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# solve for x. measure of angleAOB=28 measure of angle BOC=3x-2 measure of angle AOD=6x

you have to solve for x.

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### Solve for x. The measure of anle AOB=28. The meas... - OpenStudy

Solve for x. The measure of anle AOB=28. The measure of angle BOC= 3x-2. The measure of angle AOD=6x.

### Angle AOB=x+3, Angle AOC=2x+11, Angle BOC=4x-7. Solve for x.

If angle AOB = 28, Angle BOC = 3X-2, and Angle AOD = 6x ... Solve for x: measure of AOC= 7x-2 measure of AOB= 2x+8 measure of BOC= 3x+14 math

### Solve for x. Find the angle measures to check your work. m&lt ...

If angle AOB = 28, Angle BOC = 3X-2, and Angle AOD = 6x ... Solve for x: measure of AOC= 7x-2 measure of AOB= 2x+8 measure of BOC= 3x+14 geometry line BD bisects ...

### If the measure of angle AOC = 7x - 2, the measure of angle ...

If the measure of angle AOC = 7x - 2, the measure of angle AOB = 2x + 8, and the measure of angle BOC = 3x + 14, solve for x. 10 Points? Find answers now! No. 1 ...

### Solve for X. The measure of angle AOB = 4x-2. The... - OpenStudy

Solve for X. The measure of angle AOB = 4x-2. The measure of angle BOC = 5x+10. The measure of angle COD = 2x+14.

## Suggested Questions And Answer :

### If the measure of angle one is 2 minus nine and the measure of angle 2 is 27 minus 4x. solve for x

If the measure of angle one is 2 minus nine and the measure of angle 2 is 27 minus 4x. solve for x If the measure of angle one is 2x minus 9 and the measure of angle 2 is 27 minus 4x. solve for x You haven't told us the relationship between the two angles. Do they add up to 90 degrees? Do they add up to 180 degrees? Is there some other relationship? Possibility one: (2x - 9) + (27 - 4x) = 90 2x - 4x - 9 + 27 = 90 -2x + 18 = 90 -2x = 72 x = -36 A negative angle is measured clockwise from the x axis, that is, sweeping downward around the origin. Check: (2x - 9) + (27 - 4x) = 90 (2(-36) - 9) + (27 - 4(-36)) = 90 (-72 - 9) + (27 + 144) = 90 -81 + 171 = 90 90 = 90 Possibility two: (2x - 9) + (27 - 4x) = 180 2x - 4x - 9 + 27 = 180 -2x + 18 = 180 -2x = 162 x = -81 Check: (2x - 9) + (27 - 4x) = 180 (2(-81) - 9) + (27 - 4(-81)) = 180 (-162 - 9) + (27 + 324) = 180 -171 + 351 = 180 180 = 180 We need more information.

### If the measure of angle one is "2x minus 9" and the measure of angle 2 is "27 minus 4x", solve for x

Are these angles on a straight line? If so, 2x-9+27-4x=180, so -2x-18=180 and -2x=198, so x=-99. If they're angles in a right-angled triangle, then 2x-9+27-4x=90 and -2x=108, so x=-54.

### In a triangle, the measure of the 2nd angle is twice the 1st angle. The 3rd angle is 15 degrees less than the 2nd angle. If there are 180 degrees in a triangle, find the measure of each angle.

X = first angle, 2x= second angle, 2x-15 . Their sum is 180. Solve for x. I got x= 39.  Plug 39 to x to get 2 (39) to get second angle =78. To get third angle subtract 15 to get 63. First angle=39. Second angle =78. Third angle = 63.

