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# what is the answer to the problem 2n + 3n +7 = -41

what is the answer to the problem 2n + 3n +7 = -41

## Research, Knowledge and Information :

### 2n +3n +7=-41 what's the answer for this question - Brainly.com

2n +3n +7=-41 what's the answer for this question 2. Ask for ... Alright the first n should be 14 n the second one should be 20 plus the 7 thanks This question is ...

### What is 2n 3n 7-41 - Answers.com

What is 2n 3n 7-41? ... What is the answer to this problem 2n-5 equals 7? in algebra, ... What is the answer to 2n-7 equals 5n-10? 2n - 7 = 5n ...

### 2n+3n+7=-41 what is n?? (5465) | Wyzant Resources

2n+3n+7=-41 what is n?? ... please sign in to answer this question. ... It is a bit unfortunate that n is used in this problem as n is normally used as an integer ...

### What is the answer to this problem 2n-5 equals 7?

... Science Math and Arithmetic Algebra What is the answer to this problem 2n-5 equals 7? ... 2n from each side - 7 = 3n ... divide 35 by 7 to get the answer 5 ...

### Find the Domain 2n+3n+7=-41 - Mathway | Math Problem Solver

Free math problem solver answers your algebra, geometry, ... Find the Domain 2n+3n+7=-41. ... 4,000,000+ problems solved daily.

### What's the answer to 5n+2n-(3-10n)?

What's the answer to 5n+2n-(3-10n)? ... -3 + 3n = 3 + 5n + -2n Combine like terms: ... How do you make a word problem involving addition and subtraction?

## Suggested Questions And Answer :

### how do i add fractions

To add or subtract fractions, obtain a least common denominator. Subtract the numerators in the correct order and retain the same least common denominator for your answer. Simplify. To multiply fractions, multiple the numerators. The product will be the numerator of your answer. Repeat with denominators. Simplify. To divide fractions, take the reciprocal of what you are dividing by. Multiply the reciprocal with the initial number (see above for multiplication process). Simplify. Evaluate means to solve. You can solve fraction problems using the above processes. You can only simplify if both the numerator and denominator are divisible by the same number. If the denominator is odd, you can only simplify it if the numerator also is divisible by a same number. Ex. 88/33. Although the denominator is odd, both the numerator and denominator are divisible by 11 resulting in 8/3 as the simplified answer. To pace yourself during a test do the following. Find out how long you have for the test. Divide this by the total number of problems on the test. Example. 1 hour for 20 problems on your test. This means you have 3 minutes per problem. If you spend more than 3 minutes on a problem, skip it. Continue until you attempt all the problems. Go back with the remainder of the time to retry these problems you skipped. Most likely they are the most difficult, hence why you spent alot of time on them. This method of pacing allows you to skip the hard problems at first, attempt all problems, and finish the easier problems for sure.

### |3x-2|=2sqrtx+8

Four problems: Problem 1: 3x - 2 = 2sqrt(x) + 8 3x - 10 = 2sqrt(x) 9x^2 - 60x + 100 = 4x 9x^2 - 64x + 100 = 0 x = (64 +- sqrt(4096 - 3600))/18 x = (64 +- sqrt(496))/18 x = (64 +- 4sqrt(31))/18 x = (32 +- 2sqrt(31))/9 x = (32 + 2sqrt(31))/9, (32 - 2sqrt(31))/9 . Problem 2 -3x + 2 = 2sqrt(x) + 8 -3x - 6 = 2sqrt(x) 9x^2 + 36x  + 36 = 4x 9x^2 + 32x + 36 = 0 x = (-32 +- sqrt(1024 - 1296))/18 Can't do square root of a negative, so no solution. . Problem 3 3x - 2 = 2sqrt(x + 8) 9x^2 - 12x + 4 = 4(x+8) 9x^2 - 12x + 4 = 4x + 32 9x^2 - 16x - 28 = 0 x = (16 +- sqrt(256 + 36*28))/18 x = (16 +- sqrt(256 + 1008))/18 x = (16 +- sqrt(1264))/18 x = (16 +- 4sqrt(79))/18 x = (8 +- 2sqrt(79))/9 x = (8 + 2sqrt(79))/9, (8 - 2sqrt(79))/9 . Problem 4: -3x + 2 = 2sqrt(x+8) 9x^2 - 12x + 4 = 4(x+8) 9x^2 - 12x + 4 = 4x + 32 9x^2 - 16x - 28 = 0 same as Problem 3 x = (8 + 2sqrt(79))/9, (8 - 2sqrt(79))/9 . Answer: If you meant abs(3x-2) = 2sqrt(x) + 8 then the answer is:  x = (32 + 2sqrt(31))/9, (32 - 2sqrt(31))/9 If you meant abs(3x-2) = 2sqrt(x+8) then the answer is:  x = (8 + 2sqrt(79))/9, (8 - 2sqrt(79))/9

