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# write the first quantity as fraction of 2nd quantity a)3 days;the month of january

Math solve to find 2nd quantity

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### Problem of the Month: Fractured Numbers - Inside Mathematics

Problem of the Month Fractured Numbers Page 3 ... and 3 packages of meat. How many days will the dog be fed ... larger fraction, the next natural number ...

### Fraction Concepts - Conceptual Mathematics

Each day when the date is written have a student write out what fraction of the month, ... first: the fraction of the counted number of coins, second: ...

### Calendar Math Worksheets - Super Teacher Worksheets

Answer questions about the January calendar. ... Write an ordinal number for each month given. ... and "Write the date that is fifteen days after May 25."

### Months - Math is Fun

Month Number. Month. In 3 letters ... See the days in each month ... the second King of Rome, added January (for the god Janus) ...

### Math Forum: Ask Dr. Math FAQ: Calendar and Days of the Week

How do I find the day of the week for ... but a normal calendar year is only 365 days. The extra fraction of a ... k is the day of the month. Let's use January ...

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Write the decimal as a fraction or mixed number in ... The graph below shows the experimental probability of a runner finishing in first place (1), in second ...

### Writing Classes and Javadoc - Carnegie Mellon School of ...

... //Scan every earlier month, summing the # of days in that month... for (int m=JANUARY; ... number (fraction) ... 3 on the first die and a 5 on the second) ...

### Fraction (mathematics) - Wikipedia

A mixed number can be converted to an improper fraction as follows: Write the mixed number ... The second fraction, ... as decimal fractions were first used five ...

## Suggested Questions And Answer :

### write the first quantity as fraction of 2nd quantity a)3 days;the month of january

????? yu want 3/31 ???=0.096774193

### i = 0.072/4 how do you simplify the fraction?

Let's consider the monthly contributions. 10 years ago she started paying \$625 to the retirement fund. After another 5 years that initial payment would increase to \$625*(1+0.0384/12)^(15*12). The second month accumulates \$625*(1+0.0384/12)^(15*12-1), one month less than the initial payment. The third month's period of growth will be measured over 15*12-2=178 months. So it continues up to the last payment which will only accumulate a month's interest. The monthly rate is 0.0384/12=0.0032, so the growth factor is 1.0032^p where p is the number of months. Now we can write a series, S, that takes into account the accumulated no interest. Let's use a general expression, where A is the monthly contribution amount, r the monthly rate as a fraction, and p=12n where n is the number of years: S=A(1+r)^p+A(1+r)^(p-1)+A(1+r)^(p-2)+...+A(1+r)^2+A(1+r) S=A(1+r)((1+r)^(p-1)+...+1). This equation contains a geometric progression which can be summed. (1+r)S=A(1+r)((1+r)^p+(1+r)^(p-1)+...+(1+r)^2+(1+r)). So (1+r)S-S=A(1+r)((1+r)^p-1); rS=A(1+r)((1+r)^p-1). This formula can be applied to both parts of this question. a. Same rate applies for the whole 15 years. 0.0032S=625*1.0032(1.0032^180-1)=625*1.0032*0.7773=487.3504, so S=\$152,297. b. 0.0032 applies for ten years: 0.0032S=625*1.0032*(1.0032^120-1)=292.963, so S=\$91,550.94. Now start a new series with A=1000 and r=0.0772/12=0.0064333... or 0.0193/3 and p=60. 0.006433S=1000*1.006433(1.006433^60-1)=472.286, so S=\$73,412.33. However, we're not through yet, because \$91,550.94 continues to earn interest over 5 years at the new rate. This comes to 91550.94*1.006433^60=\$134,512.78. The combined amount is this plus 73,412.33=\$207,925.10 approx. (Approximate figures throughout.)

