal point. Divisibility by 9 or remainder after dividing by 9. All multiples of 9 contain digits which added together give 9. As we add the digits together, each time the result goes over 9 we add the digits of the result together and use that result and continue in this way up to the last digit. Is 12345 divisible by 9? Add the digits together 1+2+3=6. When we add 4 we get 10, so we add 1 and zero=1 then we add 5 to get 6. The number is not exactly divisible by 9, but the remainder is 6. We can also ignore any 9's in the number. Now try 67959. We can ignore the two 9's. 6+7=13, and 1+3=4; 4+5=9, so 67959 is divisible by 9. Multiplying by 11. Example: 132435*11. We write down the first and last digits 1 ... 5. Now we add the digits in pairs from the left a digit step at a time. So 1+3=4; 3+2=5: 2+4=6; 4+3=7; 3+5=8. Write these new digits between 1 and 5 and we get 1456785=132435*11. But we had no carryovers here. Now try 864753*11. Write down the first and last digits: 8 ... 3. 8+6=14, so we cross out the 8 and replace it with 8+1=9, giving us 94 ... 3. Next pair: 6+4=10. Again we go over 10 so we cross out 4 and make it 5. Now we have 950 ... 3. 4+7=11, so we have 9511 ... 3. 7+5=12, giving us 95122 ... 3; 5+3=8, giving us the final result 9512283.  Divisibility by 11. We add alternate digits and then we add the digits we missed. Subtract one sum from the other and if the result is zero the original number was divisible by 11. Example: 1456785. 1 5 7 5 make up one set of alternate digits and the other set is 4 6 8. 1+5+7=13. We drop the ten and keep 3 in mind to add to 5 to give us 8. Now 4 6 8: 4+6=10, drop the ten and add 0 to 8 to give us 8 (or ignore the zero). 8-8=0 so 11 divides into 1456785. Now 9512283: set 1 is 9 1 2 3 and set 2 is 5 2 8; 9+1=0 (when we drop the ten); 2+3=5; set 1 result is 5; 5+2+8=5 after dropping the ten, and 5-5=0 so 9512283 is divisible by 11. Nines remainder for checking arithmetic. We can check the result of addition, subtraction, multiplication and (carefully) division. Using Method 2 above we can reduce operands to a single digit. Take the following piece of arithmetic: 17*56-19*45+27*84. We'll assume we have carried out this sum and arrived at an answer 2365. We reduce each number to a single digit using Method 2: 8*2-1*9+9*3. 9's have no effect so we can replace 9's by 0's: 8*2 is all that remains. 8*2=16 and 1+6=7. This tells us that the result must reduce to 7 when we apply Method 2: 2+3+6=11; 1+1=2 and 2+5=7. So, although we can't be sure we have the right answer we certainly don't have the wrong answer because we arrived at the number 7 for the operands and the result. For division we simply use the fact that a/b=c+r where c is the quotient and r is the remainder. We can write this as a=b*c+r and then apply Method 2, as long as we have an actual remainder and not a decimal or fraction. Divisibility by 3. This is similar to Method 2. We reduce a number to a single digit. If this digit is 3, 6 or 9 (in other words, divisible by 3) then the whole number is divisible by 3. Divisibility by 6. This is similar to Method 6 but we also need the last digit of the original number to be even (0, 2, 4, 6 or 8). Divisibility by 4. If 4 divides into the last two digits of a number then the whole number is divisible by 4. Using 4 or 2 times 2 instead of 25 for multiplication and division. 469/25=469*4/100=1876/100=18.76. 538*25=538*100/4=134.5*100=13450. We could also double twice: 469*2=938, 938*2=1876, then divide by 100 (shift the decimal point two places to the left). And we can divide by 2 twice: 538/2=269, 269/2=134.5 then multiply by 100 (shift the decimal point two places left or add zeroes). Divisibility by 8. If 8 divides into the last three digits of a number then the whole number is divisible by 8. Using 8 or 2 times 2 times 2 instead of 125 for multiplication and division. Similar to Method 9, using 125=1000/8. Using addition instead of subtraction. 457-178. Complement 178: 821 and add: 457+821=1278, now reduce the thousands digit by 1 and add it to the units: 278+1=279; 457-178=279. Example: 1792-897. First match the length of 897 to 1792 be prefixing a zero: 0897; complement this: 9102. 1792+9102=1894. Reduce the thousands digit by 1 and add to the result: 894+1=895. Example: 14703-2849. 2849 becomes 02849, then complements to 97150. 14703+97150=111853; reduce the ten-thousands digit by 1 and and add to the result: 11854. Squaring numbers ending in 5. Example: 75^2. Start by writing the last two digits, which are always 25. Take the 7 and multiply by 1 more than 7, which is 8, so we get 56. Place this before the 25: 5625 is the square of 75. The square of 25 is ...25, preceded by 2*3=6, so we get 625. All numbers ending in 0 or 5 are exactly divisible by 5 (see also Method 1). All numbers ending in zero are exactly divisible by 10. All numbers ending in 00, 25, 50 or 75 are divisible by 25. Divisibility by 7. Example: is 2401 divisible by 7? Starting from the left with a pair of digits we multiply the first digit by 3 and add the second to it: 24: 3*2+4=10; now we repeat the process because we have 2 digits: 3*1+0=3. We take this single digit and the one following 24, which is a zero: 3*3+0=9. When we get a single digit 7, 8 or 9 we simply subtract 7 from it: in this case we had 9 so 9-7=2 and the single digit is now 2. Finally in this example we bring in the last digit: 3*2+1=7, but 7 is reduced to 0. This tells us the remainder after dividing 2401 by 7 is zero, so 2401 is divisible by 7. Another example: 1378. 3*1+3=6; 3*6=18 before adding the next digit, 7 (we can reduce this to a single digit first): 3*1+8=3*1+1=4; now add the 7: 4+7=4+0=4;  3*4=12; 3*1+2+8=5+1=6, so 6 is the remainder after dividing 1378 by 7.  See also my solution to: http://www.mathhomeworkanswers.org/72132/addition-using-vedic-maths?show=72132#q72132
Read More: ...

