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simply 21/-3

simplify 21/-3

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Simply 3/21? - Weknowtheanswer


Simply 3/21? Find answers now! No. 1 Questions & Answers Place. More questions about Science & Mathematics, Mathematics
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Simply Christian Quotes by N.T. Wright - Goodreads


70 quotes from Simply Christian: ... Simply Christian Quotes (showing 1-30 of 70) ... (Revelation 21:3).” ...
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Simply CVS


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Fractions - Engrade Wikis - McGraw Hill Education


Simplifying Improper Fractions ... can be added simply by adding the numerator ... (Least Common Denominator) of 3 & 7 is 21. c. 2/3 = 14/21 ; ...
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Suggested Questions And Answer :


Probability Question

There are 70 combinations of quartets of these 8 numbers, or, in other words, 70 different ways of grouping 4 outcomes from S. They all have the same probability of being selected as a group because each member of S has the same probability of selection. These are combinations of the possible outcomes of simply picking 4 numbers from 1 to 8 so that once drawn, a number cannot be returned to the pool. After a group of 4 has been drawn, then all the numbers are returned to the pool for the next group selection in this experiment. If we add together the numbers in each quartet we get a particular sum, associating each quartet with a sum. For example, 1+2+3+4=10 and 5+6+7+8=26. So the sum is in the range 10 to 26, and the sums are not usually unique. For example: 1+2+3+8=1+3+4+6=2+3+4+5=14. So, given a sum we can identify how many quartets have that sum. Or, we can find out how many have less or more than this sum. That gives us a probability based on the number of occurrences divided by the total number of possibilities. If we can find a sum that is shared by 49 quartets then the probability of selecting that sum will be 49/70=7/10=0.7. Alternatively, we can count the number of quartets that are below or above that sum. This will be one of the requirements of the experiment. But it doesn't have to be a sum. We can use other operators than plus. In fact, between 4 numbers we can have three operators, for example, 1*2+3*4=14, or 1*2*3*4=24. So two possible events for X will simply be the result of applying different operators. If we take the sample space for the operators as { + - * } then there will be 6 permutations of these, if all operators are to be applied in order, to ordered elements of each quartet. The elements can be ordered in ascending or descending order and the results will usually be different. The normal priority rules would apply (multiplication takes priority over addition and subtraction). All that's needed is a particular result (< X, ≤ X, = X, ≥ X, > X), so that the number of occurrences is 49 out of the possible 70 outcomes. Then P(X)=49/70=0.7. The question doesn't ask for specific X, just possibilities for X. If I can, I'll identify specific events for X...when I have time!  
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8/9 - 1/5=

8/9 - 1/5= how do i get the answer please explain dont just give answer please thanks When adding or subtracting fractions, you must always use a common denominator. The easiest way to determine that denominator is simply to multiply them: 9 * 5 = 45. Multiply each fraction by a fraction that is equivalent to 1, but will result in the same denominator. For this problem, multiply the first fraction by 5/5, and multiply the second fraction by 9/9. Both 5/5 and 9/9 are equal to 1, so you are NOT changing the VALUE of the fractions, merely their representation. (8/9) * (5/5) - (1/5) * (9/9) When multiplying fractions, multiply the numerators to get the new numerator, and multiply the denominators to get the new denominator. (8/9) * (5/5) - (1/5) * (9/9) (8 * 5) / (9 * 5)  -  (1 * 9) / (5 * 9) 40/45 - 9/45 Now, simply subtract. 40/45 - 9/45 31/45
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solve 3x+y=-2 , x=y-2. this is Systems OF Equations

3x + y = -2,        [1] x = y - 2             [2]   Since equation [2] is equal to 'x' we can simply put this equation into equation [1]: So, take equation [1],   3x + y = -2 Put in equation [2],      3(y - 2) + y = -2 Now multiply out the brackets,   3(y) 3x(-2) + y = -2                                                3y -6 + y = -2                                                 4y - 6 = -2 Now you can add 6 to both sides of the equation, 4y - 6 + 6 = -2 + 6                                                                        4y = 4 Now you can divide both sides of the equation by 4,  (4y)/4 = 4/4                                                                              y = 1 So now you have the value for 'y' you can simply put this value into one of the original equations to find the value of 'x'. So take equation [2],     x = y - 2  Substitute in the value of y,         x = 1 - 2                                                x = -1   So the solution to this system of equations is: (-1, 1)       
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how to find slope and y-intercept of y=3x-5

