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a pack of 52 cards find probability when a ace or a queen?

A card is drawn at random from a well-shuffled pack of 52 cards,find the probability that the card is 1. an ace or a queen 2. a red card or a picture card.

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Playing Cards Probability | Basic Concept on Drawing a Card ...


Playing cards probability problems based on a well ... are ace, king, queen, ... A card is drawn from a well shuffled pack of 52 cards. Find the probability of: (i ...
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Two cards are randomly chosen from a pack of 52 cards ... - Quora


Two cards are randomly chosen from a pack of 52 cards. what is the probability ... queen simultaneously from a pack of 52 cards? ... probability of getting ace is 4/52
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Probability: Playing Cards - Portland State University | Home


Probability: Playing Cards ... a king, queen, and jack, ... What is the probability of picking up an ace in a 52 card deck?
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Probability - Aptitude Questions and Answers Page 3


Home » Aptitude » Probability ... of 52 cards. The probability of getting a queen of club or a ... from a pack of 52 cards. The probability that one is a ...
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Three cards are drawn at random from a well-shuffled deck of ...


... and 4 Jacks in a pack of cards. * An Ace can be ... from a pack of 52 cards, what is the probability that ... probability of getting a King, Queen AND ...
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From a standard deck of cards, one card is drawn. What is the ...


Find the probability that the card is a queen ... Queen, King, and Ace of the same ... there are 51 cards left in the pack. therefore the probability of drawing a ...
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Drawing/Picking/Selecting/Choosing Two/Three/More Cards from ...


... Three/More Cards from a well shuffled Pack of Cards. ... pack of 52 cards then find the probability that 3 of ... an ace a king and a queen is ; Two cards are ...
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Drawing/Picking/Choosing Single/One Card from a Pack ...


... a pack ; Find the probability of getting an ace, ... queen ; Find the probability of drawing a card which is not a diamond from a pack of 52 cards ; Probability ...
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Question 1 Q. Four cards are drawn from a pack of 52 cards ...


Four cards are drawn from a pack of 52 cards. Find the probability of, 1. They are King, Queen ... Queen, Jack, & Ace 2. First is King, then Queen, then Jack and ...
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a pack of 52 cards find probability when a ace or a queen?


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2.if a card is drawn at random from a well-shuffled standard deck of cards,what is the probability that it is not a face card? a.4/3 b.6/11 c.7/11 d.9/13

There are 3 face cards in a suit of 13 cards, or 12 in a standard pack of 52. The aces are not usually included as face cards. Therefore there are 10 non-face cards in a suit, making the probability of randomly drawing one of these 10/13. If the ace is included as a face card then the probability of a non-face card is 9/13.
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Three cards are drawn in sequence from a deck of cards without replacement. Find the probability distribution for the number of spades.

There are 4 suits so the chances of picking a spade initially are 1/4. There are 13 of each suit in a pack. No spades: 39 other cards so if the first card is not a spade the probability is 39/52=3/4. Now there are 51 cards left, 13 of which are spades. The probability of no spade next is 38/51, then for the third card 37/50. The combined probability for no spades is 703/1700. One spade: if a spade is drawn first the chances are 1/4. The next card is not a spade, chances are 39/51, and the third 38/50. Overall: 247/1700. Suppose the spade was drawn second: overall: 3/4 * 13/51 * 38/50=247/1700, and the same probability applies if the spade was third. So we have 3*247/1700=741/1700. Two spades: this is similar to the non-spade being drawn in 1st, 2nd or 3rd position. We multiply one probability by 3. First two are spades: 1/4 * 12/51 * 39/50=39/850. Multiply by 3: 117/850. Three spades: 1/4 * 12/51 * 11/50=11/850. So we have: #spades Probability 0             703/1700 1             741/1700 2             117/850 3               11/850 TOTAL:        1
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a well shuffled pack of 52 cards is dealt among 4 players find probability one of them has 4 aces?

chans 1 person get 4 aeses=(1/13)*(3/51)*(2/50)*(1/49)=0.00000369378520 chans 1 av 4 get 4 aeses=4 times this =0.000014775140825560995
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Count the number of elements in the event

Let's call the valued cards royal. In a pack of 52 cards there will be 16 royals. The odds of picking one of them is 16 in 52. That leaves 51 cards containing 15 royals. So the odds of picking another royal is 15 in 51. So we continue until only 37 remain, one of which is the remaing royal. The odds of picking all 16 royals in any order is therefore 16/52*15/51*...1/37 to 1 against. The number of events is the reciprocal of this which is 52C16 in nCr format. This evaluates to 10,363,194,502,115. Go for it - you can't lose!! Not!
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how do you calculate the probability of an event?

Probability of an event = # of ways an event can happen divided by # of ways anything can happen. Example:  Bag contains 3 green marbles, 2 red marbles, and 9 blue marbles. Probability of picking a green marble = 3 (how many green marbles) / 14 (how many marbles all together). Example:  Deck of cards, normal 52 cards. Probability of picking an ace = 4 (# of aces) / 52 (# of cards). Example:  Deck of cards, 54 card (52 + 2 jokers) Probability of picking an ace = 4 (# of aces) / 54 (# of cards).
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you are dealt one card from a 52 card deck. Find the probability that you are not dealt a diamond?

The probability of not being dealt a diamond is 39/52=3/4 or 0.75 or 75%, because there are 39 cards of other suits.
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What is the probability of red cards to diamonds in a standard deck of cards?

The probability of diamond being red is 1 (certainty) because all diamonds (in cards) are red. However, the probability of a red card being a diamond is 1/2 because there are as many hearts as diamonds. The probability of a card being red is 1/2 because half the cards in a pack are black and half red. The probability of a card being a diamond is 1/4 because there are four different suits. I hope this helps.
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how to find probability ?


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probability of getting 6 of clubs

There is only one 6 of Clubs in a standard pack of 52 playing cards, so the probability of selecting it is 1/52, the same as selecting any other specific card. There are 4 suits so there is a probability of 13/52=1/4 of selecting any Club; and a probability of 1/13 in selecting a 6 of any suit. The probability of selecting a Club and a 6 is 1/4*1/13=1/52. The probability of selecting a diamond or a 3 is 1/4+1/13=13/52+4/52=17/52.
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