How to Find Square Root

98=49*2, so sqrt(98)=sqrt(49)*sqrt(2)=7sqrt(2)=7*1.4142=9.8994 approx. There's another way using the binomial theorem. 98=100-2=100(1-0.02). sqrt(100)=10 so sqrt(98)=10(1-0.02)^(1/2) because square root is the same as power 1/2. (1+x)^n expands to 1+nx+(n(n-1)/1*2)x^2+(n(n-1)(n-2)/1*2*3)x^3+... Putting n=1/2 and  x=-0.02, we get sqrt(98)=10(1-0.02)^(1/2)=10[1-(1/2)0.02+((1/2)(-1/2)/2)0.0004+...]. This gives us: 10(1-0.01-0.00005+...)=10*0.98995=9.8995. A third method is to use an iterative process, which means you keep repeating the same action over and over again. Look at this: x=10-(2/(10+x)). If we solve for x we get x=sqrt(98); but we're going to find x in an iterative way. Start with x=0 and work out the right hand side: 10-2/10=9.8. This gives us a new value for x, 9.8, which we feed back into the right hand side: 10-(2/(10+9.8))=10-2/19.8=9.8989..., giving us another value for x, 9.8989... which we feed back into the right hand side: 10-(2/(10+9.8989...))=9.89949..., giving us yet another value for x and so on. Very quickly we build up accuracy with each x. You can do this on a calculator, a basic one that doesn't even have square roots, using the memory to hold values for you. Here's a very simple program, where STO means store in memory (if your calculator doesn't have STO use MC (memory clear) followed by M+ (add to memory)); MR means read memory (the steps show what calculator keys to press in order; / may be ÷ on your calculator): 0= +10=STO 10-2/MR= GO TO STEP 2 OR STOP (display should show the answer for sqrt(98)) Note: In STEP 3 the division must be carried out before subtracting from 10, otherwise you get the wrong answer. If your calculator doesn't do this you need to replace STEP 3 with: 0-2=/MR=+10= You should only have to go round the loop a few times before you get a really accurate result. To find the square root of 2 directly the iteration equation is x=1+1/(1+x) and the program is: 0= +1=STO 1/MR+1= GO TO STEP 2 OR STOP STEP 3 should work on all calculators.
Read More: ...

how much 3/4 in gravel do i need to cover 1000 square meters i foot thick compacted

Gravel's consistency is around 1800 kg/(m^3) 1000 m^3 = 1800 tonne gravel. 1 feet = 0.3 metre 1800 * 0.3 = 540 You need 540 tonne gravel.
Read More: ...

What are the equal lengths of the remaining 2 sides of the triangle?

