Guide :

Find the number termed as x in the following

  1.     7 – 5x = 3x – 6

Research, Knowledge and Information :


Find next greater number with same set of digits - GeeksforGeeks


We get “536479” which is the next greater number for input 534976. Following is C++ ... means there cannot be a greater number with same set ...
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21-110: Finding a formula for a sequence of numbers


It is often useful to find a formula for a sequence of ... might look like the following. Theorem. The total number of vertices for n squares that share exactly ...
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Merrill's Chpt 1, 3, 10, 16 Flashcards | Quizlet


patient's name or ID number ... Collimation of the x-ray beam prompts which of the following. ... the x-ray projection is termed. AP.
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Algebra Examples | Linear Equations | Finding X and Y Intercepts


Algebra Examples. Step-by-Step Examples. Algebra. Linear Equations. Find the X and Y Intercepts. To find the x-intercept, ... Credit Card Number .
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Ch 1 & 3 positioning exam Flashcards | Quizlet


Ch 1 & 3 positioning exam. ... Which of the following terms are used both as an x-ray projection and a body position? 1.) ... the x-ray projection is termed: AP
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Stats: Binomial Probabilities - Richland Community College


Stats: Binomial Probabilities. Binomial Experiment. ... Define the number of successes out of those trials: x = 2; Anytime a six appears, it is a success ...
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Polynomial functions - xaktly


Find all roots of these polynomial functions by factoring by grouping. ... The number to be substituted for x is written in the square bracket on the left, ...
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3 Easy Ways to Find the Zeros of a Function (with Pictures)


You usually try to find the zeros of a function to find an "answer" to a polynomial equation, such as x2 + 4x +3 ... A binomial is just (x ± number)(x ± number). ...
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WebElements Periodic Table»Group numbers»periodicity


Group numbers: periodicity. The group number is an identifier used to describe the column of the standard ... The following names for specific groups in the periodic ...
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CS Illuminated, 5 ed. Chapter 2 Review Quiz


CS Illuminated, 5th ed. Chapter 2 Review Quiz 1. ... Convert the following octal number to hexadecimal: 476 101. Convert the following octal number to base 13: ...
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Suggested Questions And Answer :


Fibonacci Type Sequence..

1) F3 =  F1+F2 F4 = F2+F3 = F2+F1+F2 =                F1+ 2F2 F5 = F3+F4 = F1+F2+2F2+F1 =      2F1+ 3F2 F6 = F4+F5 = 2F2+F1+2F1+3F2 =  3F1+ 5F2 F7 =F5+F6 = 2F1+3F2+3F1+5F2 = 5F1+ 8F2 F8 = F6+F7 =                                   8F1+13F2 F9 =                                               13F1+21F2 F10 =                                              21F1+34F2 2) 7335+11733=19068=F18 (this is not part of the "true" Fibonaccci series, where F16=987, F17=1597) 3) F23=28657, F25=75025=28657+F24, F24=75025-28657=46368 (Point of interest: the Fibonacci series is closely connected to the Golden Ratio,G=(1+√5)/2=1.618 approx. To find the next term following a given one, multiply by G and round it up to the nearest integer. The bigger the term the closer the product will be to an integer. F23=28657. F23*G=46368.00002 approx, so F24=46368 and F25=F24*G=75024.99999 approx, so F25=75025.)
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what will be next number in series 31,47,91,131

The next two numbers in the series may be 135 and 71 if the following reasoning is adopted. There are 4 numbers in the series as given. They could be consecutive values of a polynomial of degree 3: y=Ax^3+Bx^2+Cx+D, because there are 4 unknown coefficients and 4 numbers in the series, which is sufficient to find the unknowns. Put x=0 and y=31, and we have D=31. Put x=1 and y=47, and we have A+B+C+D=47, so A+B+C=47-31=16. Put x=2 and y=91, and we have 8A+4B+2C+D=91 and 8A+4B+2C=91-31=60. We can write: 2A+2B+2C=32 and subtract from the previous equation: 6A+2B=28, from which B=14-3A. We know from above that C=16-A-B, so we can substitute for B and write C=16-A-14+3A=2+2A. We now have B and C in terms of A. Put x=3 and y=131, and we have 27A+9B+3C+D=131 and we can substitute for B, C and D: 27A+9*14-27A+6A+6=131. From this we get 6A=-32 and A=-16/3. We can now find B and C from A: B=14+16=30; C=-26/3. So y=-16x^3/3+30x^2-26x/3+31=30x^2+31-(2x/3)(8x^2+13). Put x=4 and we get y=480+31-(8/3)(128+13)=511-8*47=135, the next term in the series.
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Interpolate the data set (1, 150), (3, 175), (4, 185), (6, 200), (8, 300) to estimate the amount of money Gracie may earn if she displays her items for 7 hours

