This is a three part problem...I need direction on the next two tasks PLEASE its due today!
If he triples the price of the items the inequality will be 6A+9B>3000 where A is the number of item 1 and B the number of item 2. The total amount earned from sales has to be at least 3*1000=$3000. The first inequality can also be written 2A+3B>1000 reflecting his original investment. The cost of production has not been given. Without it we can't work out or determine the profit. If he produces item 1 only A>500; if he produces item 2 only B>333. Otherwise, A>(1000-3B)/2 or 500-(3/2)B. If B is an even number starting at 0, then B can be written B=2X where X is an integer. Then A>500-3X, so if we write (A,B) we have all possible pairs (500,0), (497,2), (494,4), (491,6), etc. as the numbers of each item. These are the minimum required to earn at least $3000 from sales. The amount of money earned for each pair is $3000. The total number of items for each pair is: 500, 499, 498, 497, etc. There are equal numbers of each item (200,200), 400 items in all, and 200*6+200*9=3000. When B=334 (X=167) and A=0, the total number of items is, of course, 334 which earns $3006.
If the shipping cost is $5 per item, then the cost per item is $11 and the total cost is 11x where x is the number of items. If $5 is the overall shipping cost then the total cost=5+6x. Assume the latter.
The other company's cost per item is $3 (half of $6) and the overall cost is 20+3x.
The Alaskan customer's cost is (a) 5+6x for x items; (b) 20+3x for x items. If x=5 then (a)=35 and (b)=35; if x=50 (a)=$305 and (b)=$170. For 5 items there is no difference in cost, and for 50 items the second company is cheaper.
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