Guide :

108 metres squared carries 0.5 tonnes. How much does 67.5 square centimetres?

A stage of 12 x 9 (108 metres squared) metres has a deck loading of 0.5 tonnes, what is the deck loading of the stage scaled down to 30 x 22.5 centimetres (67.5 centimetres squared)?

Research, Knowledge and Information :

3 Simple Ways to Calculate Square Meters - wikiHow

How to Calculate Square Meters. ... Since 1 square foot = 0.093 square meters, ... 67% of people told us that this article helped them.

5 square metres - Math Central

an area of 5 square metres and an area of 5 m 2 (5 metres squared) mean exactly the same thing. ... The word square or squared refers to the units and not the shape.

Square Meters to Square Centimeters conversion

Square Meters to Square Centimeters. Bookmark Page Square Centimeters to Square Meters (Swap Units) Format Accuracy Note ... Square Centimeters; 0 m ...

CHAPTER 1 - BASIC TERMS AND CALCULATIONS

... BASIC TERMS AND CALCULATIONS. ... The surface of these triangles is expressed in square centimetres ... A = 0.5 x (108 cm + 16 cm) ...

Convert metric tonnes to tons - Convert Units - Measurement ...

Convert metric tonnes to tons ... equal to 0.001 metric tonnes, or 0.00110231131092 ... 100 kg, US fluid ounce, 6'3", 10 stone 4, cubic cm, metres squared ...

Square Feet to Square Centimeters - Metric Conversion charts ...

Square Feet to Square Centimeters. ... 20438.67 cm ²: 23 ft²: 21367.70 cm² ... In metric terms a square foot is a square with sides 0.3048 metres in length.

How do I convert meters to square meters? | Reference.com

How do I convert meters to square meters? A: ... Four millimeters is equal to 5/32 inch, 0.4 centimeters, or 0.004 meters. There are 25.4 millimeters in one inch.

Aggregate Calculator gravel stone chippings path driveway

Cloburn Quarry Aggregate Calculator ... one tonne will cover 14 square metres. ... Compacted Firechip weighs 2 tonnes per cubic metre.

Calculating gravel tonnage, cubes, and sand and earth.

... What area do I need? How much coverage area is a square ... How much does a ... which does do the math/conversions of US Tons and Metric tonnes ...

Online Conversion - Area calculator

Area Calculator Enter the Length ... Area in Square Feet: Area in Square Meters . Did you find us useful? Please consider supporting the site with a small donation.

108 metres squared carries 0.5 tonnes. How much does 67.5 square centimetres?

??????????????? "tonnes" ???????????????? ??????????? "metres" ???????? ??????? "108 metres squared ????? du yu meen 108 sumthun or iz zat spozed tu be 108^2 ???????????

HELP ME!!!!!!!!!!!! I'M STUPID

1. maebee yu luv tu be frustrated, thats wot puter is for 2. ?? "chook pen" ??, wot du chook look like? 3. 15&50=750, not 800 4. I take it, yu wanna find biggest area yu kan get with 80 meters for 3 sides me no anser: square...eech side=80/3, area=711.1111111... 5. yu don trust me? length+2*wide=80, so leng=80-2*wide area=length*wide=wide*(80-2wide) =80wide-2*wide^2 tu find max or min, take derivativ...80-4wide & set it tu 0...4(20-wide)=0 or wide=20, leng=40, area=800 the mistreeus math gremlins hit agin