Since 7 is halfway between 6 and 8, Gracie should earn an amount about halfway between 200 and 300, that is, 250 (triangular interpolation). This is the simplest interpolation, but see later. Interpolating for 2 and 5 we get 162.5 and 192.5, that is, respectively, a difference of 12.5 (162.5-150 or 175-162.5) and 7.5 (192.5-185 or 200-192.5), while 250 is a difference of 50 from 200 and 300. So the interpolated figures fluctuate. For a more sophisticated approach, we need to take the whole dataset and look for a formula that best fits. One way to do this is to fit a polynomial F(x)=ax^4+bx^3+cx^2+dx+e into the five given points. This polynomial has 5 unknown coefficients, so with 5 simultaneous equations we should be able to find them. The process can be simplified slightly by taking the lowest "x" coord and using that as the zero starting point. In this case the lowest coord is 1 (hour) so we subtract 1 from the first coord of each pair to get: (0,150), (2,175), etc. F(0)=e=150. So we have the constant 150. The next step is to subtract 150 from each of the other "y" coords so we arrive at the following set of equations: (1) F(2)=16a+8b+4c+2d=25 (2) F(3)=81a+27b+9c+3d=35 (3) F(5)=625a+125b+25c+5d=50 (4) F(7)=2401a+343b+49c+7d=150 and we already have F(0)=150=e. We can now eliminate d from (1) and (2): 2F(3)-3F(2): (162-48)a+(54-24)b+(18-12)c=70-75=-5; (5) 114a+30b+6c=-5. and we can eliminate d from (3) and (4): 5F(7)-7F(5): (12005-4375)a+(1715-875)b+(245-175)c=750-350; 7630a+840b+70c=400 which simplifies to (6) 763a+84b+7c=40 or 109a+12b+c=40/7 We can eliminate c between (5) and (6): 6(6)-(5): (654-114)a+(72-30)b=240/7+5=275/7; (7) 540a+42b=275/7 or 90a+7b=275/42. So b=(275/42-90a)/7. From (6) we have: 109a+12b+c=109a+12(275/42-90a)/7+c=40/7, so c=40/7-109a-12(275/42-90a)/7; c=40/7-550/7+(1080/7-109)a=-510/7+317a/7=(317a-510)/7. We now have b and c in terms of a. We can continue to find d in terms of a. From (1) d=(25-16a-8b-4c)/2=25-16a-8(275/42-90a)/7-4(317a-510)/7; d=25-1100/147+2040/7+(-16+720/7-1268/7)a= (3675-1100+42840)/147+(-112+720-1268)a/7; d=45415/147-660a/7. We have b, c and d in terms of a, so we can find a by substituting into an equation containing all four coefficients (but not (1), because we used it to find d). Let's pick (2) and hope we get a sensible result! 81a+27(275/42-90a)/7+9(317a-510)/7+3(45415/147-660a/7)=35. From this a=5143/2772=1.855. Therefore b=-22.919, c=78.510, d=-67.687, e=150. And F(x)=1.855x^4-22.919x^3+78.510x^2-67.687x+150. This results need to be checked before we use F to find an interpolated value. Unfortunately, this polynomial approach produces inconsistent results, and needs to be discarded. Lagrange's method seems the obvious choice, even if it is tedious to do. We have 5 x values which we'll symbolise as x0, x1, x2, x3, x4 and 5 function values f0, f1, f2, f3, f4. If the function we're looking for is f(x) then: f(x)=(x-x1)(x-x2)(x-x3)(x-x4)f0/((x0-x1)(x0-x2)(x0-x3)(x0-x4))+         (x-x0)(x-x2)(x-x3)(x-x4)f1/((x1-x0)(x1-x2)(x1-x3)(x1-x4))+         (x-x0)(x-x1)(x-x3)(x-x4)f2/((x2-x0)(x2-x1)(x2-x3)(x2-x4))+... x0=1, x1=3, x2=4, x3=6, x4=8; f0=150, f1=175, f2=185, f3=200, f4=300. We want x=7, so f(7) is given by: 4.3.1.-1.150/(-2.-3.-5.-7)+6.3.1.-1.175/(2.-1.-3.-5)+ 6.4.1.-1.185/(3.1.-2.-4)+6.4.3.-1.200/(5.3.2.-2)+ 6.4.3.1.300/(7.5.4.2) This comes to: -60/7+105-185+240+540/7=1600/7=228.57 (229 to the nearest whole number) compared with 250 from the simple interpolation. 
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Gcf of 4 and 16

