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what is 3/50 as a decimal?

  Write  3 50  as a decimal number.  

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What is 3/50 as a decimal? - Research Maniacs


What is 3/50 as a decimal? Here we calculate what 3/50 is as a decimal. Research Maniacs ... To get 3/50 converted to decimal, you simply divide 3 by 50.
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What is 3/50 as a decimal? | Socratic


3/50 = 6/100 = 0.06 The first step is to make the ... What is 3/50 as a decimal? ... #3/50 xx 2/2 = 6/100# Now write as a decimal with 2 decimal places because ...
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What is 3 over 50 into a decimal - Answers.com


3/50 = 6/100 = 0.06. Go. Log In Sign Up. ... Answers.com ® WikiAnswers ® Categories Science Math and Arithmetic What is 3 over 50 into a decimal? What would you ...
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Decimals - Math is Fun


and the "3" is in the ... The decimal point is the most important ... Decimals Index Decimal Worksheets Powers of 10 Rounding Numbers Adding Decimals Subtracting ...
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What is 3.50/35 in decimal form? - Brainly.com


What is 3.50/35 in decimal form? 2. Ask for details ; Follow; Report; by Deleted account 12/08/2015. Log in to add a comment Hi! We've verified an answer to this ...
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What is 3 over 5 as a decimal? | Reference.com


Three-fifths, otherwise written as 3/5, can also be written in decimal form as 0.6. ... What is 3 over 5 as a decimal? A: Quick Answer. Three-fifths, ...
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Decimal - Wikipedia


... (e.g. 3.14159265...). Decimal fractions have terminating decimal representations and other fractions ... 1000) and secondary symbols for half these values (5, 50 ...
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Decimal, Fractions, and Percentage - mathsisfun.com


1 / 3: 50%: 0.5: 1 / 2: 75%: 0.75: 3 / 4: 80%: 0.8: 4 / 5: 90%: 0.9: 9 / 10: 99%: 0.99: 99 / 100: 100%: 1 : 125%: 1.25: 5 / 4: ... The easiest way to divide by 100 is ...
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Suggested Questions And Answer :