How to Find Square Root

98=49*2, so sqrt(98)=sqrt(49)*sqrt(2)=7sqrt(2)=7*1.4142=9.8994 approx. There's another way using the binomial theorem. 98=100-2=100(1-0.02). sqrt(100)=10 so sqrt(98)=10(1-0.02)^(1/2) because square root is the same as power 1/2. (1+x)^n expands to 1+nx+(n(n-1)/1*2)x^2+(n(n-1)(n-2)/1*2*3)x^3+... Putting n=1/2 and  x=-0.02, we get sqrt(98)=10(1-0.02)^(1/2)=10[1-(1/2)0.02+((1/2)(-1/2)/2)0.0004+...]. This gives us: 10(1-0.01-0.00005+...)=10*0.98995=9.8995. A third method is to use an iterative process, which means you keep repeating the same action over and over again. Look at this: x=10-(2/(10+x)). If we solve for x we get x=sqrt(98); but we're going to find x in an iterative way. Start with x=0 and work out the right hand side: 10-2/10=9.8. This gives us a new value for x, 9.8, which we feed back into the right hand side: 10-(2/(10+9.8))=10-2/19.8=9.8989..., giving us another value for x, 9.8989... which we feed back into the right hand side: 10-(2/(10+9.8989...))=9.89949..., giving us yet another value for x and so on. Very quickly we build up accuracy with each x. You can do this on a calculator, a basic one that doesn't even have square roots, using the memory to hold values for you. Here's a very simple program, where STO means store in memory (if your calculator doesn't have STO use MC (memory clear) followed by M+ (add to memory)); MR means read memory (the steps show what calculator keys to press in order; / may be ÷ on your calculator): 0= +10=STO 10-2/MR= GO TO STEP 2 OR STOP (display should show the answer for sqrt(98)) Note: In STEP 3 the division must be carried out before subtracting from 10, otherwise you get the wrong answer. If your calculator doesn't do this you need to replace STEP 3 with: 0-2=/MR=+10= You should only have to go round the loop a few times before you get a really accurate result. To find the square root of 2 directly the iteration equation is x=1+1/(1+x) and the program is: 0= +1=STO 1/MR+1= GO TO STEP 2 OR STOP STEP 3 should work on all calculators.

how much 3/4 in gravel do i need to cover 1000 square meters i foot thick compacted

Gravel's consistency is around 1800 kg/(m^3) 1000 m^3 = 1800 tonne gravel. 1 feet = 0.3 metre 1800 * 0.3 = 540 You need 540 tonne gravel.

What are the equal lengths of the remaining 2 sides of the triangle?

Triangle with base line of 6 metres, connecting to 2 equal sides with angles of 10 degrees at the connections. What are the lengths of the remaining 2 sides? To find the hypotenuse of a right triangle, we use the formula c^2 = a^2 + b^2. That is derived from the general forumula c^2 = a^2 + b^2 - (2 * a * b * cos C). It works because the cosine of a 90 degree angle is 0, so the last term is 0, due to multiplying by 0. To solve the problem before us, we need that general formula. We know c, the would-be hypotenuse; it is the 6m base. The other two sides, a and b, are equal length, so we will refer to both lengths as a. Angle C is the angle opposite the base. We are given that there are two 10 degree angles, so angle C must be 160 degrees. c^2 = a^2 + b^2 - (2 * a * b * cos C) 6^2 = a^2 + a^2 - (2 * a * a * cos 160)    Remember, a is the length of each of the other two sides. 36 = (2 * a^2) - (2 * a^2 * cos 160)         We factor out (2 * a^2) 36 = (2 * a^2) * (1 - cos 160)                 Next, divide by (1 - cos 160) 36 / (1 - cos 160) = 2 * a^2                   Now, divide by 2 18 / (1 - cos 160) = a^2                       The final step to simplify is to take the square root sqrt(18 / (1 - cos 160)) = a                   Perform the calculations and you have the length of the other two sides. a = sqrt (18 / (1 - (-0.9397))) = sqrt (18 / 1.9397) a = sqrt (9.2798) = 3.046m Adding the lengths of the two sides gives 6.093, barely longer than the base, but that shows the triangle is extremely short. That's why the two angles at either end of the base are only 10 degrees.

2/×+2+4/×-5=28/(×+2)(×-5)