### what is "c" in the problem 4c - 5 + 14c = 67?

Problem: what is "c" in the problem 4c - 5 + 14c = 67? i did the problem but not sure if my answer is correct. my book doesnt explain this in a way i understand 4c - 5 + 14c = 67 Add the c terms. 18c - 5 = 67 Add 5 to both sides of the equation. 18c - 5 + 5 = 67 + 5 18c = 72 Divide both sides of the equation by 18 18c/18 = 72/18 c = 4 You should, of course, check the answer. 4c - 5 + 14c = 67 4(4) - 5 + 14(4) = 67 16 - 5 + 56 = 67 Taking 16 - 5 first... 11 + 56 = 67 67 = 67 It checks. Answer: c = 4

### What is the answer to 4x-2y=0 when 4x+y=0?

What is the answer to 4x-2y=0 when 4x+y=0? This problem is for using addition to solve a system if that makes any sense. Like if a problem was 3x-2y=5 when 4x+2y=-16, the answer would be -3,-2. 4x - 2y = 0  and   4x+y=0   -1 * (4x + y) = -1 * 0   -4x -3 = 0 -4x - y = 0 ---------------      -3y = 0        y = 0 4x - 2y = 0 4x - 2(0) = 0 4x - 0 = 0 4x = 0 x = 0 The (x, y) pair is (0,0), the origin. This is obvious since the y-intercept for both equations is zero. 4x - 2y = 0 -2y = -4x + 0 y = 2x + 0   set x to zero, y is zero 4x + y = 0 y = -4x + 0   set x to zero, y is zero

### what is the answer for this problem and the steps to solve 6x(4y-8) for x=3.6y=1.5

what is the answer for this problem and the steps to solve 6x(4y-8) for x=3.6y=1.5 I would like information on how to slove this problem and the answer 6x(4y-8) for x = 3.6y = 1.5. 6x(4y - 8) 6(3.6)(4(1.5) - 8) 21.6(6 - 8) 21.6(-2) -43.2

### what is the answer to the problem 240!

what is the answer to the problem 240! Please, what is the answer for the math problem 240! What you have written is 240 factorial. That means the product of every positive integer from 1 up to, and including, 240. Example: 6! = 6 * 5 * 4 * 3 * 2 * 1 = 720 240! is so large that you would have difficulty calculating it. According to Wikipedia, 100! is 9.332621544×10^157. That means 9.33 etc. multiplied by 157 tens.

### how can you get the answer 7 while only using the number 2,0,1, and 2?

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### a real word problem that models 46 divided by 6 and the answer is 7

There is a class of 46 students in all. a) Suppose at least six students are required to form a sports team. How many sports team can there be at most? (Answer: 7) b) Suppose the class is going out on a field trip. Assume that the teacher drives her own car. Each travelling-car can hold six students. How many travelling-cars will thus be needed? (Answer: 8) c) For every two travelling-car, there must be a fire extinugisher. Hence, how many fire extinguishers are needed for all the travelling-cars on this field trip? (Answer: 4)