### HOW TO SOLVE LINEAR EQUQTIONS WITH FIVE UNKNOWN

It's clear that the percentages exceed 100%, so I conclude that the dry matter content includes the crude ingredients, which are supplemented by another ingredient that is not specified. I also conclude that the dry matter content indicates that water is present, because none of the percentages for dry matter are 100%. First, remove water content and recalculate percentages: to do this we divide each percentage of the components by the percentage of dry matter. The result is expressed as a percentage. This enables us to mix the feed on a dry basis.  The adjusted percentages are: CORN: CP: 9.4909%, CF: 2.3812%, CFB: 1.1339% RICE: CP: 13.4427%, CF: 13.7776%, CFB: 8.3150% SBM: CP: 48.0682%, CF: 6.3636%, CFB: 5.1136% WHEAT: CP: 18.5698%, CF: 5.1903%, CFB: 8.5352% COPRA: CP: 20.7792%, CF: 13.2035%, CFB: 12.4459% We also have to adjust the percentages on the required feed: CP: 18.1818%, CF: 4.5455%, CFB: 13.6364% The last letter of each ingredient will be used to signify the fraction of that ingredient needed to make up the required feed (N, E, M, T, A). So we can write: CP REQUIREMENT: 9.4909N+13.4427E+48.0682M+18.5698T+20.7792A=18.1818 CF REQUIREMENT: 2.3812N+13.7776E+6.3636M+5.1903T+13.2035A=4.5455 CFB REQUIREMENT: 1.1339N+8.3150E+5.1136M+8.5352T+12.4459A=13.6364 N+E+M+T+A=1 (The ingredient fractions must add up to 1.) [To show these equations are valid, let's move away from percentages and consider actual amounts in the dry mix. For example, n grams of corn contains 9.4909n/100 grams (0.094909n grams) of crude protein. Similarly for the other ingredients: e grams of rice contains 13.4427e/100 grams (0.134427e grams) of crude protein. When we add together the crude protein contributions for all the ingredients we get the required amount, 18.1818x/100 (0.1818x grams), where x grams is the weight of the dry mix=n+e+m+t+a. So we can multiply through by 100 to leave the percentage numbers; if we divide through by x we get n/x, e/x, etc., and we can replace these by N, E, etc., where these are fractions of the total feed: N=n/x, E=e/x, ... X=x/x=1.] There are five variables but only four equations. The amount of copra is A=1-(N+E+M+T), so the equations can be reduced to omit A: CP REQUIREMENT: 11.2883N+7.3366E-27.2890M+2.2094T=2.5974 CF REQUIREMENT: 10.8222N-0.5741E+6.8398M+8.0132T=8.6580 CFB REQUIREMENT: 11.3120N+4.1308E+7.3323M+3.9107T=-1.1905 This last equation is suspicious because all the values on the left are positive but the value on the right is negative. Therefore at least one assumption in the logic is false. To resolve this difficulty we have to change the requirements to include inequalities. For example, the mix must contain at least a certain amount of an essential ingredient, or no more than a certain amount, as well as exactly a certain amount. We have no guide in the question to make any assumptions. Nevertheless, we'll continue with the solution and see where it leads us. The plan now is to treat T as an independent variable or constant, and to find each of N, E and M in terms of T. T is therefore a parameter from which the other fractions can be derived. We can eliminate M from CP and CF: 6.8398(11.2883N+7.3365E-27.2890M+2.2094T) + 27.2890(10.8223N-0.5714E+6.8398M+8.0132T)=6.8398*2.5974+27.2890*8.6580 77.2104N+50.1808E+15.1122T+295.3277N-15.6668E+218.6706T=17.7658+236.2681 372.5381N+34.5140E+233.7828T=254.0338 And we can similarly eliminate M from CF and CFB: 7.3323(10.8223N-0.5714E+6.8399M+8.0132T) - 6.8398(11.3120N+4.1308E+7.3323M+3.9107T)=7.3323*8.6580+6.8398*1.1905 79.3514N-4.2095E+58.7544T-77.3719N -28.2542E-26.7486T=63.4827+8.1427 1.9795N-32.4637E+32.0059T=71.6253. We now have two equations involving N, E and T, and we can eliminate E between them and so find N in terms of T: 32.4637(372.5381N+34.5140E+233.7828T) + 34.5140(1.9795N-32.4637E+32.0059T)=32.4637*254.0338+34.5140*71.6253, 12162.2997N+8694.1124T=10718.9626, 12162.2997N=10718.9626-8694.1124T, N=0.8813-0.7148T. If we substitute this value of N in 1.9795N-32.4637E+32.0059T=71.6253, we can find E in terms of T: 1.9795(0.8813-0.7148T)-32.4637E+32.0059T=71.6253; 1.7445-1.4149T-32.4637E+32.0059T=71.6253 -32.4637E+30.5910T=69.8808; E=(30.5910T-69.8808)/32.4637, E=0.9423T-2.1526. Substituting for E and N we can find M then A: using the CP requirement equation: 11.2883N+7.3366E-27.2890M+2.2094T=2.5974 11.2883(0.8813-0.7148T)+7.3366(0.9423T-2.1526)-27.2890M+2.2094T=2.5974, 9.9484-8.0689T+6.9133T-15.7928-27.2890M+2.2094T=2.5974, 1.0538T-27.2890M=8.4418, M=(1.0538T-8.4418)/27.2890=0.0386T-0.3093. We now have N, E and M in terms of T. We can find A from A=1-(N+E+M+T): A=1-(0.8813-0.7148T+0.9423T-2.1526+0.0386T-0.3093+T)=2.5806-1.2661T. All the ingredients have now been found in terms of T (wheat). These values are based on equality in the ingredient equations.  Summary N=0.8813-0.7148T, E=0.9423T-2.1526, M=0.0386T-0.3093, A=2.5806-1.2661T. These are all supposed to be positive fractions<1, and clearly they are not! This implies that the exact amounts required in the mix cannot be achieved. I've checked the arithmetic and logic fully and I can find no errors, so it does not appear to be possible to mix the desired quantities of the essential ingredients. It may be possible to get the right quantity of one particular ingredient at the expense of the others, or with an excess of at least one of the other ingredients. An excess could be as undesirable as a deficiency.

