Guide :

EIGHT TIMES A NUMBER MINUS FOUR TIMES THE SAME NUMBER

NEED THE EXPRESSION AND SIMPLIFY

Research, Knowledge and Information :


seven times a number minus four times the same number ...


So seven times a number minus four times the ... a number minus four times the same number seven times a number minus ... for valid complex df/dz Telling Time in ...
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Four times a number is eight more than twice the same number


Four times a number is eight more than twice ... translate the phrase into a mathematical expression and then simplify. nine times a number subtract twice the same ...
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less than or subtracted from - Math Activities Resource Center


“less than ” or “subtracted from ”. ... The same goes for ... Seven times the sum of a number and four translates to 7(x+ 4) 2) ...
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Four times the number minus fifteen is equal to s... - OpenStudy


Four times the number minus fifteen is equal to seventeen minus four ... Four times the number minus fifteen is equal to seventeen minus four times the same number.
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TRANSLATING KEY WORDS AND PHRASES INTO ALGEBRAIC EXPRESSIONS


TRANSLATING KEY WORDS AND PHRASES INTO ALGEBRAIC EXPRESSIONS ... ( x ) times Eight times a number 8x ... is the same as Eight is the same as twice a number. 8 = 2x
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Translating Verbal Expressions – Terms


Translating Verbal Expressions – Terms . ADDITION: ... a number . n – 3. minus a number . ... The product of four times a number and negative two is five 4x ...
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eight times the reciprocal of a number equals 2 times the ...


the sum of six timesa number and four times the reciprocal of same number is 14 ... number equals 47 and 10 times the first number minus 4 times the second ...
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five times a number decreased by 18 minus 4 times the same ...


five times a number decreased by 18 minus 4 times the same number is -36. what is the number? ... This result minus 4 times the same number is -108-4(-18) ...
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Suggested Questions And Answer :


Creata a fraction story

FIVE LITTLE PIGS GO TO THE MALL Mama Pig gave her five little pigs seven and a half dollars between them to spend at the mall. It was a cold day, twenty-three Fahrenheit, minus five Celsius, or five degrees below freezing. Off they trotted at a quarter to three in the afternoon. "How far is it?" the youngest pig asked after a while. "One point seven five miles from home," said the eldest. "What does that mean?" asked the youngest. "Well," explained the eldest, "if we divide the distance into quarter miles, it's seven quarters." "How long will it take to get there?" asked the pig in the middle. Her twin sister replied, "It's five past three now, so that means we've taken twenty minutes to get here. Remember the milestone outside our house? There's another one here, so we've come just one mile and we've taken a third of an hour. [That means our speed must be three miles an hour.] "How much longer?" the youngest asked. "Three quarters of a mile to go," the next youngest started. "Yes," said the eldest, "we get the time by dividing distance by speed, so that means three quarters divided by three, which is one quarter of an hour [which is fifteen minutes]." ["So what time will we arrive?" the youngest asked. "About twenty past three," all the other pigs replied together.] "That's thirty-five minutes altogether," the eldest continued, "which means that - let me see - seven quarters divided by three is seven twelfths of an hour. One twelfth of an hour is five minutes [so seven twelfths is thirty-five minutes]. Yes, that's right." When they got to the mall, it had started to snow. Outside there was a big thermometer and a sign: "COME ON IN. IT'S WARMER INSIDE!" The eldest observed: "It shows temperature in Fahrenheit and Celsius. See, there's a scale on each side of the gauge. It's warmer now than it was when we left home. The scales are divided into tenths of a degree. It says twenty-seven Fahrenheit exactly, and, look, that's the same as minus two point eight Celsius," speaking directly to the youngest, "because the top of the liquid is about eight divisions between minus two and minus three. Our outside thermometer at home is digital, but this is analogue." The youngest stuttered: "What's 'digital' and 'analogue'?" "Well," began one of the twins, "your watch is analogue, because it has fingers that move round the watch face. Our thermometer at home is digital, because it just shows the temperature in numbers." ["Yes," said the eldest, "it would show thirty-seven point zero degrees Fahrenheit, four degrees warmer, and minus two point eight Celsius, two point two degrees warmer than when we left."] Continued in comment... 
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writing a number sentence for twice a number cubed minus four times the sum of eight and six