These are the steps to solve GCF   GCF of 4, 16 is?   GCF (4, 16)   4, 16 = 4 x 1, 4 x 4    = 4(1,4)   So 4 is the Greatest Common Divisor for numbers 4, 16.   You can solve greatest common factor or greatest common divisor with following steps:  Step 1: Note the given terms   Step 2: Find the factors of term a   Step 3: Find the factors of term b   Step 4: Note the common factors   Step 5: Highest Common Factor is obtained by multiplying the common factor. Note : If a remainder does not end at zero then the remainder is divided into the previously used divisor.
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Simplifying Ratios

For the first question you need to find the greatest common factor. Start by trying 2 and work your way up. 2 does not work because it will not go into 35 or 63. 3 does not go evenly into 35. 4 also will not work. 5 does not work. 6 also will not work. . .Then we come to 7. . .if we divide each number by 7 we get the following: 6:5:9 We know this is in lowest simplist form because 5 is a prime number. Next we need to convert kilograms to grams by multiplying by 1000 to get 35000 g : 1400 g in this case the greatest common factor is 1400 which if we divide both numbers we get 25 g : 1 g For the final question we should convert to mm 2.5m=2500mm 75cm=750mm 350 mm : 2500 mm : 750 mm We know that 50 will go evenly into each of these and we know that 350/50 is 7 which is prime. So 50 must be the greatest common factor.  Divide all 3 terms by 50 and we get 7 mm : 50 mm : 15 mm
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Describe the pattern rule in words, and then with an algebraic expression.

There are really insufficient terms to find a definitive pattern, but going off the fact that the first two terms differ by 3 and the next two terms by 5, we might suspect that the following two terms differ by 7, making the next term 19. The squares of the natural numbers differ in the same way: 1 4 9 16 ... Add 3 to each of these and we get 4 7 12 19. Therefore, the algebraic formula for the nth term is n^2+3.
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Factor by grouping

The idea behind factoring is to group as many like terms as possible making the equation simpler and easier to manipulate. 1) Seperate the like terms.  This means you group the terms that have either the same variable or are products of the same number.  I will demonstrate by putting like terms in parentheses. 0 = (x^3 + 4x^2 -3x) - 18 2) Now you will basically 'un-FOIL' the part of the equation inside the parentheses.  Since you know how to FOIL(asumming you do) you just work backwards. You know that after FOILing you have 4 terms, so try separating it into 4 terms.  The only term that can be split in this instance is 4x^2. 4x^2 = 2x^2 + 2x^2 3) un-FOIL x^3 +2x^2 + 2x^2 - 3x = (x-2)(x+3)^2 4) To find the value of 'x', you simply set it equal to each term inside parentheses. x = x-2 x = (x+3)^2 Ans) x = -3          x = 2
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Find percentage of persons who read all the news papers

           188  In above Venn diagram the letters label regions identified as follows: All the numbers are percentages. A Non-readers (8) B Read newspaper A only C Read newspaper B only D Read newspaper C only E Read A and C only  F Read B and C only  G Read A and B only  H Read all three newspapers A+B+C+D+E+F+G+H=100 (all the people) B+C+D+E+F+G+H=100-8=92 B+E+G+H=42 (A readers);  C+F+G+H=51 (B readers) D+E+F+H=68 (C readers) We have to interpret the statement: 36% read A and C. This could mean they (a) Read A and C only or (b) Read A and C and possibly B. Similarly with the 28% reading B and C and the 30% reading A and B. If we look at (a) first, this implies that E+G=30+36=66; but E+G+B+H=42, so B+H=-24, which cannot be since all the percentages have to be positive. So interpretation (b) is the acceptable one. This means that: (E+H)+(G+H)=E+G+2H=30+36=66 and E+G=66-2H, so: E+G+B+H=42=66-2H+B+H=66+B-H. Therefore H-B=24 or B=H-24. Now we have B and E+G in terms of H. Similarly, (E+H)+(F+H)=E+F+2H=36+28=64 and E+F=64-2H, so: E+F+D+H=68=64-2H+D+H=64+D-H. Therefore 4=D-H or D=H+4. And (F+H)+(G+H)=F+G+2H=58 and F+G=58-2H, so: F+G+C+H=51=58-2H+C+H=58+C-H. Therefore H-C=7 or C=H-7. Substituting for the variables that we have in terms of H, we can write: (E+G)+(E+F)+(F+G)=66-2H+64-2H+58-2H=188-6H=2(E+F+G); E+F+G=94-3H. B+C+D=H-24+H-7+H+4=3H-27 so B+C+D+E+F+G+H=3H-27+94-3H+H=92. H=92-94+27=25, so 25% of the people read all three newspapers.
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find the terms indicated in the following sequence.2,6,11,17.....a8.please explain how.

there is no possible way to solve this as a8 is not a constant number. do you have any head to ask this kind of a question. mate you need to get out of your school right now before it makes you even more dumber
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find the terms in the following sentence -2p+7 q

me ges (-2p +7q) bekum -2p and 7q
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