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What formula do we use to figure relative humidity.

formula to use in determining relative humidity. If it is 84 F and the humidity is 100% what is the relative humidity?

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Temperature, Dewpoint, and Relative Humidity Calculator


Calculate Temperature, Dewpoint, or Relative Humidity Tweet. 1) Choose a temperature scale. 2) Enter values ... Press "Calculate" to find the missing value.
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Humidity Conversion Formulas B210973EN-F - Vaisala - a global ...


For instance for hydrogen we get ... The ambient temperature is 20°C and the relative humidity is 50%. Calculate enthalpy: ... Humidity Conversion Formulas ...
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CALCULATING RELATIVE HUMIDITY


CALCULATING RELATIVE HUMIDITY: METEOROLOGIST JEFF HABY Calculating the RH requires the correct equation(s). ... There are computer programs that will do this.
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How to Calculate Humidity: 9 Steps (with Pictures) - wikiHow


How to Calculate Humidity. ... Relative humidity is an estimate of the how saturated the air is with water vapour. To figure out what kind to tool you need and how to ...
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Dewpoint Calculator | Relative Humidity Calculator


Simple online weather calculator to find relative humidity, dewpoint from wet-bulb temperature
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A Method to Measure Humidity Based on Dry-Bulb and Wet-Bulb ...


A Method to Measure Humidity Based on Dry ... searching table and smooth transformation to calculate the air relative humidity is ... we use the Buck formula ...
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How to calculate relative humidity



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WRAL.com


How to calculate relative humidity
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... calculate relative humidity using formula (7). ... but we'll still have plenty of heat and humidity.


http://www.wral.com/how-to-calculate-relative-humidity/1174528/
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How do I calculate dew point? - IRI Data Library


How do I calculate dew point when I know the temperature and the relative humidity? Relative humidity gives the ratio of how much moisture the air is holding ...
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Online calculator: Relative humidity to absolute humidity and ...


Second calculator converts absolute humidity to relative humidity for ... First calculator converts relative humidity to absolute ... Then we can use the ...
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Suggested Questions And Answer :


What formula do we use to figure relative humidity.


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napier's formula

If you are referring to Napier's formula that is frequently used to estimated the steam flow from a system at a pressure Pgage through an ******* to atmosphere, this would interest me too. quote begin(By Henry Manczyk, CPE, CEM Manczyk Energy Consulting): Steam loss through an ******* can be estimated using a variant of the Napier formula: Steam Flow (lb/hr) = 24.24 x Pa x D² where: Pa = Pgage + Patmospheric Pa = Absolute Pressure, psia Pgage = Gage Pressure, psig Patmospheric = Atmospheric Pressure, psi = 14.696 psi D = Diameter of *******, in. quote end. It is quite astonishing that the formula uses the absolute pressure. This would mean that if a system had a relative pressure of Pgage=0, then it would still leak steam with a flow rate of 24.24 x 14.696 x D² lb/hr to atmospheric pressure?!? It seems very strange to me that the absolute and not the relative pressure enters this formula. This formula and a corresponding table are stated by various steam trap manufacturers and vendors for steam trap monitoring and it is always used to estimate the steam leakage to atmosphere. I would really appreciate any reference to the origine of this formula or any further comments. Thanks JF
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Find the explicit formula for a the nth term in the following sequence: 2, 24, 144, 3456

The series is: 2^1*3^0, 2^3*3^1, 2^4*3^2, 2^7*3^3. The powers of 3 are progressive: 0, 1, 2, 3, etc., but the powers of 2 are: 1, 3, 4, 7. It would seem that 3^n is part of the explicit formula, but we also need a formula for the powers of 2. It appears that the the sum of the first 2 powers of 2 equals the third (1+3=4) and the sum of the next pair equals the next power (3+4=7). The next power using this pattern would be 11. However, there are insufficient terms to determine whether this pattern is the actual one. The series 1, 3, 4, 7 is related to the Fibonacci series, and there is no explicit formula for the nth term without invoking an irrational expression, which is unlikely to be a solution for this question. (A more plausible formula would be: 2^(2n+1)3^n or 2*12^n, which gives 2, 24, 288, 3456, 41472, etc.) There is a formula relating 1 3 4 and 7 as the first few terms of a series: n^3/2-2n^2+7n/2+1. When n=0, we have 1; n=1, 3; n=2, 4; n=3, 7; n=4, 15; n=5, 31; n=6, 58; n=7, 99; n=8, 157. So the explicit formula would be for the nth term, starting at n=0: 2^(n^3/2-2n^2+7n/2+1)*3^n. This is an unlikely formula which suggests that the series may have been wrongly presented.
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area under a curve at the right of a circle