If you mean 2/(x+4) + 4/(x-5) = 28/( (x+2)(x-5) ) then: Multiply both sides by (x+4)(x+2)(x-5) 2(x+2)(x-5) + 4(x+4)(x+2) = 28(x+4) x(x^2 - 3x - 10) + 4(x^2 + 6x + 8) = 28x + 112 x^3 - 3x^2 - 10x + 4x^2 + 24x + 32 = 28x + 112 x^3 + x^2 + 14x + 32 = 28x + 112 x^3 + x^2 - 14x - 80 = 0 Checking for nice solutions. . . 80: 2 * 2 * 2 * 2 * 5 What you can make with the prime factors of 80:  2, 4, 5, 8, 10, and a bunch of larger numbers. If you plug 10 in for x, the x^3 makes 1000, much larger than the rest of the equation, so 10 is not a root of x^3 + x^2 - 14x - 80 = 0 2: -96 4: -56 5: 125 + 25 - 70 - 80 = 0 x = 5 is a root (x - 5)( ? ) = x^3 + x^2 - 14x - 80 (x-5)(x^2 + ?x + 16) = x^3 + x^2 - 14x - 80 The -14x is made of 16x + (-5)(?x) -14x = 16x -5?x -14 = 16 - 5? -30 = -5? ? = 6 (x-5)(x^2 + 6x + 16) = x^3 + x^2 - 14x - 80 Checking (x-5)(x^2 + 6x + 16). . . x^3 + 6x^2 + 16x -5x^2 - 30x - 80 x^3 + x^2 - 14x - 80  good (x-5)(x^2 + 6x + 16) factor x^2 + 6x + 16 If you're in pre-algebra, you won't have run into it yet, but there's this thing called the quadratic formula for solving and factoring things with x^2 If you have ax^2 + bx + c = 0 then the values for x are x = (-b +- sqrt(b^2 - 4ac) ) / 2a x^3 + x^2 - 14x - 80 = (x-5)(x^2 + 6x + 16) = 0 a = 1, b = 6, c = 16 x = (-6 +- sqrt(6^2 - 4(1)(16)) ) / 2(1) x = (-6 +- sqrt(36 - 64) ) / 2 x = (-6 +- sqrt(-28)) / 2 You can't take the square root of a negative number, so doesn't factor. This means there is no way to make x^2 + 6x + 16 = 0. That means the only way to make (x-5)(x^2 + 6x + 16) = 0 is if x - 5 = 0, which gives us x = 5 Answer:  x = 5

make two magical square with single digit

3 x 3 MAGIC SQUARE SOLUTIONS Represent square using letters: A B C D E F G H I A+B+C=S=D+E+F=G+H+I; A+B+C+D+E+F+G+H+I=3S. A+E+I=B+E+H=C+E+G=D+E+F=S (A+B+C+D+E+F+G+H+I)+3E=4S; 3S+3E=4S, E=S/3. A+E+I=S, I=S-E-A, I=2S/3-A. H=S-E-B, H=2S/3-B. C=S-(A+B). G=2S/3-C=2S/3-S+(A+B), G=A+B-S/3. D+G=B+C=B+S-(A+B)=S-A; D=S-A-G=S-A-A-B+S/3, D=4S/3-(2A+B). F=2S/3-D=2S/3-4S/3+2A+B, F=2A+B-2S/3. Completed square:           A            B             S-(A+B) 4S/3-(2A+B)    S/3    2A+B-2S/3    A+B-S/3    2S/3-B      2S/3-A So A and B are arbitrary; S must be a multiple of 3 if square is to be whole numbers only. EXAMPLE: A=1, B=5, S=18:   1  5  12 17  6  -5   0  7  11 Single digits can be 1 to 9 (sum=45) or 0 to 8 (sum=36). The common sum is 45/3=15 or 36/3=12. In one case the middle digit is 5 (15/3)  and in the other it's 4 (12/3). In the first case, 5 must be in the middle of the square, and we need to see where 9 fits in. The common sum is 15 so 15-9=6 and the other two numbers must be (1,5) or (2,4). This tells us that 9 can only participate in two sums and therefore it must be in the middle of a side with 2 and 4 on either side of it. So B=9 and A=2. 2 9 4 7 5 3 6 1 8 is a solution. In the case for 0-8 we simply subtract 1 from each square: 1 8 3 6 4 2 5 0 7 and we can reorientate this: 7 2 3 0 4 8 5 6 1 There we have it: two solutions.

- Provide details, support with references or personal experience .
- If you need clarification, ask it in the comment box .
- It's 100% free, no registration required.
next Question || Previos Question
• Start your question with What, Why, How, When, etc. and end with a "?"
• Be clear and specific
• Use proper spelling and grammar