### An amount of 10 000 was invested in a special savings account

15% per annum is 3.75% per quarter. 15 May is included in the 2nd quarter of the year, an even period. At the end of the quarter 10000 would accumulate a whole quarter's interest: 375, making the total savings 10375. This is the starting amount for July, so by October, if the simple interest is calculated on the original 10000 a further 375 would accumulate making the savings 10750. October is the start of the last quarter and the 7-month period ends in December. 10750 would accumulate by compound interest, becoming 11153.125 at the end of the quarter. So the interest is 1153.13. If compound interest is applied for the whole 7 months, then taking this to be 3 quarter periods, the interest is 1167.71. If simple interest is applied for 7 months the interest is 875, based on 7/12*0.15*10000.

### of tgere is 4 mondays and 4 fridays what day is january 1

In a month of 31 days there will be 4 dates where the same day of the week falls on that date if d+28>31, so d>3 where d is the earliest date in the month. So, for example, if d=4, then the dates are 4, 11, 18, 25. Also, d<8, because if d=8, then there would be an earlier date, d=1. Therefore, 3 Read More: ...

### Describe two methods for converting a mixed number to a decimal

Represent the mixed number as N a/b where N is the whole number part and a over b is the fraction. Method 1 Write down N and follow it by a decimal point. Now you need to divide b into a, but because a is smaller than b you need to write a, a decimal point, and as many zeroes as you wish for accuracy. Some decimals terminate (divide exactly) and some recur (a pattern repeats indefinitely). Example: a=3 and b=4 so we have 3/4. Divide b into 3.0000... Treat 3.0 as 30 and divide by 4, putting the answer immediately after the decimal point. So we have .7 and 2 over making 20 with the next zero. Now divide 4 into 20 and write the result after the 7: .75. This is an exact division so we don't need to go any further. Let's say N was 5 so the mixed number is 5 3/4. We've already written N as 5. so now we continue after the decimal point with what we just calculated giving us 5.75. Another example: 7 5/6. We write 7. first. Divide 6 into 5.0000... and we get .8333. This is a recurring decimal. We keep getting the same carryover. Now we attach the whole number part to get 7.83333... Another example: 2 1/16. We write 2. first. But be careful in the next part: 16 divided into 1.0000... 16 doesn't go into 10 so we write .0 as our first number. Then we divide 16 into 100. This is 6 remainder 4. So we have .06. 16 into 40 goes 2 remainder 8. That gives us .062. Finally 16 into 80 is exactly 5 so we have .0625. Attach this to the whole number: 2.0625. Method 2 For N a/b we make the improper fraction b*N+a over b, then divide by b. Example: 2 1/16: 16*2+1=33. So we divide 33.000.... by 16. We end up with 2.0625. Example: 7 5/6: divide 6*7+5=47 by 6. We end up with 7.83333...