2x^3 -4*(8+6) or 2x^3 -4*14 or 2x^2 -56
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four times eight minus (sixteen divided four) times two.

what is the answer to four times eight minus (sixteen divided by four) times two.
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Forty eight decreased by a # is the same as the dif. of four times th num and 7

Forty eight decreased by a # is the same as the dif. of four times th num and 7 this is what i have idk if its right. 48-x=4*x+7 The statement "the dif. of four times th num and 7" refers to subtraction. It means the difference between two numbers: 4x is one number, and 7 is the other number. 48 - x = 4x - 7 48 + 7 = 4x + 4 5x = 55 x = 11     <<<<<<<<< Check it. 48 - 11 = 4(11) - 7 37 = 44 - 7 37 = 37 Solving the equation you suggested doesn't produce an integer for x. 48 - x = 4x + 7 5x = 41 x = 8 1/5 Solving your equation gives 39.8 = 39.8  
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the expression 8-2x can be used to represent which phrase?

maebee thats the fazes av the moon on planet x . . .
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EIGHT TIMES A NUMBER MINUS FOUR TIMES THE SAME NUMBER

8x-4x bekum4x .........
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Add three to a number, then multiply your number by 4

y=4*(x+3) ....................
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the difference of negative nine times a number and eight minus the square of the same number

sound like x^2-9x =x*(x-9) .........
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If 8 times a # decreased by 4 is the same as 7 times the # decreased by 10. What is the #?

it mite be 8x-4=7x-10 or werds kood be interpreted as8(x-4)=7(x-10) 8x-4=7x-10 1x-4=-10 x=-10+4=-6
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how to factorise fully