Any line equation which is in the form y=m*x + b is called slope-intercept form. What that gives you is the slope is the number which is multiplied by X (called the coefficient) while the slope intercept is the Y value when X=0. So if we take your first equation: y = 3x - 5 The slope (or m) = 3 The Y intercept = -5 Slope is defined as either "the change in y divided by the change in x" or "rise over run", so that 3, really can be considered as 3/1. Each change in X of 1 will change Y by 3. So slope = 3/1. Graphing any line can come from 2 methods. 1) create a table of values or 2) calculate a single point (x,y) and then apply the slope to find a second coordinate pair (x,y). For the equation y=3x - 5: y = 3x - 5 x y 0 -5 1 -2 Replacing the values for X into the original equation, will come out to the values for Y. So when X=0, y = 3*0 - 5, or simply -5.  When X = 1, Y = 3*1 -5 or simply -2. With these two coordinate pairs of points, you can plot a dot on your graph at each (0,-5) and (1, -2) then draw a straight line which goes through each point and continues straight in each direction, probably ending each end of this line with an arrow to show it continues. I do not have a way to include a picture here of a graph. The second way to graph a line is as follows. You need a starting point that will be on the line. Given the form of y=mx + b, you have a simple point which can be used at the y-intercept. The point is always in the form of (0, b), so in this case it is (0,-5). From that first point, you will apply your slope. The slope is 3 (or technically 3/1 which is a big help). From the initial point (0,-5) you will go UP 3 and RIGHT 1 and that will be the next point that is easy to find. Connect those two points and continue the line in each direction and that will be a graph of your line. Anytime your slope is positive, you will use it by going UP the top number (numerator of the slope) and going RIGHT the bottom number (denominator of the slope). But if your slope is negative (like your second problem is) you will use it by going DOWN the numerator and then RIGHT the denominator. The equation is y= -2/3x + 4 ( / = divided). I need to state the slope and y-intercept. I will not walk through the details on the second equation, but you should have enough information to get the answer from the above example.
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10 vedic maths rules for class IX

2 instead of 5: 34/5 can be calculated by multiplying 34 by 2 instead of dividing by 5. 34*2=68. We just move the decimal point one place to the left: 34/5=6.8. 124/5=24.8 because 124*2=248. Move the decimal point: 248 becomes 24.8. 34*5 is the same as 34/2=17 but we add a zero to make 17 into 170. 73*5 is the same as 73/2=36.5 then move the decimal point one place to the right (or add zero): 36.5 becomes 365=73*5. So we only need to know how to multiply and divide by 2 to divide and multiply by 5. We just move the decimal point. Divisibility by 9 or remainder after dividing by 9. All multiples of 9 contain digits which added together give 9. As we add the digits together, each time the result goes over 9 we add the digits of the result together and use that result and continue in this way up to the last digit. Is 12345 divisible by 9? Add the digits together 1+2+3=6. When we add 4 we get 10, so we add 1 and zero=1 then we add 5 to get 6. The number is not exactly divisible by 9, but the remainder is 6. We can also ignore any 9's in the number. Now try 67959. We can ignore the two 9's. 6+7=13, and 1+3=4; 4+5=9, so 67959 is divisible by 9. Multiplying by 11. Example: 132435*11. We write down the first and last digits 1 ... 5. Now we add the digits in pairs from the left a digit step at a time. So 1+3=4; 3+2=5: 2+4=6; 4+3=7; 3+5=8. Write these new digits between 1 and 5 and we get 1456785=132435*11. But we had no carryovers here. Now try 864753*11. Write down the first and last digits: 8 ... 3. 8+6=14, so we cross out the 8 and replace it with 8+1=9, giving us 94 ... 3. Next pair: 6+4=10. Again we go over 10 so we cross out 4 and make it 5. Now we have 950 ... 3. 4+7=11, so we have 9511 ... 3. 7+5=12, giving us 95122 ... 3; 5+3=8, giving us the final result 9512283.  Divisibility by 11. We add alternate digits and then we add the digits we missed. Subtract one sum from the other and if the result is zero the original number was divisible by 11. Example: 1456785. 1 5 7 5 make up one set of alternate digits and the other set is 4 6 8. 1+5+7=13. We drop the ten and keep 3 in mind to add to 5 to give us 8. Now 4 6 8: 4+6=10, drop the ten and add 0 to 8 to give us 8 (or ignore the zero). 8-8=0 so 11 divides into 1456785. Now 9512283: set 1 is 9 1 2 3 and set 2 is 5 2 8; 9+1=0 (when we drop the ten); 2+3=5; set 1 result is 5; 5+2+8=5 after dropping the ten, and 5-5=0 so 9512283 is divisible by 11. Nines remainder for checking arithmetic. We can check the result of addition, subtraction, multiplication and (carefully) division. Using Method 2 above we can reduce operands to a single digit. Take the following piece of arithmetic: 17*56-19*45+27*84. We'll assume we have carried out this sum and arrived at an answer 2365. We reduce each number to a single digit using Method 2: 8*2-1*9+9*3. 9's have no effect so we can replace 9's by 0's: 8*2 is all that remains. 8*2=16 and 1+6=7. This tells us that the result must reduce to 7 when we apply Method 2: 2+3+6=11; 1+1=2 and 2+5=7. So, although we can't be sure we have the right answer we certainly don't have the wrong answer because we arrived at the number 7 for the operands and the result. For division we simply use the fact that a/b=c+r where c is the quotient and r is the remainder. We can write this as a=b*c+r and then apply Method 2, as long as we have an actual remainder and not a decimal or fraction. Divisibility by 3. This is similar to Method 2. We reduce a number to a single digit. If this digit is 3, 6 or 9 (in other words, divisible by 3) then the whole number is divisible by 3. Divisibility by 6. This is similar to Method 6 but we also need the last digit of the original number to be even (0, 2, 4, 6 or 8). Divisibility by 4. If 4 divides into the last two digits of a number then the whole number is divisible by 4. Using 4 or 2 times 2 instead of 25 for multiplication and division. 469/25=469*4/100=1876/100=18.76. 538*25=538*100/4=134.5*100=13450. We could also double twice: 469*2=938, 938*2=1876, then divide by 100 (shift the decimal point two places to the left). And we can divide by 2 twice: 538/2=269, 269/2=134.5 then multiply by 100 (shift the decimal point two places left or add zeroes). Divisibility by 8. If 8 divides into the last three digits of a number then the whole number is divisible by 8. Using 8 or 2 times 2 times 2 instead of 125 for multiplication and division. Similar to Method 9, using 125=1000/8. Using addition instead of subtraction. 457-178. Complement 178: 821 and add: 457+821=1278, now reduce the thousands digit by 1 and add it to the units: 278+1=279; 457-178=279. Example: 1792-897. First match the length of 897 to 1792 be prefixing a zero: 0897; complement this: 9102. 1792+9102=1894. Reduce the thousands digit by 1 and add to the result: 894+1=895. Example: 14703-2849. 2849 becomes 02849, then complements to 97150. 14703+97150=111853; reduce the ten-thousands digit by 1 and and add to the result: 11854. Squaring numbers ending in 5. Example: 75^2. Start by writing the last two digits, which are always 25. Take the 7 and multiply by 1 more than 7, which is 8, so we get 56. Place this before the 25: 5625 is the square of 75. The square of 25 is ...25, preceded by 2*3=6, so we get 625. All numbers ending in 0 or 5 are exactly divisible by 5 (see also Method 1). All numbers ending in zero are exactly divisible by 10. All numbers ending in 00, 25, 50 or 75 are divisible by 25. Divisibility by 7. Example: is 2401 divisible by 7? Starting from the left with a pair of digits we multiply the first digit by 3 and add the second to it: 24: 3*2+4=10; now we repeat the process because we have 2 digits: 3*1+0=3. We take this single digit and the one following 24, which is a zero: 3*3+0=9. When we get a single digit 7, 8 or 9 we simply subtract 7 from it: in this case we had 9 so 9-7=2 and the single digit is now 2. Finally in this example we bring in the last digit: 3*2+1=7, but 7 is reduced to 0. This tells us the remainder after dividing 2401 by 7 is zero, so 2401 is divisible by 7. Another example: 1378. 3*1+3=6; 3*6=18 before adding the next digit, 7 (we can reduce this to a single digit first): 3*1+8=3*1+1=4; now add the 7: 4+7=4+0=4;  3*4=12; 3*1+2+8=5+1=6, so 6 is the remainder after dividing 1378 by 7.  See also my solution to: http://www.mathhomeworkanswers.org/72132/addition-using-vedic-maths?show=72132#q72132
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7(6x^2-2x+17)+9(2x^2+6x-83)

