Guide :

# Use the formula d=rt for distance traveled to solve for the missing variable.

d= ?, r= 55mi t=3h

## Research, Knowledge and Information :

### Word Problems: Distance I (d = rt) - AlgebraLAB

Word Problems: Distance I (d = rt) ... A typical problem involving distance and the formula d = rt ... you must carefully solve for the assigned variable. After ...

### quiz 2.1-2.3 - Test over Lessons 2.1-2.3 B Name Tel l Ox 1 P ...

... will l Use the formula d=rt for the distance traveled to ... will l Use the formula d=rt for the distance traveled to solve for the miSSing variable. . 1. d= 5 ...

### Use the formula d=rt to find the value of the missing ...

Use the formula d=rt to find the value of the missing ... Use the formula d=rt to find the value of the missing variable ... Use the distance equation (d=rt) ...

### Algebra II Chapters; 1, 2, 3, 10, 11 Flashcards | Quizlet

Use the formula d = rt for distance traveled to solve fore the missing variable. d = 1240 miles r = t = 16 hours. ... Find the missing probability. P(A) ...

### Solving for Missing Variable Word Problems d = rt specified

Solving for Missing Variable Word Problems One useful formula from science says that distance = rate X time. We usually write d = rt ... Use the formula d=rt to ...

### Algebra Topics: Distance Word Problems - Full Page

Use this free lesson to help you learn how to solve distance word problems. ... the distance Lee traveled. d = rt. The formula d = rt ... missing one variable, ...

### SECTION Algebra - Dublin City School District

... solve the equation for the missing variable. ... Here are three problems you can solve using the formula d 5 rt (distance 5 rate 3 time ... ALGEBRA 14. Using ...

### Ch. 2_Rates & Work Strategy Flashcards | Quizlet

Ch. 2_Rates & Work Strategy. ... RT = D Then find the missing variable. RTD Chart ... Step 1: Use the RT = W equation to solve for the rate, ...

### Solving Distance, Rate, and Time Problems

... Solving Distance, Rate, and Time Problems: ... Use the formula d = rt to fill in the remainder of the chart. In some questions you will need to solve the formula ...

## Suggested Questions And Answer :

### What's a function of function?

If you just mean the purpose of a function then see immediately below. If you mean f of g where f and g are two functions, go to the end. The purpose of a function is like giving someone a to-do list. A function (normally shown as f(x)= meaning "function of x", or y=) will usually contain one variable, usually represented by x. Some functions may have more than one variable. If x isn't the variable, it will usually be a different letter like t or a or any letter. Let's say it is x. This variable will appear in a formula with numbers. The formula is the function and it contains instructions in symbols telling you what to do with the variable. For example, multiply the variable by 2 then add 3 and divide the result by 4. This would be written f(x)=(2x+3)/4 or y=(2x+3)/4. The equals sign means that the function is defined as the expression on the right. Just like someone might say to you, think of a number (that's x), but don't tell me what it is, then double it and add 3 and divide the result by 4. Functions can be plotted on a graph. The idea of this is that on the horizontal axis (x axis) you have markers for 0, 1, 2, etc. On the vertical axis (y or f(x)) you also have markers. The graph is usually a continuous line, and every point on the line is made by putting a different value for x and marking the point (on a rectangular grid f(x) units vertically and x units horizontally) for the result of working out the value of the function for different values of x. The points make up the graph. You can use the graph to find the value of x for any value of the function, and the value of the function for any value of x, provided the graph extends far enough. This is just a brief example of the purpose of a function. A practical example is the conversion of temperature in degrees Fahrenheit (F) to degrees Celsius: C=5(F-32)/9. This function tells you what do with the value of the temperature. You could plot this as a straight line graph and you can read off degrees C for any temperature in degrees F, and vice versa. Another example is d=30t where d=distance, speed=30mph, t=time. The function is 30t, and from it you can work out the distance a car moves in a particular time t when its speed is 30mph. Function of a function: this simply means you work out the value of applying one function and then feed this answer as the variable into the other function. An example could be that one function is used to find out how many miles a car travelling at an average speed of 30mph in a given time. The second function could be to find out how much fuel is used to travel that distance. So g(t)=30t is the first function. The second function is h(d)=d/24 where fuel consumption is 24 miles per gallon. h of g is h(g(t))=30t/24=5t/4.

