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Math Word Problems: Money -

Home > By Subject > Math Word Problems > Money. ... are 2 decimal places ... a multi-step problem means that there is more than one step in solving the problem.
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Algebra Word Problems | She Loves Math

Solving Quadratics by Factoring and ... so we move the decimal 2 places away from ... Can you help me to make a problem using quadratic equations about coin ...
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"Mixture" Word Problems (page 1 of 2) - Purplemath

"Mixture" Word Problems ... When the problem is set up like this, you can usually use the last column to write your equation: The liters of ...
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Supposedly Difficult Arithmetic Word Problems

Supposedly Difficult Arithmetic Word Problems. Keep It Simple for Students ... Problem 2. A child can run 5 ... he just told them to move the decimal two places ...
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Money Word Problems - Dad's Worksheets - Free Printable Math ...

Money Word Problems. ... Mixed operation word problems with money with extra unused facts in the problem. Mixed Operation Money Word Problems with Extra Facts.
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Converting Fractions to Decimals Word Problems (4 worksheets!)

... to convert fractions to decimal numbers. ... problem solving, multiplication, division, decimals, place value, ... Peso Saludable, ...
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Converting Units: Examples | Purplemath

Converting Units: Examples. Process Examples. Purplemath. ... The conversion ratios are 1 acre = 43,560 ft 2, 1ft 3 = 7.481 gallons, and five gallons = 1 water bottle.
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PHP: number_format - Manual

* problem : number_format ... return number_format($broken_number[0]).$decimal.$broken ... the same arguments but deals with numbers as strings solving the problems ...
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Suggested Questions And Answer :

in 5.3-1.5x=1.1 what is the value of x?

5.3-1.5x=1.1 is solved by getting the unknowns on side of the equation and the knowns on the other. We do this by adding or subtracting quantities from either side of the equation. If we add 1.5x to each side we can get rid of the negative sign: 5.3=1.1+1.5x. Now subtract 1.1 from each side: 4.2=1.5x. Don't like decimals? Multiply both sides by 10 so the the decimal point is removed: 42=15x. Both sides can be divided exactly by 3, because 3 goes into 42 and 15: 14=5x. This equation is exactly the same as 5x=14. We have to divide both sides by 5 to leave x by itself, but 5 doesn't go into 14 exactly, so we need to go back to decimals: x=2.8. This is obtained by dividing 5 into 14.0. 5 goes out not 14 twice with 4 over, which makes 40 with the zero just added. The result is 8 but it's after the decimal point, hence the answer 2.8.
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How do I solve for the variable to the nearest hundredth?

Solve for the variable, making sure to get an answer that is further out (3 or more decimal places) than the hundredths place (2 decimal places), then round the answer to the nearest hundredth. As far as the actual math problem ( 4^x+2 = 15^3x-1 ), the problem is unclear. Do you mean (4^x) + 2 = (15^3x) - 1  ? Or do you mean 4^(x+2) = 15^(3x-1)  ? Or maybe (4^x) + 2 = (15^3)x - 1  ?
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Which is higher 1.05 mg or 1.30 mg?

1.30 mg is bigger than 1.05 mg just as 130 is bigger than 105. Getting rid of the decimal point by multiplying both numbers by 100 (shifting the decimal point two places to the right) makes the problem easier to solve.
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Write the equivalent fraction, the reduced fraction, and the decimal equivalent for 45%. Jenny solved this problem and her work is shown below. What mistake did she make?

45/100 is correct; 9/20 is correct; but 9/20=0.45. Jenny did not move the decimal point to the right position, so she had 10 times the proper answer.
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What is the Solution of 5 % of which is 10

The question is a bit confusing but it looks like you are looking for 5% of x = 10 or you could write this as x*5%=10 To solve this, convert the percentage to a decimal by removing the percent sign shifting two places to the left. One place would make this .5, in order to move it a second place we need to add a zero as a place holder and we get .05 We can rewrite this problem again as .05x=10 Solve for x by dividing both sides of the equation by .05 x=200
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What is the diameter of a spiral coil of .65265 inch diameter pipe 100 feet long?