lol. i realize i messed up my sentence. happens. "^" represents the next number is an exponent, wouldnt figure that info would be needed, but just incase.
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definite integral

integral_0^0.4 1/(0.02+0.025 x)^2 dx = 666.667 how to solve this manually?? help int [0 .. 0.4] 1/(0.02+0.025 x)^2 dx. Consider the integral of 1/(a+bx)^n. This is simply (-1/(b(n-1)))*(1/(a+bx)^(n-1)) (It is easier to inderstand the above if you differentiate it to get the original expression.) if a = 2, b = 3 and n = 4, then int 1/(2+3x)^4 = (-1/(3*3))*(1/(2+3x)^(3)) So, when we have 1/(0.02+0.025 x)^2 the integral is: (-1/(0.025*1)*(1/(0.02 + 0.025x)^(1)) this simplifies as: -40/(0.02 + 0.025x) Now simply enter your limits to get the result 666.667
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add and simply 1/15 + 5/12

your answer is 29/60 simplified 0.48333
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what is 1/2 of 2/3?

1/2 of 2/3 is the same as saying 1/2 multiplied by 2/3.   (1/2) x (2/3)                             I have simply put in brackets so as not to get confused = (1x2) / (2x3) = 2 / 6   This can then be simplied as 2 and 6 both have a common factor of 2 (this means that both 2 and 6 can be divided by 2 and still remain whole numbers)   2 / 6 = (1x2) / (3x2) = (1 / 3) x (2 / 2)   And since 2/2 is the same as saying 1   (i.e.   2/2 = 1    )   So the answer is, (1 / 3) x (2 /2) = 1/3                                             
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What is 19/20 as a percentage?

19/20 is 85%. The easiest fractions can be simply solved by multiplying the numerator and the denominator such that the denominator becomes 100, then the numerator is your percent. In this case, you simply multiply top and bottom by 5. (19x5)/(20X5)=>(85)/(100) In the cases where the denominator does not easily go to 100, you could plug the fraction into the calculator and then multiply by 100.   Some common fractions->%s 1/2=50% 1/3=33.333333333%(repeats) 1/4=25% 1/5=20% 1/10=10%
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