Remember that the area under a curve has to be bounded, so limits need to be applied to define the boundaries. Usually it's the area between the curve and one axis or both. Occasionally it's the area between two curves or the area produced by the intersection of two curves. Sometimes, as in the case of a circle or ellipse which already encloses an area, it's the whole or part of an area inside the curve. The "formula" is based on the area of very thin rectangles, infinitely thin, in fact, which are laid side by side to fill the area. An integral is applied which sums the areas of the rectangles over the whole region specified to get the area of that region. The most common formula is integral(ydx) where y=f(x) defines the curve. Limits of x are then given to enclose the area, so that definite integration is applied. The best way to approach any problem involving finding areas related to a curve is to sketch the curve and draw the area that needs to be found. Imagine a large curve had been drawn on the ground and you had a roll of sticky tape. You work out where the area is and cut strips of tape and stick them down so that you fill the required area. You can only lay the strips side by side, no criss-crossing and no laying the tape in a different direction. You can only cut the strips into rectangles using a cut straight across, not at an angle. You end up with not quite filling, or slightly over-filling the space because the tape will overlap the curve slightly. But when you step back it will look like the area has been properly covered by tape. If you used narrower tape the area would be even better filled. That's the principle on which the integration is based, because the area of each rectangle is the length of the strip y times the width we call dx (the width of the strips of tape). The area outside a circle must be bounded. You need the equation of the circle so that you can relate x and y. For example, the general equation of a circle is (x-h)^2/r^2 + (y-k)^2/r^2=1, where r is the radius and (h,k) is the centre. So y=k+sqrt(r^2-(x-h)^2) is half the circle, because the other half is k-sqrt(r^2-(x-h)^2).  If you need the area between the circle and the x axis between a and b, you need the lower part of the curve given by the second expression; if you need the upper part of the curve you need the first expression. If the circle is coloured red and the outside of the circle is blue, the area between the lower circle and the x axis will be entirely blue, whereas the area between the upper circle and the x axis will be red and blue. Get the picture? Once you've decided what you want, you compose the integral: integral(ydx)=integral((k-sqrt(r^2-(x-h)^2))dx) for b Read More: ...

What is the diameter of a spiral coil of .65265 inch diameter pipe 100 feet long?

