Guide :

AC=3x+3, AB=-1+2x, BC=11 Find x

Please i need help can someone show me the steps of showing the work because i don't understand how to solve.

Research, Knowledge and Information :


SOLUTION: B is between A and C. AB = 2x - 3, BC = 3x + 1, AC ...


AC = AB + BC (7X-8) = (2X-3) + (3X+1) Substitute the values of X=3 and see that LHS = RHS of the equation. let us do that, 7*3-8 = 2*3-3 + 3*3+1 21-8 = 6-3+9+1
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AC= 3X + 3, AB= -1+2 X , and BC=11 find X



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... and BC=11 find X ... More. Spanish Economics Geography Vocabulary French Accounting ... AC= 3X + 3, AB= -1+2 X , and BC=11 find X – Umisays9. Umisays9 ...
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The Segment Addition Postulate Date Period


The Segment Addition Postulate Date_____ Period____ Find the ... x. 11) AC = x , AB = x, ... AB = x, BC = , AC = ...
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B is the midpoint of AC. If Ab= x +5 and BC = 2x-11, find the ...


If Ab= x +5 and BC = 2x-11, find the measure of Ab. - 3450428. 1. ... B is the midpoint of AC. If Ab= x +5 and BC = 2x-11, ... (x + 5) + (2x − 11) = 3x − 6 ...
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Point B is between A and C on segment AC. Use the given ...


Use the given information to write an equation in terms of x. ... Then find AB and BC. AB= 3x; BC= x; AC= 20 AB= 2x-5; BC= 6x; ... 2016-11-22T01:47:16-05:00.
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what are the critical numbers of the equation: 3x^4-8x^3+6x^2

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find and classify all the critical points of the function f(x)=2x^3+3x^2-12x+2

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given px-13+2x+y=0.py-13+x+2y=0 If Tc=x+y find the price and output for each good which will maximize profit shown using the second order condition that profit have a maximum at this point

Price of input, Px=13-2x-y; price of output, Py=13-x-2y; total cost, Tc=x+y. Revenue comes from the sale of the output=y*Py. Variable cost comes from production of the input=x*Px. Let the fixed cost be F, profit P=(revenue)-(total cost of production)= yPy-xPx-F=13y-xy-2y^2-13x+2x^2+xy-F= 13(y-x)-2(y^2-x^2)-F=13(y-x)-2(y-x)(y+x)-F=(y-x)(13-2(y+x))-F, and total cost is cost of production xPx+F=Tc=x+y (given). So 13x-2x^2-xy+F=x+y. From this, 12x-2x^2+F=y(1+x) and y=(2x(6-x)+F)/(1+x). This relates output and input quantities. So, dividing by 1+x: y=2(7-x)+(F-14)/(1+x). Since y>0, F>2x(x-6) and x>6 because F cannot be negative. Px=13-2x-(2x(6-x)+F)/(1+x)=(13+13x-2x-2x^2-12x+2x^2-F)/(1+x)=(13-F-x)/(1+x). Px>0, so F<13-x, and x<13. Now we can see that 62x(x-6), so 00. Therefore, 13-2F-12x+3x^2>0 because Py>0. x^2-4x+(13-2F)/4>0; x^2-4x+4+(13-2F)/4-4>0; (x-2)^2>(3+2F)/4. This implies x>2±sqrt(3/4+F/2)>0 and since we know 6 Read More: ...

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f(x)=6x^2 - 5x + 4 find the slope between x=-2 and x=a

The slope varies according to the derivative, f'(x)=12x-5. At f'(-2) the slope is 12(-2)-5=-29. At f'(-3) it is 12(-3)-5=-41. So the slope varies from point to point. If you need to find the slope between two points, the best you can get is the average, so in this case we would have the average of -29 and -41=-70/2=-35. Negative means a backwards slope (\). Using h as the difference between two values of x we have: f(x)=6x^2-5x+4 and f(x+h)=6(x+h)^2-5(x+h)+4. If we calculate f(x+h)-f(x) we get: 6((x+h)^2-x^2)-5h=6(x+h-x)(x+h+x)-5h=6h(2x+h)-5h=12hx+6h^2-5h. However, h is supposed to be very small so that h^2 can be ignored. If h is 1, for example, it's too big to be ignored so that when we divide through by h, we get 12x+6h-5 instead of 12x-5, the derivative as shown above. Instead of -29 (for x=-2) we would have -29+6h. If h=-1, this becomes -35, which is the average slope.
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