### i need to know how to figure out word problems dealing with solving mph and minutes

i need to know how to figure out word problems dealing with solving mph and minutes the question is 50mph between two towns and they arrived in 25 minutes. im not looking for an answer just the formula to solve so i can study it   (mph) is a mile per hour → this a velocity (speed) so if talking about two towns mean that there will be distance to travel in mile(s). 25 min is the time that used to travel this two town.   as you are going to examen the velocity (mph or mile / hour) this mean Velocity = mile(distance) / hour (Time)   If you will be asked for Distance then Distance = Velocity x Time   If you are asked for time then Time = Distance / Velocity     This is whar you are going to need in solving problem like this.   Remember that Jesus loves you.  Know Him in the Bible God Bless

You need to see through the problem and apply whatever is necessary to reduce the number of variables till eventually there's only one to find. Remember a simple fact: if you have two variables you always need two independent equations to find them; for three variables, three equations; four variables, four equations. You use the multiplication property if it helps you to eliminate a variable between two equations. Take some examples: x+y=10, x-y=3; simply adding these two equations will eliminate y and help you find x. 2x=13 so x=6.5 and y=3.5; 2x+y=10, x-2y=10; we could double one equation or the other so as to match the coefficients of one or other of the variables; but since it's easier to add two equations rather than to subtract them, where we have a minus in one equation and a plus in the other, we would prefer to use the multiplier for the relevant variable. So we double the first equation and add to the second: 4x+2y=20 PLUS x-2y=10: 5x=30, making x=6 and y=-2. The last pair of equations could have been written: 2x+y=x-2y=10, but it's still two equations. There is no one way to solve equations, and you can save yourself a lot of stress by not assuming you have to remember a rigid technique or formula as “The Way to do it”. You'll find mathematics is more fun when you intelligently try different methods and use your natural creativity to guide you. And here's another interesting thing. Those questions about finding a missing number in a series can be tackled in many cases as solving simultaneous equations. You only need n equations to find n variables, and a series can be seen as a set of terms generated by a function y=f(x) for different values of x (the position in the series), giving different values of y (the terms in the series). f(x) is a polynomial of the type ax^n+bx^(n-1)+cx^(n-2)+... If there are four given terms n=3 and the variables are a, b, c and d; if there are 3 given terms, n=2 and the variables are a, b and c. There is always a solution, we just have to work through and find it!

### solving equations

huever rote that=obveeus guvt krat...many werds that never sae nuthun... "measurements av dimenshuns" ???????? get out yer tape meshuer ?????? ????????? "determin the amount av" ???? thats same as... "measurements av dimenshuns"...=nuthun... "time tu travel"=first time yu sae sumthun that make NE sens...= look at yer watch or klok... mite be yuzefule sumtimes... nies tuno if sun up, but if yu wanna reelee find out, look up at ski... ?????????? traveling ?????????????? yu go sumweer?????... yes...nies tuno if it will take 1 our or 2 weeks & if gas mite kost 5\$ or 500\$...

### Use the formula d=rt for distance traveled to solve for the missing variable.

55*3=165 ................

### Pythagorean theorem

Here is a picture that represents what you have explained. the ladder measurement is 90 feet and the ground distance between the house and base of the ladder is 45 feet so you are just missing the distance to the window. Use the following: A^2 + B^2 = C^2 C is the Hypotenuse of the right triangle which in this case is the ladder. We will call A the ground distance and B is unknown So if you have 45^2 + B^2 = 90^2 then you just have to solve for B 2025 + B^2 = 8100 subtract 2025 from each side leaving B^2 = 6075 Then take the square root of both sides which leaves B= 77.942 which rounds to 78 The distance to the window is 78 Feet.  You should be able to create your own data for the remainder of the question using the same formula.