I can offer tips: Look out for constants and coefficients that are multiples of the same number, e.g., if all the coefficients are even, 2 is a factor. If 3 goes into all the coefficients, 3 is a factor. Place the common numerical factor outside brackets, containing the expression, having divided by the common factor. In 2x^2+10x-6 take out 2 to give 2(x^2+5x-3). In 24x^2-60x+36 12 is a common factor so this becomes: 12(2x^2-5x+3). This also applies to equations: 10x+6y=16 becomes 2(5x+3y)=2(8). In the case of an equation, the common factor can be completely removed: 5x+3y=8. Now look for single variable factors. For example, x^2y^3+x^3y^2. Look at x first. We have x^2 and x^3 and they have the common factor x^2, so we get x^2(y^3+xy^3) because x^2 times x is x^3. Now look at y. We have y^2 and y^3 so now the expression becomes x^2y^2(y+x). If the expression had been 2x^2y^3+6x^3y^2, we also have a coefficient with a common factor so we would get: 2x^2y^2(y+3x). If you break down the factors one at a time instead of all at once you won't get confused. After single factors like numbers and single variables we come to binomial factors (two components). These will usually consist of a variable and a constant or another variable, such as x-1, 2x+3, x-2y, etc. The two components are separated by plus or minus. In (2) above we had a binomial component y+x and y+3x. These are factors. It's not as easy to spot them but there are various tricks you can use to help you find them. More often than not you would be asked to factorise a quadratic expression, where the solution would be the product of two binomial factors. Let's start with two such factors and see what happens when we multiply them. Take (x-1) and (x+3). Multiplication gives x(x+3)-(x+3)=x^2+3x-x-3=x^2+2x-3. We can see that the middle term (the x term) is the result of 3-1, where 3 is the number on the second factor and 1 the number in the first factor. The constant term 3 is the result of multiplying the numbers on the factors. Let's pick a quadratic this time and work backwards to its factors; in other words factorise the quadratic. x^2+2x-48. The constant term 48 is the product of the numbers in the factors, and 2 is the difference between those numbers. Now, let's look at a different quadratic: x^2-11x+10. Again the constant 10 is the product of the numbers in the factors, but 11 is the sum of the numbers this time, not the difference. How do we know whether to use the sum or difference? We look at the sign of the constant. We have +10, so the plus tells us to add the numbers (in this case, 10+1). When the sign is minus we use the difference. So in the example of -48 we know that the product is 48 and the difference is 2. The two numbers we need are 6 and 8 because their product is 48 and difference is 2. It couldn't be 12 and 4, for example, because the difference is 8. What about the signs in the factors? We look at the sign of the middle term. If the sign in front of the constant is plus, then the signs in front of the numbers in the factors are either both positive or both negative. If the sign in front of the constant is negative then the sign in the middle term could be plus or minus, but we know that the signs within each factor are going to be different, one will be plus the other minus. The sign in the middle term tells us to use the same sign in front of the larger of the two numbers in the factors. So for x^2+2x-48, the numbers are 6 and 8 and the sign in front of the larger number 8 is the same as +2x, a plus. The factors are (x+8)(x-6). If it had been -2x the factors would have been (x-8)(x+6). Let's look at a more complicated quadratic: 6x^2+5x-21. (You may also see quadratics like 6x^2+5xy-21y^2, which is dealt with in the same way.) The way to approach this type of problem is to look at the factors of the first and last terms. Just take the numbers 6 and 21 and write down their factors as pairs of numbers: 6=(1,6), (2,3) and 21=(1,21), (3,7), (7,3), (21,1). Note that I haven't included (6,1) and (3,2) as pairs of factors for 6. You'll see why in a minute. Now we make a table (see (5) below). In this table the columns A, B, C and D are the factors of 6 (A times C) and 21 (B times D). The table contains all possible arrangements of factors. Column AD is the product of the "outside factors" in columns A and D and column BC is the product of the "inside factors" B and C. The last column depends on the sign in front of the constant 21. The "twiddles" symbol (~) means positive difference if the sign is minus, and the sum if the sign in front of the constant is plus. So in our example we have -21 so twiddles means the difference, not the sum. Therefore in the table we subtract the smaller number in the columns AD and BC from the larger and write the result in the twiddles column. Now we look at the coefficient of the middle term of the quadratic, which is 5 and we look down the twiddles column for 5. We can see it in row 6 of the figures: 2 3 3 7 are the values of A, B, C and D. If the number hadn't been there we've either missed some factors, or there aren't any (the factors may be irrational). We can now write the factors leaving out the operators that join the binomial operands: (2x 3)(3x 7). One of the signs will be plus and the other minus. Which one is which? The sign of the middle term on our example is plus. We look at the AD and BC numbers and associate the sign with the larger product. We are interested in the signs between A and B and C and D. In this case plus associates with AD because 14 is bigger than 9. The plus sign goes in front of the right-hand operand D and the minus sign in front of right-hand operand B. If the sign had been minus (-5x), minus would have gone in front of D and plus in front of B. So that's it: [(Ax-B)(Cx+D)=](2x-3)(3x+7). (The solution to 6x^2+5xy-21y^2 is similar: (2x-3y)(3x+7y).) [In cases where the coefficient of the middle term of the quadratic appears more than once, as in rows 1 and 7, where 15 is in the twiddles column, then it's correct to pick either of them, because it just means that one of the binomial factors can be factorised further as in (1) above.] Quadratic factors A B C D AD BC AD~BC 1 1 6 21 21 6 15 1 3 6 7 7 18 11 1 7 6 3 3 42 39 1 21 6 1 1 126 125 2 1 3 21 42 3 39 2 3 3 7 14 9 5 2 7 3 3 6 21 15 2 21 3 1 2 63 61  
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