The equation of a spiral in polar coordinates has the general form r=A+Bø, where A is the starting radius of the spiral and B is a factor governing the growth of the spiral outwards. For example, if B=0, there is no outward growth and we just have a circle of radius A. A horizontal line length A represents the initial r, and the angle ø is the angle between r and this horizontal line. So r increases in length as ø increases (this angle is measured in radians where 2(pi) radians = 360 degrees, so 1 radian is 180/(pi)=57.3 degrees approximately.) If B=1/2 and A=5", for example, the minimum radius would be 5" when ø=0. When ø=2(pi) (360 degrees), r=5+(pi), or about 8.14". This angle would bring r back to the horizontal position, but it would be 8.14" instead of the initial 5". At ø=720 degrees, the horizontal line would increase by a further 3.14". Everywhere on the spiral the spiral arms would be 3.14" apart. What would B be if the spiral arms were 0.65625" apart? 2(pi)B=0.65625, so B=0.65625/(2(pi))=0.10445". The equation of the spiral is r=5+0.10445ø. To calculate the length of the spiral we have two possible ways: an approximate value based on the similarity between concentric circles and a spiral; or an accurate value obtainable through calculus. The approximate way is to add together the circumferences of the concentric circles: L=2(pi)(5+(5+0.65625)+...+(5+0.65625N)) where L=spiral length and N is the number of turns. L=2(pi)(5N+0.65625S) where S=0+1+2+3+...+(N-1)=N(N-1)/2. This formula arises from the fact that the first and last terms (0, N-1) the second and penultimate terms (1, N-2) and so on add up to N-1. So, for example, if N were 10 we would have (0+9)+(1+8)+(2+7)+(3+6)+(4+5)=5*9=45=10*9/2. If N were 5 we would have 0+1+2+3+4=10=(0+4)+(1+3)+2=5*4/2. L=12*100 inches. L=1200=2(pi)(5N+0.65625N(N-1)/2)=(pi)N(10+0.65625(N-1))=(pi)N(9.34375+0.65625N). If the external radius is r1 and the internal radius is r then the thickness of the spiral is r1-r and since 0.65625 is the gap between the spiral arms N=(r1-r)/0.65625. N is an integer, but, since it is unlikely that this equation would actually produce an integer we would settle for the nearest integer. If we solve this equation for N, we can deduce the external radius and diameter of the spiral: N(9.34375+0.65625N)=1200/(pi)=381.97; 0.65625N^2+9.34375N-381.97=0 and N=(-9.34375+sqrt(1089.98))/1.3125=18 (nearest integer). This means that there are 18 turns of the spiral to make the total length about 100 feet. If X is the final external diameter of the coiled pipe and the internal radius is 5" (the minimum allowable) then X/2 is the external radius, so N=((X/2)-5)/0.65625. We found N=18 so we can find X: X=2*(0.65625*18+5)=33.625in. Solution using calculus Using calculus, we can work out the relationship between the length of the spiral and other parameters. We start with any polar equation r(ø) and a picture: draw a line representing a general value of r. At a small angle dø to this line we draw another line a little bit longer, length r+dr. Now we join the ends together to make a narrow-angled triangle AOB where angle AOB=dø and AB=ds, the small section of the curve. In the triangle AO is length r and BO is length r+dr. If we mark the point C along BO so that CO is length r, the same as AO, we have an isosceles triangle COA. Because the apex angle is small, CA=rdø, the length of the arc of the sector. In triangle ABC, CB=dr, AB=ds and CA=rdø. By Pythagoras, AB^2=CB^2+CA^2, that is, ds^2=dr^2+r^2dø^2, because angle BCA is a right angle as dø tends to zero. The length of the curve is the result of adding the tiny ds values together between limits of r or ø. We can write ds=sqrt(dr^2+r^2dø^2). If we divide both sides by dr, we get ds/dr=sqrt(1+(rdø/dr)^2) so s=integral(sqrt(1+(rdø/dr)^2)dr, where s is the length of the curve. The integral is definite if we define the limits of r. For our spiral we have r=A+Bø, making ø=(r-A)/B and B=p/(2(pi)), where p is the diameter of the pipe=0.65625", so we can substitute for ø in the integral and the limits for r are A to X/2, where A is the inner radius (A=5") and X/2 is the outer radius. dø/dr=2(pi)/p, a constant=9.57 approx. s=integral(sqrt(1+(2(pi)r/p)^2)dr) between limits r=A to X/2. After the integral is calculated, we solve for X putting s=1200". The expression (2(pi)r/p)^2 is large compared to 1, so s=integral((2(pi)r/p)dr) approximately and s=[(pi)r^2/p] (r=A to X/2); therefore, since we know s=1200, we can write ((pi)/p)(X^2/4-A^2)=1200. Therefore X=2sqrt(1200p/(pi))+A^2)=33.21". Compare this answer with the one we got before and we can see they are close. [We could get a formal solution to the integral, using hyperbolic trigonometric or other logarithmic functions, but such a solution would make it very difficult or tedious to solve for X, since X would appear in logarithmic expressions and in other expressions making it difficult or impossible to isolate X. For example, the next term in the expansion of the integral would be (p/(4(pi))ln(X/2A), having a value of about 0.06. It is anticipated, therefore, that an approximation would be sufficient in this problem with the given figures.] We can feel justified in using the formula for finding the length of pipe, L, when X=6'=72": L=((pi)/p)(1296-25)=6084.52"=507' approximately. This length of pipe would hold 507/100*0.96 gallons=4.87 gallons.      
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We need the Quadratic formula for this y=(x-2)(x-6)

We need the Quadratic formula for this y=(x-2)(x-6) My daughter is working on this problem and we can't figure this out. y = (x - 2)(x - 6) y = x^2 - 2x - 6x + 12 y = x^2 - 8x + 12 An equation of this type defines a parabola. What we are looking for is any points where the graph crosses the x-axis. If those points exist, the y value is by definition zero. Therefore, we set the equation equal to 0. x^2 - 8x + 12 = 0 This is in the form ax^2 + bx + c = 0. The a, b and c are the values used in the quadratic formula.        -b ± √(b^2 - 4ac) x = -----------------------                 2a        -(-8) ± √((-8)^2 - 4(1)(12)) x = ----------------------------------                      2(1)        8 ± √(64 - 48) x = -------------------                2        8 ± √(16) x = -------------              2        8 ± 4 x = -------           2        8 + 4                      8 - 4 x = -------      and    x = --------          2                            2        12                        4 x = -----      and    x = ----         2                         2 x = 6    and    x = 2 These values mean that the graph crosses the x-axis at (2, 0)  and  (6, 0)
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find the approximate location of all relative extrema f(x) = 0.1x^3-15^2+96x+91