The equation of a spiral in polar coordinates has the general form r=A+Bø, where A is the starting radius of the spiral and B is a factor governing the growth of the spiral outwards. For example, if B=0, there is no outward growth and we just have a circle of radius A. A horizontal line length A represents the initial r, and the angle ø is the angle between r and this horizontal line. So r increases in length as ø increases (this angle is measured in radians where 2(pi) radians = 360 degrees, so 1 radian is 180/(pi)=57.3 degrees approximately.) If B=1/2 and A=5", for example, the minimum radius would be 5" when ø=0. When ø=2(pi) (360 degrees), r=5+(pi), or about 8.14". This angle would bring r back to the horizontal position, but it would be 8.14" instead of the initial 5". At ø=720 degrees, the horizontal line would increase by a further 3.14". Everywhere on the spiral the spiral arms would be 3.14" apart. What would B be if the spiral arms were 0.65625" apart? 2(pi)B=0.65625, so B=0.65625/(2(pi))=0.10445". The equation of the spiral is r=5+0.10445ø. To calculate the length of the spiral we have two possible ways: an approximate value based on the similarity between concentric circles and a spiral; or an accurate value obtainable through calculus. The approximate way is to add together the circumferences of the concentric circles: L=2(pi)(5+(5+0.65625)+...+(5+0.65625N)) where L=spiral length and N is the number of turns. L=2(pi)(5N+0.65625S) where S=0+1+2+3+...+(N-1)=N(N-1)/2. This formula arises from the fact that the first and last terms (0, N-1) the second and penultimate terms (1, N-2) and so on add up to N-1. So, for example, if N were 10 we would have (0+9)+(1+8)+(2+7)+(3+6)+(4+5)=5*9=45=10*9/2. If N were 5 we would have 0+1+2+3+4=10=(0+4)+(1+3)+2=5*4/2. L=12*100 inches. L=1200=2(pi)(5N+0.65625N(N-1)/2)=(pi)N(10+0.65625(N-1))=(pi)N(9.34375+0.65625N). If the external radius is r1 and the internal radius is r then the thickness of the spiral is r1-r and since 0.65625 is the gap between the spiral arms N=(r1-r)/0.65625. N is an integer, but, since it is unlikely that this equation would actually produce an integer we would settle for the nearest integer. If we solve this equation for N, we can deduce the external radius and diameter of the spiral: N(9.34375+0.65625N)=1200/(pi)=381.97; 0.65625N^2+9.34375N-381.97=0 and N=(-9.34375+sqrt(1089.98))/1.3125=18 (nearest integer). This means that there are 18 turns of the spiral to make the total length about 100 feet. If X is the final external diameter of the coiled pipe and the internal radius is 5" (the minimum allowable) then X/2 is the external radius, so N=((X/2)-5)/0.65625. We found N=18 so we can find X: X=2*(0.65625*18+5)=33.625in. Solution using calculus Using calculus, we can work out the relationship between the length of the spiral and other parameters. We start with any polar equation r(ø) and a picture: draw a line representing a general value of r. At a small angle dø to this line we draw another line a little bit longer, length r+dr. Now we join the ends together to make a narrow-angled triangle AOB where angle AOB=dø and AB=ds, the small section of the curve. In the triangle AO is length r and BO is length r+dr. If we mark the point C along BO so that CO is length r, the same as AO, we have an isosceles triangle COA. Because the apex angle is small, CA=rdø, the length of the arc of the sector. In triangle ABC, CB=dr, AB=ds and CA=rdø. By Pythagoras, AB^2=CB^2+CA^2, that is, ds^2=dr^2+r^2dø^2, because angle BCA is a right angle as dø tends to zero. The length of the curve is the result of adding the tiny ds values together between limits of r or ø. We can write ds=sqrt(dr^2+r^2dø^2). If we divide both sides by dr, we get ds/dr=sqrt(1+(rdø/dr)^2) so s=integral(sqrt(1+(rdø/dr)^2)dr, where s is the length of the curve. The integral is definite if we define the limits of r. For our spiral we have r=A+Bø, making ø=(r-A)/B and B=p/(2(pi)), where p is the diameter of the pipe=0.65625", so we can substitute for ø in the integral and the limits for r are A to X/2, where A is the inner radius (A=5") and X/2 is the outer radius. dø/dr=2(pi)/p, a constant=9.57 approx. s=integral(sqrt(1+(2(pi)r/p)^2)dr) between limits r=A to X/2. After the integral is calculated, we solve for X putting s=1200". The expression (2(pi)r/p)^2 is large compared to 1, so s=integral((2(pi)r/p)dr) approximately and s=[(pi)r^2/p] (r=A to X/2); therefore, since we know s=1200, we can write ((pi)/p)(X^2/4-A^2)=1200. Therefore X=2sqrt(1200p/(pi))+A^2)=33.21". Compare this answer with the one we got before and we can see they are close. [We could get a formal solution to the integral, using hyperbolic trigonometric or other logarithmic functions, but such a solution would make it very difficult or tedious to solve for X, since X would appear in logarithmic expressions and in other expressions making it difficult or impossible to isolate X. For example, the next term in the expansion of the integral would be (p/(4(pi))ln(X/2A), having a value of about 0.06. It is anticipated, therefore, that an approximation would be sufficient in this problem with the given figures.] We can feel justified in using the formula for finding the length of pipe, L, when X=6'=72": L=((pi)/p)(1296-25)=6084.52"=507' approximately. This length of pipe would hold 507/100*0.96 gallons=4.87 gallons.      
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2.5 × 3 + 1.6 ÷ 1.25- (.85-2)