### solving equations

gibberish in=gibberish out

### a boat travels 30 miles upstream in 6 hours doing downstream it can travel 78 miles in the same amount of time. Find the speed of the current and the speed of the boat in still water

a boat travels 30 miles upstream in 6 hours doing downstream it can travel 78 miles in the same amount of time. Find the speed of the current and the speed of the boat in still water I don't know whether or not the math books still teach this, but this is what we were taught to solve time and distance problems:      distance               d speed | time            s | t With that, being given two of the parameters, we know how to calculate the missing parameter. This problem gives us distance and time. We need to find speed. Part 1: 30 mi / 6 hrs  =  5 m/h Part 2: 78 mi / 6 hrs  = 13 m/h Speed has two components, the boat's speed and the current's speed. Going upstream, the boat's speed is decreased by the current's speed to give the combined speed. Going downstream, the boat's speed is increased by the current's speed to give the combined speed. Part 1:  b - c = 5 m/h Part 2:  b + c = 13 m/h Adding these two equations will eliminate the current's speed.     b - c = 5 m/h +(b + c = 13 m/h) -----------------------   2b       = 18 m/h 2b = 18 m/h b = 9 m/h We can use either the upstream or downstream equation to find the current's speed. b + c = 13 m/h 9 m/h + c = 13 m/h c = 13 m/h - 9 m/h c = 4 m/h We have the speed of the current is 4 miles per hour and the speed of the boat is 9 miles per hour

### i need the answer for these questions

Part 1 Newton’s Method for Vector-Valued Functions Our system of equations is, f1(x,y,z) = 0 f2(x,y,z) = 0 f3(x,y,z) = 0 with, f1(x,y,z) = xyz – x^2 + y^2 – 1.34 f2(x,y,z) = xy –z^2 – 0.09 f3(x,y,z) = e^x + e^y + z – 0.41 we can think of (x,y,z) as a vector x and (f1,f2,f3) as a vector-valued function f. With this notation, we can write the system of equations as, f(x) = 0 i.e. we wish to find a vector x that makes the vector function f equal to the zero vector. Linear Approximation for Vector Functions In the single variable case, Newton’s method was derived by considering the linear approximation of the function f at the initial guess x0. From Calculus, the following is the linear approximation of f at x0, for vectors and vector-valued functions: f(x) ≈ f(x0) + Df(x0)(x − x0). Here Df(x0) is a 3 × 3 matrix whose entries are the various partial derivative of the components of f. Speciﬁcally,     ∂f1/ ∂x (x0) ∂f1/ ∂y (x0) ∂f1/ ∂z (x0) Df(x0) = ∂f2/ ∂x (x0) ∂f2/ ∂y (x0) ∂f2/ ∂z (x0)     ∂f3/ ∂x (x0) ∂f3/ ∂y (x0) ∂f3/ ∂z (x0)   Newton’s Method We wish to find x that makes f equal to the zero vector, so let’s choose x = x1 so that f(x0) + Df(x0)(x1 − x0) = f(x) =  0. Since Df(x0)) is a square matrix, we can solve this equation by x1 = x0 − (Df(x0))^(−1)f(x0), provided that the inverse exists. The formula is the vector equivalent of the Newton’s method formula for single variable functions. However, in practice we never use the inverse of a matrix for computations, so we cannot use this formula directly. Rather, we can do the following. First solve the equation Df(x0)∆x = −f(x0) Since Df(x0) is a known matrix and −f(x0) is a known vector, this equation is just a system of linear equations, which can be solved efficiently and accurately. Once we have the solution vector ∆x, we can obtain our improved estimate x1 by x1 = x0 + ∆x. For subsequent steps, we have the following process: • Solve Df(xi)∆x = −f(xi). • Let xi+1 = xi + ∆x

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