Triangle with base line of 6 metres, connecting to 2 equal sides with angles of 10 degrees at the connections. What are the lengths of the remaining 2 sides? To find the hypotenuse of a right triangle, we use the formula c^2 = a^2 + b^2. That is derived from the general forumula c^2 = a^2 + b^2 - (2 * a * b * cos C). It works because the cosine of a 90 degree angle is 0, so the last term is 0, due to multiplying by 0. To solve the problem before us, we need that general formula. We know c, the would-be hypotenuse; it is the 6m base. The other two sides, a and b, are equal length, so we will refer to both lengths as a. Angle C is the angle opposite the base. We are given that there are two 10 degree angles, so angle C must be 160 degrees. c^2 = a^2 + b^2 - (2 * a * b * cos C) 6^2 = a^2 + a^2 - (2 * a * a * cos 160)    Remember, a is the length of each of the other two sides. 36 = (2 * a^2) - (2 * a^2 * cos 160)         We factor out (2 * a^2) 36 = (2 * a^2) * (1 - cos 160)                 Next, divide by (1 - cos 160) 36 / (1 - cos 160) = 2 * a^2                   Now, divide by 2 18 / (1 - cos 160) = a^2                       The final step to simplify is to take the square root sqrt(18 / (1 - cos 160)) = a                   Perform the calculations and you have the length of the other two sides. a = sqrt (18 / (1 - (-0.9397))) = sqrt (18 / 1.9397) a = sqrt (9.2798) = 3.046m Adding the lengths of the two sides gives 6.093, barely longer than the base, but that shows the triangle is extremely short. That's why the two angles at either end of the base are only 10 degrees.
Read More: ...

2/×+2+4/×-5=28/(×+2)(×-5)

If you mean 2/(x+4) + 4/(x-5) = 28/( (x+2)(x-5) ) then: Multiply both sides by (x+4)(x+2)(x-5) 2(x+2)(x-5) + 4(x+4)(x+2) = 28(x+4) x(x^2 - 3x - 10) + 4(x^2 + 6x + 8) = 28x + 112 x^3 - 3x^2 - 10x + 4x^2 + 24x + 32 = 28x + 112 x^3 + x^2 + 14x + 32 = 28x + 112 x^3 + x^2 - 14x - 80 = 0 Checking for nice solutions. . . 80: 2 * 2 * 2 * 2 * 5 What you can make with the prime factors of 80:  2, 4, 5, 8, 10, and a bunch of larger numbers. If you plug 10 in for x, the x^3 makes 1000, much larger than the rest of the equation, so 10 is not a root of x^3 + x^2 - 14x - 80 = 0 2: -96 4: -56 5: 125 + 25 - 70 - 80 = 0 x = 5 is a root (x - 5)( ? ) = x^3 + x^2 - 14x - 80 (x-5)(x^2 + ?x + 16) = x^3 + x^2 - 14x - 80 The -14x is made of 16x + (-5)(?x) -14x = 16x -5?x -14 = 16 - 5? -30 = -5? ? = 6 (x-5)(x^2 + 6x + 16) = x^3 + x^2 - 14x - 80 Checking (x-5)(x^2 + 6x + 16). . . x^3 + 6x^2 + 16x -5x^2 - 30x - 80 x^3 + x^2 - 14x - 80  good (x-5)(x^2 + 6x + 16) factor x^2 + 6x + 16 If you're in pre-algebra, you won't have run into it yet, but there's this thing called the quadratic formula for solving and factoring things with x^2 If you have ax^2 + bx + c = 0 then the values for x are x = (-b +- sqrt(b^2 - 4ac) ) / 2a x^3 + x^2 - 14x - 80 = (x-5)(x^2 + 6x + 16) = 0 a = 1, b = 6, c = 16 x = (-6 +- sqrt(6^2 - 4(1)(16)) ) / 2(1) x = (-6 +- sqrt(36 - 64) ) / 2 x = (-6 +- sqrt(-28)) / 2 You can't take the square root of a negative number, so doesn't factor. This means there is no way to make x^2 + 6x + 16 = 0. That means the only way to make (x-5)(x^2 + 6x + 16) = 0 is if x - 5 = 0, which gives us x = 5 Answer:  x = 5
Read More: ...