Do the calculation in brackets first: .85-2=-1.15. The minus sign outside the brackets makes this positive 1.15. Remember this result for later. Next we do the division: 1.6/1.25. Problems dividing by a decimal? Make it simpler by multiplying top and bottom by 4: 6.4/5. Still a problem dividing into a decimal? Make it easier by multiplying top and bottom by 2: 12.8/10. To divide by 10 just move the decimal point one place to the left making 1.28. (We could have got there quicker by 8*1.6/8*1.25=12.8/10.) Remember the answer for later. Do the multiplication: 2.5*3=7.5. (We could have done the multiplication before the division.) Put all the bits together: 7.5+1.28+1.15=7.50+1.28+1.15=9.93.    
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How do I write a problem that can solve by making an organized list

the type of question would be referring to mean, median and mode for example, if i give you a set of 50 numbers, 1 3 2 5 0 7 6 3 9 8 5 4 3 7 0 8 3 1 5 2 8 7 4 9 6 6 0 5 4 8 3 5 8 0 6 4 2 1 5 4 7 9 5 4 3 2 6 5 4 3 Find the mean, median and mode for this question. this will require you to make an organized list
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F (X) 2/x^2-16

In this problem to find the x and y intercept is using previous knowledge. For and function the x intercept is the the values of F(x) when x = 0. So plug zero in for x and solve for F(x). The y-intercept is the x-values for when F(x)=0. So make F(x) = 0 and solve for x. In this problem this will require you to muliply by the denominator and actually obtain the answer 0 = 2 which is impossible so there are no x intercepts. the y-intercepts are -1/8. The vertical asymptote is what makes your denominator zero. so I set the denominator equal to zero and solve. By using the difference of two squares I find (x-4)(x+4) = 0 where the vertical and horizontal asymptoes are located at x = 4 and -4. To find the horizontal asymptotes you need to look at the degrees of the polynomials of the numerator and denominator. Since the numberator is a constant the degree is 0 which is less than 2. By using the definition located in your book or on the internet. The horizontal asymptote is y = 0. Since I cannot factor my rational expression to obtain a linear equation there are no holes in my graph. I have presented plenty of videos on how to do these types of problems, you may also get an explanation on these on my youtube channel located at Let me know if it helps!
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