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what number is equivalent to 35/4

what number is equivalent to 35/4  

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What is 35 equivalent to in the following problem? - Quora


What is 35 equivalent to in the following problem? ... 4 = 1000x Ect to 35=?x So what x is 35? If x = speed of light how fast is 35? And how do you say that number?
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Read about equivalent fractions - Math Goodies


The numerator and the denominator of a fraction must be multiplied by the same nonzero whole number in order to have equivalent fractions. ... as an equivalent ...
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Equivalent Fractions Calculator - Online Calculator Resource


... equivalent fractions and how to find them. Multiply the numerator and denominator by the same whole number to create an equivalent ... 4/20 = 5/25 = 6/30 = 7/35 ...
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Fill in the blanks to make the fractions equivalent ? / 35 = 4/7


Fill in the blanks to make the fractions equivalent ? / 35 = 4/7 2. ... Let's equate ? = x x/35 = 4/7 x = (4/7 ... What is the maximum number of points in which 5 ...
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35 mm equivalent focal length - Wikipedia


In photography, the 35 mm equivalent focal length is a measure that indicates the angle of view of a particular combination of a camera lens and film or sensor size.
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Fractions And Mixed Numbers - McGraw Hill Education


Fractions And Mixed Numbers ... Because 5 > 2 you have to borrow from the whole number in order to create a bigger equivalent ... 3 x 4 = 12 Answer: 35/12 Step 4: ...
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Equivalent fractions (video) | Fractions | Khan Academy


Learn how to write equivalent fractions. Learn how to write equivalent fractions. If you're seeing this message, ...
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Ex) 5 35 2 20 7 49 70 20 63 100 6 9 3 - Common Core Sheets


4. 35 5. 20 6. 6 7. 54 8. 14 9. 40 10. 6 11. 9 12. 40 13. 3 14. 48 15. 80 16. 2 17. 70 18. 8 19. 24 20. 18 ... Find the number that makes an equivalent fraction. 4 ...
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What numbers equal 35 - Answers.com


Answers.com ® WikiAnswers ® Categories Science Math and Arithmetic What numbers equal 35 ... Two times a number plus the square of the number equals 35 find the ...
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Suggested Questions And Answer :


How to solve a Logic problem?

Let q={ 0 1 4 9 16 25 36 }, r={ 1 3 5 7 9 11 }, p={ 0 2 4 6 8 10 } So q ^ r={ 1 9 }, p v q={ 0 1 2 4 6 8 9 10 16 25 36 }, p v r={ 0 1 2 3 4 5 6 7 8 9 10 11 } (p v q) ^ (p v r)={ 0 1 2 4 6 8 9 10 } p v (q ^ r)={ 0 1 2 4 6 8 9 10 }, so (p v q) ^ (p v r) = p v (q ^ r) (p v q) ^ r={ 1 9 } ≠ (p v q) ^ (p v r). Draw two intersecting circles representing sets q and r. Where they intersect is q ^ r (in the example the intersection would contain the numbers 1 and 9. Now consider augmenting the sets by the contents of p (this is the union of p with each of the two intersecting sets). This time the intersection would contain all the elements of p as well as 1 and 9. This demonstrates the first part of the question. But if the p elements are added only to q then the intersection only contains 1 9 because there are no more common elements in r than there were before. This demonstrates the second part of the question.
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help me :D

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write the equation for the function having a graph that meets all the conditions

What does g(x) look like as a graph? It's a good idea to draw a picture to help you visualise the answer to this question. When we show g(x) as a graph it looks like an inverted U with it's maximum point at (0,0). The graph never moves any further into the positive region of the vertical axis, that is, g(x), but it spreads itself symmetrically because the square of a negative number is the same as the square of the equivalent positive number (for example, -1 and +1 have the same square =1). This makes the vertical axis look like a mirror. Now to the question. The spread of the arms of the U is governed by the constant -3. The answer to the question must preserve the spread so we can reject option a, because that would be a narrower shape than g(x). Next we have to see which option puts the maximum point at f(x)=4. The maximum for g(x) is at (0,0) the "top" of the upturned U. We need to slide the U upwards, more positive, so we can reject option c, because it would force the curve downwards, more negative. We're left with options b and d. When f(x)=4 we know we must have x=-2 to satisfy the requirements, so we substitute this value into options b and d and for b we get a number which is far too negative, while option d gives us 4, so d is the right answer!
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How many ways are there to place 6 identical balls in 3 identical boxes?