Question: find the approximate location of all relative extrema f(x) = 0.1x^3-15x^2+96x+91. f = 0.1x^3-15x^2+96x+91 Turning points at f'(x) = 0 f'(x) = 0.3x^2 - 30x + 96 = 0 Using the quadratic formula to solve the above quadratic x = (30 ± √(30^2 - 4*0.3*96))/(2*0.3) Solutions are: x1 = 3.309529880, x2 = 96.69047012 Type of extrema using sign of f''(x) f''(x) = 0.6x - 30 1st turning point - x1 = 3.309529880 f''(x1) = f''(x = 3.309529880)= 0.6*3.309529880 - 30 = -28.014 SInce f''() is negative, then hte slope is decreasing, so the TP is at a maximum.   2nd turning point - x2 = 96.69047012 f''(x2) = f''(x = 96.69047012)= 0.6*96.69047012 - 30 = 28.014 SInce f''() is positive, then the slope is increasing, so the TP is at a minimum. Answer: The turning points are at x1 = 3.3 (a maximum) and x2 = 96.7 (a minimum)
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i need to know how to figure out word problems dealing with solving mph and minutes

i need to know how to figure out word problems dealing with solving mph and minutes the question is 50mph between two towns and they arrived in 25 minutes. im not looking for an answer just the formula to solve so i can study it   (mph) is a mile per hour → this a velocity (speed) so if talking about two towns mean that there will be distance to travel in mile(s). 25 min is the time that used to travel this two town.   as you are going to examen the velocity (mph or mile / hour) this mean Velocity = mile(distance) / hour (Time)   If you will be asked for Distance then Distance = Velocity x Time   If you are asked for time then Time = Distance / Velocity     This is whar you are going to need in solving problem like this.   Remember that Jesus loves you.  Know Him in the Bible God Bless  
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Describe the possible values of x in the figure shown

I am assuming that the figure mentioned is a right-angles triangle. If so, then the hypotenuse is the longest side. i.e. hypotenuse = 2x + 31, since 2x + 31 is greater than either 2x + 1 or x + 16. Using pythagoras' theorem, Hypotenuse squared = sum of squares of other two sides. i.e. (2x + 31)^2 = (2x + 1)^2 + (x + 16)^2 4x^2 + 124x + 961 = 4x^2 + 4x + 1 + x^2 + 32x + 256 x^2 + (4 + 32 - 124)x + (1 + 256 - 961) = 0 x^2 - 88x - 704 = 0 Using the quadratic formula, x = 44 +/- sqrt(165) x = 44 +/-  sqrt(165) = 44 +/-  51.3809 x= 95.38, x = -7.38 If x = -7.38, then one side of the triangle will be 2x + 1 = -14.76 + 1 = negative. We cannot have a negative length, so the negative solution for x should be ignored  
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whats the nth term for 2, 10, 24, 44, 70

Compound Arithmetic Sequence         b0          b1         b2          b3          b4           b5                c0          c1          c2          c3          c4  -------------- 1st differences                        d            d            d             d   ------------------- 2nd differences = constant We have here an irregular sequence (b_n) = (b_1, b_2, b_3, ..., b_k, ...). The differences between the elements of (b_n), the 1st differences, are non-constant. However, the (2nd) differences between the elements of (c_n) are constant. This makes (c_n) a regular arithmetic sequence, and so we can write, cn = c0 + nd,  n = 0,1,2,3,... The sequence (b_n) is non-regular, but we can write, b_(n+1) = b_n + c_n Using the expression for the c-sequence, b_(n+1) = b_n + c_0 + nd Solve the recurrence relation for b_n Develop the terms of the sequence. b1 = b0 + c0 b2 = b1 + c0 + 1.d = b0 + 2.c0 + 1.d b3 = b2 + c0 + 2.d = b0 + 3.c0 + (1 + 2).d b4 = b3 + c0 + 3.d = b0 + 4.c0 + (1 + 2 + 3).d ‘ ‘ ‘ b(n+1) = b_0 + (n+1).c0 + sum[k=1..n](k) * d b_(n+1) = b_0 + (n+1).c0 + (nd/2)(n + 1) b_(n+1) = b_0 + (n+1)(c_0 + nd/2) We could also write c0 = b1 – b0 in the above expression.   Now for you question. what the nth term for 2, 10, 24,44, 70 i cant figure it out?? The terms and differences are,         2          10         24          44          70               8            14          20          26  -------------- 1st differences                        6            6            6    ------------------- 2nd differences = constant Using the expression above for b_n, the nth term of your sequence is, a_(n+1) = 2 + (n+1)(8 + 3n),    n = 0,1,2,3,... or, a_n = 2 + n(5 + 3n),    n = 0,1,2,3,...  
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