10 vedic maths rules for class IX

2 instead of 5: 34/5 can be calculated by multiplying 34 by 2 instead of dividing by 5. 34*2=68. We just move the decimal point one place to the left: 34/5=6.8. 124/5=24.8 because 124*2=248. Move the decimal point: 248 becomes 24.8. 34*5 is the same as 34/2=17 but we add a zero to make 17 into 170. 73*5 is the same as 73/2=36.5 then move the decimal point one place to the right (or add zero): 36.5 becomes 365=73*5. So we only need to know how to multiply and divide by 2 to divide and multiply by 5. We just move the decimal point. Divisibility by 9 or remainder after dividing by 9. All multiples of 9 contain digits which added together give 9. As we add the digits together, each time the result goes over 9 we add the digits of the result together and use that result and continue in this way up to the last digit. Is 12345 divisible by 9? Add the digits together 1+2+3=6. When we add 4 we get 10, so we add 1 and zero=1 then we add 5 to get 6. The number is not exactly divisible by 9, but the remainder is 6. We can also ignore any 9's in the number. Now try 67959. We can ignore the two 9's. 6+7=13, and 1+3=4; 4+5=9, so 67959 is divisible by 9. Multiplying by 11. Example: 132435*11. We write down the first and last digits 1 ... 5. Now we add the digits in pairs from the left a digit step at a time. So 1+3=4; 3+2=5: 2+4=6; 4+3=7; 3+5=8. Write these new digits between 1 and 5 and we get 1456785=132435*11. But we had no carryovers here. Now try 864753*11. Write down the first and last digits: 8 ... 3. 8+6=14, so we cross out the 8 and replace it with 8+1=9, giving us 94 ... 3. Next pair: 6+4=10. Again we go over 10 so we cross out 4 and make it 5. Now we have 950 ... 3. 4+7=11, so we have 9511 ... 3. 7+5=12, giving us 95122 ... 3; 5+3=8, giving us the final result 9512283.  Divisibility by 11. We add alternate digits and then we add the digits we missed. Subtract one sum from the other and if the result is zero the original number was divisible by 11. Example: 1456785. 1 5 7 5 make up one set of alternate digits and the other set is 4 6 8. 1+5+7=13. We drop the ten and keep 3 in mind to add to 5 to give us 8. Now 4 6 8: 4+6=10, drop the ten and add 0 to 8 to give us 8 (or ignore the zero). 8-8=0 so 11 divides into 1456785. Now 9512283: set 1 is 9 1 2 3 and set 2 is 5 2 8; 9+1=0 (when we drop the ten); 2+3=5; set 1 result is 5; 5+2+8=5 after dropping the ten, and 5-5=0 so 9512283 is divisible by 11. Nines remainder for checking arithmetic. We can check the result of addition, subtraction, multiplication and (carefully) division. Using Method 2 above we can reduce operands to a single digit. Take the following piece of arithmetic: 17*56-19*45+27*84. We'll assume we have carried out this sum and arrived at an answer 2365. We reduce each number to a single digit using Method 2: 8*2-1*9+9*3. 9's have no effect so we can replace 9's by 0's: 8*2 is all that remains. 8*2=16 and 1+6=7. This tells us that the result must reduce to 7 when we apply Method 2: 2+3+6=11; 1+1=2 and 2+5=7. So, although we can't be sure we have the right answer we certainly don't have the wrong answer because we arrived at the number 7 for the operands and the result. For division we simply use the fact that a/b=c+r where c is the quotient and r is the remainder. We can write this as a=b*c+r and then apply Method 2, as long as we have an actual remainder and not a decimal or fraction. Divisibility by 3. This is similar to Method 2. We reduce a number to a single digit. If this digit is 3, 6 or 9 (in other words, divisible by 3) then the whole number is divisible by 3. Divisibility by 6. This is similar to Method 6 but we also need the last digit of the original number to be even (0, 2, 4, 6 or 8). Divisibility by 4. If 4 divides into the last two digits of a number then the whole number is divisible by 4. Using 4 or 2 times 2 instead of 25 for multiplication and division. 469/25=469*4/100=1876/100=18.76. 538*25=538*100/4=134.5*100=13450. We could also double twice: 469*2=938, 938*2=1876, then divide by 100 (shift the decimal point two places to the left). And we can divide by 2 twice: 538/2=269, 269/2=134.5 then multiply by 100 (shift the decimal point two places left or add zeroes). Divisibility by 8. If 8 divides into the last three digits of a number then the whole number is divisible by 8. Using 8 or 2 times 2 times 2 instead of 125 for multiplication and division. Similar to Method 9, using 125=1000/8. Using addition instead of subtraction. 457-178. Complement 178: 821 and add: 457+821=1278, now reduce the thousands digit by 1 and add it to the units: 278+1=279; 457-178=279. Example: 1792-897. First match the length of 897 to 1792 be prefixing a zero: 0897; complement this: 9102. 1792+9102=1894. Reduce the thousands digit by 1 and add to the result: 894+1=895. Example: 14703-2849. 2849 becomes 02849, then complements to 97150. 14703+97150=111853; reduce the ten-thousands digit by 1 and and add to the result: 11854. Squaring numbers ending in 5. Example: 75^2. Start by writing the last two digits, which are always 25. Take the 7 and multiply by 1 more than 7, which is 8, so we get 56. Place this before the 25: 5625 is the square of 75. The square of 25 is ...25, preceded by 2*3=6, so we get 625. All numbers ending in 0 or 5 are exactly divisible by 5 (see also Method 1). All numbers ending in zero are exactly divisible by 10. All numbers ending in 00, 25, 50 or 75 are divisible by 25. Divisibility by 7. Example: is 2401 divisible by 7? Starting from the left with a pair of digits we multiply the first digit by 3 and add the second to it: 24: 3*2+4=10; now we repeat the process because we have 2 digits: 3*1+0=3. We take this single digit and the one following 24, which is a zero: 3*3+0=9. When we get a single digit 7, 8 or 9 we simply subtract 7 from it: in this case we had 9 so 9-7=2 and the single digit is now 2. Finally in this example we bring in the last digit: 3*2+1=7, but 7 is reduced to 0. This tells us the remainder after dividing 2401 by 7 is zero, so 2401 is divisible by 7. Another example: 1378. 3*1+3=6; 3*6=18 before adding the next digit, 7 (we can reduce this to a single digit first): 3*1+8=3*1+1=4; now add the 7: 4+7=4+0=4;  3*4=12; 3*1+2+8=5+1=6, so 6 is the remainder after dividing 1378 by 7.  See also my solution to: http://www.mathhomeworkanswers.org/72132/addition-using-vedic-maths?show=72132#q72132
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how do you work out: 3+7=....(finite 5)