This is equivalent to asking how many ways there are to use 3 numbers from the set of {0, 1, 2, 3, 4, 5, 6} (repeats allowed). Ways: 6,0,0 5,1,0 4,1,1 4,2,0 3,3,0 3,2,1 2,2,2 Identical balls:  It doesn't matter what order the balls go in. Identical boxes:  It doesn't matter which box the balls go in.  In the list of ways, this is equivalent to saying that 3,2,1 is the same as 3,1,2 or 2,1,3, etc.. 7 ways.
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what is two numbers in the given base 5 122315 + 11115

The question may be ambiguous because the two numbers cannot be base 5 numbers since only the digits 0 to 4 are available. The numbers could be base 6 or higher, including decimal, so the first assumption is that the numbers are decimal but their sum is required in base 5. Decimal addition gives 133430 as the sum. To convert from decimal to base 5 we use the fact that 10 decimal is 20 in base 5; 100 is 400 in base 5; 1000 is 13000; 10000 is 310000; 100000 is 11200000. One way of converting decimal 133430 is by splitting it into 100000+30000+3000+400+30 and working out the base 5 equivalent for each multiple power of ten: 11200000+3*310000+3*13000+4*400+3*20. The multiplication must be in base 5: 3*31=143, 3*13=44, 4*4=31, 3*2=11, so we have 11200000+1430000+44000+3100+110=13232210, remembering addition must be in base 5. Another way to convert to base 5 is to start from the left and multiply the first digit by 20 and add on the second digit: 23; then multiply this result by 20 and add the third digit: 1013 (using base 5 arithmetic) not 463, because 6 is 11 in base 5 and 4+1=10 in base 5; continue in the same way: 20310+4=20314; 411333; 13232210. If we instead make a second assumption, that the numbers are written in base 6, then we must use base 6 addition: 122315+11115=133434. In base 6, 5+5=14 (6, carried over as 1 to the next place, plus 4).  
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mathematical proofs-topic:relations

https://www.google.com/search?q=Let%20A%20%3D%20%7B0%2C%201%7D%203%20%3A%20that%20is%2C%20A%20is%20the%20set%20of%20all%20ordered%20triples%20with%20entries%20from%200%20and%201.Then%20define%20a%20relation%20R%20⊆%20A%20×%20A%20such%20that%20xRy%20if%20and%20only%20if%20x%20and%20y%20have%20the%20same%20number%20of%200s.%20Note%20that%20R%20is%20an%20equivalence%20relation.Give%20the%20partition%20of%20A%20created%20by%20the%20equivalence%20classes%20of%20R&rlz=1CAHPZV_enUS718US718&oq=Let%20A%20%3D%20%7B0%2C%201%7D%203%20%3A%20that%20is%2C%20A%20is%20the%20set%20of%20all%20ordered%20triples%20with%20entries%20from%200%20and%201.Then%20define%20a%20relation%20R%20⊆%20A%20×%20A%20such%20that%20xRy%20if%20and%20only%20if%20x%20and%20y%20have%20the%20same%20number%20of%200s.%20Note%20that%20R%20is%20an%20equivalence%20relation.Give%20the%20partition%20of%20A%20created%20by%20the%20equivalence%20classes%20of%20R&aqs=chrome..69i57&sourceid=chrome&ie=UTF-8&safe=active&ssui=on
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how do i get the equivalent value of decimal values in hexadecimal

225 hex=5+2*16+2*16^2 =5+32+512 =549
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Can someone help me translate this statement in symbols? And constuct a truth table.

Truth table   TRUE FALSE Tanisha owns a convertible No (0) Yes (1) Joan owns a Volvo No (0) Yes (1) The statement "Tanisha does not own a convertible or Joan does not own a Volvo" is equivalent to adding the numbers in the boxes. If the result is greater than zero, the statement is demonstrated. So the only combination that does not support the statement is 0+0=0. That is, "Tanisha owns a convertible; Joan owns a Volvo". In all other cases the result is 1 or 2: "Tanisha owns a convertible; Joan does not own a Volvo" is 0+1=1; etc.
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To produce prime numbers as solutions by substituting x in the formula x2 – x + 41

Euler's famous formula for generating primes is x^2+x+41=x(x+1)+41, where x is an integer. If we reduce x by 1 we have (x-1)x+41=x^2-x+41, the formula in the question. So the given formula is effectively the same as Euler's formula, which is valid for all integers less than 40. For the given formula, this is equivalent to 41 where the expression becomes 41^2-41+41=41^2. Euler's formula starts with x=0, but the given formula starts with x=1, and produces 40 prime numbers starting at 41. There is no known formula for generating all the prime numbers, but there are some generators capable of generating extremely large prime numbers (the type that fill a page to write out!).
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The integral from [0,infinity) of lnx/(1+x^2)dx.

The definite integral cannot be found because the range 0 to infinity includes a value for which the integrand cannot be defined. In fact, ln(x/(1+x^2)) or ln(x)/(1+x^2) is minus infinity at x=0. The definite integral is equivalent to the area under the curve, and this cannot be determined where there is an asymptote. So the definite integral will be minus infinity, because the area lies below the axis.
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