### Flying bearing 325 degrees 800km,turns course 235 degrees flies 950km - find bearing from A.

1. Wendy leaves airport A, flying on a bearing of 325 degrees for 800km. She then turns on a course of 235 degrees and flies for 950km. Find Wendy's bearing from A. frown 2. Wendy decides to turn and fly straight back to A at a speed of 450 km/h. How long will it take her? There are two coordinate systems used to solve this problem. The first system, used in aeronautics, is a system in which angles are measured clockwise from a line that runs from south to north. The second, used to plot graphs, measures angles counter-clockwise from the +X axis, which runs from left to right. It is necessary to convert the angles stated in the problem to equivalent angles in the rectangular coordinate system. Bearing 325 degrees is 35 degrees to the left of north. North converts to the positive Y axis, so the angle we want is the complementary angle measured up from the negative X axis. 90 - 35 = 55 If we could show a graph, we would see a line extending up to the left, from the origin at (0,0) to a point 800Km (scaled for the graph) from the origin. What we want to know is the X and Y coordinates of that point. By dropping a perpendicular line down to the X axis, we form a right-triangle, with the flight path forming the hypotenuse. We'll call the 55 degree angle at the origin angle A, and the angle at the far end of the flight path angle B. Keep in mind that angle B is the complement of angle A, so it is 35 degrees. Because we will be working with more than one triangle, let's make sure we can differentiate between the x and y sides of the triangles by including numbers with the tags. Side y1 is opposite the 55 degree angle, so... y1 / 800 = sin 55 y1 = (sin 55) * 800 y1 = 0.8191 * 800 = 655.32    We'll round that down, to 655 Km Side x1 is opposite the 35 degree angle at the top, so... x1 / 800 = sin 35 x1 = (sin 35) * 800 x1 = 0.5736 * 800 = 458.86     We'll round that up, to 459 Km At this point, the aircraft turns to a heading of 235 degrees. Due west is 270 degrees, so the new heading is 35 degrees south of a line running right to left, which is the negative X axis. Temporarily, we move the origin of the rectangular coordinate system to the point where the turn was made, and proceed as before. We draw a line 950Km down to the left, at a 35 degree angle. From the far endpoint of that line, we drop a perpendicular line to the -X axis ("drop" is the term even though we can see that the axis is above the flight path). Side y2 is opposite this triangle's 35 degree angle at the adjusted origin, so... y2 / 950 = sin 35 y2 = (sin 35) * 950 y2 = 0.5736 * 950 = 544.89    We'll round that up, to 545 Km Side x2 is opposite this triangle's 55 degree angle, so... x2 / 950 = sin 55 x2 = (sin 55) * 950 x2 = 0.8191 * 950 = 778.19    We'll round that down, to 778 Km The problem asks for the bearing to that second endpoint from the beginning point, which is where we set the first origin. We now draw our third triangle with a hypotenuse from the origin to the second endpoint and its own x and y legs. Because the second flight continued going further out on the negative X axis, we can add the two x values we calculated above. x3 = x1 + x2 = 459 Km + 778 Km = 1237 Km The first leg of the flight was in a northerly direction, but the second leg was in a southerly direction, meaning that the final endpoint was closer to our -X axis. For that reason, it is necessary to subtract the second y value from the first y value to obtain the y coordinate for the triangle we are constructing. y3 = y1 - y2 = 655 Km - 545 Km = 110 Km Using x3 and y3, we can determine the angle (let's call it angle D) at the origin by finding the tangent. tan D = y3 / x3 = 110 / 1237 = 0.0889 Feeding that value into the inverse tangent function, we find the angle that it defines. tan^-1 0.0889 = 5.08 degrees The angle we found is based on the rectangular coordinate system. We need to convert that to the corresponding bearing that was asked for in the problem. We know that the second endpoint is still to the left of the origin. The -X axis represents due west, or 270 degrees. We know that the endpoint is above the -X axis, so we must increment the bearing by the size of the angle we calculated. Bearing = 270 + 5.08    approximately 275 degrees The second part of the problem asks how long it will take Wendy (the pilot) to fly straight back to the origin. Distance = sqrt (x3^2 + y3^2) = sqrt (778^2 + 1237^2) = sqrt (605284 + 1530169)              = sqrt (2135453) = 1461.319    We'll round that one, too   1461 Km Wendy will fly 1461 Km at 450 Km/hr. How long will that take? t = d / s = 1461Km / (450Km/hr) = 3.25 hours   << 3hrs 15 mins

### how to solve triangle algerbra problems

Problem: how to solve triangle algerbra problems Show me how to find the missing number in a triangle. Like one point has 45 degrees another has 14 degrees the last has a b. How do you get the measure ments for the b. The sum of the angles in any triangle is 180 degrees. Since you know two of the angles, add them and subtract that from 180. b = 180 - (45 + 14) b = 180 - 59 b = 121 Answer: b = 121 degrees

### In a triangle, the sum of the interior angles is 180o.

x + y + z = 180 x + 43 + 67 = 180 x + 110 = 180 x = 180 - 110 x = 70 degree

### find the measure of an angle whose compliment is nine times its measure

find the measure of an angle whose compliment is nine times its measure x + 9x = 90 10x = 90 x = 9 9x = 81 The angle is 9 degrees, its complement is 81 degrees

### What is the value of x?

3x + ( 2x + 20 ) +(4x - 20) = 180 angle 1 + angle 2 + angle 3 = 180 9x = 180 x = 180/9 x = 20 degree