Not sure what you're asking here. Are you trying to sum 3 and 7 to a different base? In decimal the answer of course is 10. 10 means the base as a number to that base. If the base was 5, 10 would be the number 5 itself. If the base was 2, 10 would be the number 2. In base 5 we would count 0 1 2 3 4 10 11 12 13 14 20, corresponding to the numbers 0 to 10 in decimal. In base 5 we only use digits 0 to 4; in binary (base 2) we only have digits 0 and 1. In base 10 (decimal) we only have digits 0 to 9. In base 16 (hexadecimal) we have to invent symbols for digits we don't have: there's no single symbol after 9, so we use letters A to F to represent what we would write in decimal as 10 to 15. 10 in base 16 is the same as 16 in base 10. What's 16 in base 5? Well it's 3 times the base plus 1: 31. What is 16 in binary (base 2)? 10 stands for 2; 100 stands for 4 (2 squared); 1000 stands for 8 (2 cubed); 10000 stands for 16 (2^4). 3+7=20 in base 5 and the sum totally in base 5 would be 3+12=20.
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53 divided 898 ??

do you need a  decimal quotient? or fraction? if decimal:     53  /  898  =   0.0590200... 1st: add a decimal point to 53 then 0... put the point above in the quotient 2nd: divide as 530 by 898   , the quotient is 0 3rd: place another 0 in 530 it becomes 5300, which when divided by 898 = 5 4th: multiply 5 by 898 = 4490, subract this from 5300 = 810, then put another 0. 5th: 8100 divided by 898 = 9 , multiply 9 by 898 = 8082, subtract this from 8100.. 6th: continue putting 0 to the difference then divide again...
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what is 6.4 - y = 6 2/5

If I understand the problem correctly you need to convert the fraction into a decimal or the decimal into a fraction. Let's convert 6 and 2 fifths into a decimal by dividing 2 by 5 We get 6.4 - y = 6.4 Then get y alone by subtracting 6.4 from both sides. -y = 0 Then you  multiply both sides by (- ) and you get y = 0 because anything times 0 = 0 your answer is y=0
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Here I will give you more about percents. View this and try to answer it please. :)

This time the grid has 50 squares. 25 are shaded. shaded/grid size=25/50=1/2. As a ratio this is 1:2, as a fraction it is 1/2; as a decimal, we count how many digits there are in the denominator and then we write 1 followed by as many zeroes: so, there is one digit in the numerator, giving us 10, which we multiply by 1/2, to give us 5. That means the equivalent of 1/2 is 5/10 or 5 tenths. The first decimal place after the decimal point is the tenths position. 0.1 means 1 tenth. So 5 tenths is 5 times as big: 0.5. 1/2 is 0.5 as a decimal. As a per cent (which means out of 100), we multiply 1/2 by 100=50, so 1/2 is 50%. Another way of converting 1/2 into a decimal is to divide 2 into 1 like this: .....0 . 5 2 | 1 . 0 (treat this as 10 but leave the decimal points lined up)
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What is the exact value (not decimal) of the sin of a 40 degree angle of a right triangle?