### Susan is writing a linear equation for the cost of her cell phone plan.

We assume a linear relationship between the cost, y, and the time, x, in the form: y=ax+b, where a is the charge rate in \$ per minute and b is a standing fixed charge. So we have two equations: 19.41=52a+b and 45.65=380a+b. Subtract the first eqn from the second: 328a=26.24, so a=26.24/328=\$0.08 or 8 cents per minute (answer for part A). We can find b by substituting a=0.08 in the first equation: 19.41=0.08*52+b, so b=19.41-4.16=\$15.25. Susan's plan (answer to part B) is based on y=0.08x+15.25. Check that the second eqn fits: 45.65=0.08*380+15.25.

### what is 9/13 6/8 3/5 7/10 5/7 from least to greatest

One way to do this is to use the lowest common denominator of the factions. First, though, 6/8 can be reduced to 3/4. Since the LCD of 4, 5 and 10 is 20 and there are no other common factors in the other denominators, the LCD=1820 (=20*13*7). We then multiply each fraction by 1820, and write down the answers: 1260, 1365, 1092, 1274, 1300. These are easy to put in order: 1092, 1260, 1274, 1300, 1365. We now arrange the associated fractions in the same order: 3/5, 9/13, 7/10, 5/7, 6/8 (3/4). [When we multiply each fraction by 1820, we divide the denominator into 1820 and multiply the result by the numerator.] Another way is to convert each fraction into decimal and compare decimals. We only need a couple of places of decimals to make the comparisons: 0.69, 0.75, 0.60, 0.70, 0.71. This is the same as comparing: 69, 75, 60, 70, 71. The order is 60, 69, 70, 71, 75. An easy way to organise the fractions is to write the fractions on separate pieces of paper. On the back of each piece of paper write the number you are going to use in place of the fraction. Now you can easily arrange the papers in order according to the order of the replacement numbers. All you have to do then is to turn the papers over to see what the fraction order is.

### why in februry there 28 or 29 days and other month 30 or 31?

Please dont put these kinds of questions here anymore but here is the answer i copied it off of an amazon ask.com web sit which you could have just googled for./ ********************************************************************************** To meticulous persons such as ourselves, having the calendar run out in December and not pick up again until March probably seems like a pretty casual approach to timekeeping. However, we must realize that 3,000 years ago, not a helluva lot happened between December and March. The Romans at the time were an agricultural people, and the main purpose of the calendar was to govern the cycle of planting and harvesting. February has always had 28 days, going back to the 8th century BC, when a Roman king by the name of Numa Pompilius established the basic Roman calendar. Before Numa was on the job the calendar covered only ten months, March through December. December, as you may know, roughly translates from Latin as "tenth." July was originally called Quintilis, "fifth," Sextilis was sixth, September was seventh, and so on. Numa, however, was a real go-getter-type guy, and when he got to be in charge of things, he decided it was going to look pretty stupid if the Romans gave the world a calendar that somehow overlooked one-sixth of the year. So he decided that a year would have 355 days--still a bit off the mark, admittedly, but definitely a step in the right direction. Three hundred fifty five days was the approximate length of 12 lunar cycles, with lots of leap days thrown in to keep the calendar lined up with the seasons. Numa also added two new months, January and February, to the end of the year. Since the Romans thought even numbers were unlucky, he made seven of the months 29 days long, and four months 31 days long. ********************************************************************************** But Numa needed one short, even-numbered month to make the number of days work out to 355. February got elected. It was the last month of the year (January didn't become the first month until centuries later), it was in the middle of winter, and presumably, if there had to be an unlucky month, better to make it a short one. ********************************************************************************** Many years later, Julius Caesar reorganized the calendar yet again, giving it 365 days. Some say he made February 29 days long, 30 in leap year, and that Augustus Caesar later pilfered a day; others say Julius just kept it at 28. None of this changes the underlying truth: February is so short mainly because it was the month nobody liked much.