i need help with finding the answer for the square root of 34

The only step by step way of finding the square root of a number which doesn't radicalise is to use an arithmetic technique as follows: We know that the answer is close to 6 because 6 squared is 36, so there will be decimals. We write digits in pairs thus: | 34 |•00 | 00 | 00 | 00 The answer is in single digits for each pair, so we will be writing the answer over the top. The decimal point is inserted in front of the digit that will go over the first pair of zeroes. I've put in 4 pairs of zeroes so we'll be working out 4 decimal places only. We know the first digit in the answer is 5, because the answer is a little less than 6, so we write 5 over 34. We write the square of 5, i.e., 25, under 34 and subtract it: ..........5...• 8.....3.....0.....9 ...... | 34 |•00 | 00 | 00 | 00 .........25 108 |...900 ...........864 1163 |...3600 .............3489 ................11100 116609 |..1110000 ................1049481 ....................60519 I'm using dots to space out and align the working so that you can see what I'm doing. Now we double 5 to make 10 and we need to guess what digit should follow 10 so that when we multiply by the digit we get a number which is smaller than or equal to the remainder so far, 900. The digit we need to add is 8, so we write 108 and multiply by 8=864, which is a little less than 900. We subtract 864 from 900 leaving 36 and we pull down another pair of zeroes. We write 8 next to the decimal point, so now we have 5.8. The next step is to double the answer we have so far ignoring the decimal point, so we have 116, and again we need to put a digit on the end of this and multiply by the same digit so that the product is as close to 3600 as we can get without exceeding it. Let's guess 3, so we have 1163*3=3489 (note that 4 would be too big). The remainder is 111 and we bring down the next pair of zeroes to make 11100. We carry on. Double the answer so far=1166. What digit are we going to add this time? The smallest is 1, but 11661 is bigger than the remainder 11100, so we have to put zero in the answer and bring down the next pair of zeroes. Double the answer 11660. Now we can add a digit, which is going to be high, so we'll pick 9 and multiply it to give 116609*9=1049481. We could carry on repeating the same process, bringing down pairs of zeroes as necessary. There are other ways of finding square roots, but I find this one fairly straightforward and it doesn't require a calculator. I think this method is based on Newton's method.
Read More: ...

make two magical square with single digit

3 x 3 MAGIC SQUARE SOLUTIONS Represent square using letters: A B C D E F G H I A+B+C=S=D+E+F=G+H+I; A+B+C+D+E+F+G+H+I=3S. A+E+I=B+E+H=C+E+G=D+E+F=S (A+B+C+D+E+F+G+H+I)+3E=4S; 3S+3E=4S, E=S/3. A+E+I=S, I=S-E-A, I=2S/3-A. H=S-E-B, H=2S/3-B. C=S-(A+B). G=2S/3-C=2S/3-S+(A+B), G=A+B-S/3. D+G=B+C=B+S-(A+B)=S-A; D=S-A-G=S-A-A-B+S/3, D=4S/3-(2A+B). F=2S/3-D=2S/3-4S/3+2A+B, F=2A+B-2S/3. Completed square:           A            B             S-(A+B) 4S/3-(2A+B)    S/3    2A+B-2S/3    A+B-S/3    2S/3-B      2S/3-A So A and B are arbitrary; S must be a multiple of 3 if square is to be whole numbers only. EXAMPLE: A=1, B=5, S=18:   1  5  12 17  6  -5   0  7  11 Single digits can be 1 to 9 (sum=45) or 0 to 8 (sum=36). The common sum is 45/3=15 or 36/3=12. In one case the middle digit is 5 (15/3)  and in the other it's 4 (12/3). In the first case, 5 must be in the middle of the square, and we need to see where 9 fits in. The common sum is 15 so 15-9=6 and the other two numbers must be (1,5) or (2,4). This tells us that 9 can only participate in two sums and therefore it must be in the middle of a side with 2 and 4 on either side of it. So B=9 and A=2. 2 9 4 7 5 3 6 1 8 is a solution. In the case for 0-8 we simply subtract 1 from each square: 1 8 3 6 4 2 5 0 7 and we can reorientate this: 7 2 3 0 4 8 5 6 1 There we have it: two solutions. 
Read More: ...

Tips for a great answer:

- Provide details, support with references or personal experience .
- If you need clarification, ask it in the comment box .
- It's 100% free, no registration required.
next Question || Previos Question
  • Start your question with What, Why, How, When, etc. and end with a "?"
  • Be clear and specific
  • Use proper spelling and grammar
all rights reserved to the respective owners || www.math-problems-solved.com || Terms of Use || Contact || Privacy Policy
Load time: 0.3159 seconds