sin3A=sin(2A+A)=sin2AcosA+cos2AsinA=2sinAcos^2A+sinA(1-2sin^2A)=  2sinA(1-sin^2A)+sinA-2sin^3A=2sinA-2sin^3A+sinA-2sin^3A=3sinA-4sin^3A.  If A=40, sin120=3sin40-4sin^3(40)=sqrt(3)/2. Put x=sin40: 3x-4x^3-sqrt(3)/2=0 or 8x^3-6x+sqrt(3)=0, which reduces to: x^3-(3/4)x+sqrt(3)/8=0, so one solution of this cubic will be sin40. The cubic will also give sin20 as a solution, because sin120=sin60=sin(3*20)=sqrt(3)/2, and sin(-80) (=-sin80), because sin(-240)=sqrt(3)/2 (quadrant II), the same as sin120. sin40 is the most positive solution, of course, and it is an irrational number so cannot be represented as a fraction a/b where a and b are integers. The cubic factorises: (x-sin20)(x-sin40)(x+sin80)=0=x^3-x^2(sin20+sin40-sin80)+x(sin20sin40-sin20sin80-sin40sin80)+sin20sin40sin80. Comparing this with the cubic coefficients, sin20+sin40-sin80=0 because there is no x^2 coefficient, and sin40=sin80-sin20 (check: sin80-sin20=2cos((80+20)/2)sin((80-20)/2)=2cos50sin30=2sin40sin30=sin40, because sin30=1/2). Similarly, we can equate expressions for -3/4 and sqrt(3)/8, relating sin40 to sin20 and sin80. sin40=sin80-sin20 can be written sin(2*20)=sin(2*40)-sin20; 2sin20cos20=2sin40cos40-sin20; 2sin20cos20=4sin20cos20(2cos^2(20)-1)-sin20; 2cos20=4cos20(2cos^2(20)-1)-1; 8cos^3(20)-6cos20-1=0. Writing y=cos20: 8y^3-6y-1=0, which contains no irrational numbers, but is otherwise similar to the cubic obtained earlier. Although the solution includes cos20, sin40 can easily be calculated from it. Other solutions are cos100 (cos(180-80)) and cos140 (cos(180-40)). If the solution to the cubic equations can be expressed in terms of square roots, or other roots, I'll update this answer later.
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round 4.53417968617328e-05 to 4 decimal places in decimal form

4.53417968617328 * 10^-5 0.0000453417968617328 Here's the 4th decimal place:  0.0000453417968617328 The next digit over (4) is less than or equal to 5, so the 0 doesn't round up. 0.0000 or just 0 Answer:  0
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,which number represents the tenths place 4,507,612.081

The tenths place is just to the right of the decimal.  It's 0 The thousandths place is 3 digits to the right of the decimal.  It's 1 The ten thousands place is 5 digits to the left of the decimal.  It's 0
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Find the approximate solutions of the equation 2x^2+4x+1=0 (Round up to two decimal places)

2x^2 +4x+1=0 quadratik equashun giv roots=-0.2928932 & -1.7071068
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If 1=3,2=5,3=6,4=9 so how much word needed for equal of 5?

5=10 using the following logic. Switch to the binary system of counting: 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010 represent the numbers 1 to 10 decimal in binary. If we cross out those numbers with an odd number of ones we get: 11, 101, 110, 1001, 1010. When these are converted back to decimal we get: 3, 5, 6, 9, 10. These are the listed numbers in order: so 1=3, 2=5, 3=6, 4=9 and 5=10. Another way of solving the problem is to list the numbers in order that are the sum of an even number of powers of 2; or the sum of a pair of powers of 2. (1) 3=2+2^0; (2) 5=2^2+2^0; (3) 6=2^2+2^1; (4) 9=2^3+2^0; (5) 10=2^3+2^1; (6) 12=2^3+2^2, etc.
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