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two-thirds of the employees participated in the charity fun run.what percentage participated

is it (0.667%-6.67%-66.7%- OR 667%

Research, Knowledge and Information :


Two-thirds of the employees participated in the charity fun ...


Two-thirds of the employees participated in the charity fun ... charity fun run. What percentage participated ... two thirds would just be one third times by two
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Two-thirds of IT Employees Are Ready to Walk Out the Door ...


Two-thirds of IT Employees Are ... organizations who don't invest in their personnel run the risk ... "The fact that two-thirds of the IT employees are waiting ...
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What’s the Hard Return on Employee Wellness Programs?


... Chevron employees staff two hospitals and ... the percentage of employees who have participated in at least ... December 2010 issue of Harvard Business Review.
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Chapter 4 Tax Flashcards | Quizlet


Chapter 4 Tax. STUDY. ... The employer paid for two-thirds of the premiums, and the employees paid for the other one-third. ... The gross profit percentage is 40%.
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Key facts | TimeBank


Key facts and figures from the ... The most common activities undertaken by regular formal volunteers were ‘organising or helping to run an ... Over two thirds of ...
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Women in World War II - Wikipedia


Women in World War II took on a variety of ... women were initially paid two-thirds of what a man at ... participated in the campaigns at Odessa and Stalingrad and ...
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Effective Employee Incentive Programs: Bring Out the Best in ...


... and over 80% of the employees participated. ... effortsâ and two thirds on â ... prizes fun and exciting, and informing employees of their progress and ...
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7 companies with amazingly unique wellness programs


May 14, 2015 · 7 companies with amazingly unique wellness ... has run a one million step challenge where employees who hit ... (two-thirds of the workforce ...
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Suggested Questions And Answer :


two-thirds of the employees participated in the charity fun run.what percentage participated

2/3=66.666%, or round tu 67%
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two-thirds of all households own their homes what is the percent

2 thirds is equal to 66.6% because 1 third is 33.3% so you just need 2 times it by 2
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what is 3800 minus 33 and a third percent?

3800 -(1/3)=(2/3)*(3800) =7600/3 =2533.3333333...
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Eight horses are entered in a race...(Have more)

1(a) How many different orders are possible for completing the race? 8*7*6*5*4*3*2*1=8!=40,320 (b) In how many different ways can first, second, and third places be decided? (Assume there is no tie.) (8*7*6)=P(8,3)=336 or 6*C(8,3) where 6=3*2*1 the number of ways of arranging three items 2.)Telephone numbers consist of seven digits; the first digit cannot be 0 or 1. How many telephone numbers are possible? 8*10^6=8,000,000  3.)In how many ways can five people be seated in a row of five seats? 5*4*3*2*1=5!=120 4.)In how many ways can five different mathematics books be placed next to each other on a shelf? 5!=120 5.)In a family of four children, how many different boy-girl birth-order combinations are possible? (The birth orders BBBG and BBGB are different.) 16=2*2*2*2 from BBBB to GGGG 6.)Two cards are chosen in order from a deck. In how many ways can this be done if (a) the first card must be a spade and the second must be a heart?  13*13=169 (b) both cards must be spades? 13*12=156 7.)A company’s employee ID number system consists of one letter followed by three digits. How many different ID numbers are possible with this system? 26*10*10*10=26,000 Continued in comment...
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need help in reading and writing in math

After the first cut and pile the total thickness will be 0.02mm. On the second cut we double this to 0.04mm; then 0.08, 0.16, 0.32, 0.64, 1.28, 2.56, 5.12, 10.24. So the final thickness is 10.24mm=1.024cm. Day 1, 50 people, Day 2, 78, Day 3, 106; the increase is 28 per day. We have to get from 50 to 200 people, so that's an increase of 150 from Day 1. 150/28=5 and then some. So after 6 days we have 6*28=168 extra people, making 168+50=218. One way of working this out is to pick a triangle of a particular shape and size and write down how many of that size there are; then pick a different sized triangle and do the same for that. The answer is likely to be a multiple of 5. I can see more than 20 triangles. How many can you see? 0.4*0.4*0.4*0.4=0.0256. So the height after 4 bounces is 0.0256*2.3=0.05888m=5.888cm. Two more bounces takes us to just under 1cm. Add all the areas together. Take the area of each lake and divide by the total then multiply by 100 to get the percentage. Time how fast you breathe in normally. Let's suppose this is 4 seconds. Remember that you breathe slower when asleep. If you're very energetic you may breathe faster on average. There are 60*60*24=86,400 seconds in a day, so that's 21,600 breaths a day. Multiply by 365.25 to find how many breaths in a year=7,889,400 breaths a year. Now multiply by your age. You can round the figures of course. It's only a fun exercise. a) 1/10 b) 7/10 c) 5/10 d) 7/10 The probability is simply the ratio of the marbles you are counting to the total number of marbles, 10. You may have to write in your words what the answers are. I hope this helps.
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statistics

(a)(1) The probability of a sale is 0.20 so the probability of no sale is 0.80. The probability of no sales with 8 firms is 0.80^8=16.78% approx. (2) We can use the binomial distribution with coefficients: 1 8 28 56 70 56 28 8 1. For no more than 2 sales we need the first 3 coefficients. (p+(p-1))^8=p^8+8p^7(1-p)+28p^6(1-p)^2+... where p=0.80. The first term is no sales at all, the second term just one sale, and the third term two sales. The total probability is 79.69%. (b)(1) Z score for X=10 is (10-7.5)/2.1=1.19 (approx) corresponding to 88.30%. So the percentage of students studying more than 10hrs per week is 11.70%. (2) If X=9, Z=0.7143, corresponding to 76.25%; and  if X=7, Z=-0.2380, corresponding to 1-0.5940=40.60%. So the proportion of students spending 7-9 hours is 76.25-40.60=35.65% approx. (3) If X=3 then Z=-2.143, corresponding to 1-0.9839=0.0161 or about 1.61% of students spend less than 3 hrs a week studying. (4) In the distribution table Z=1.645 corresponding to 95%. Therefore Z=-1.645 corresponds to 5% and -1.645=(X-7.5)/2.1, X=7.5-3.4545=4.04 or about 4 hours. So 5% of students spend less than 4 hours studying per week. (c) We don't know how many customers the clothing stores sees in one day. Should 2.7 be 2.7%?
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Geometry Postulate 7, what's the difference between any 3 noncollinear points and any 3 points?

Two points are always colinear, but a third point is not necessarily on a line joining or passing through the other two points. Imagine the two points forming part of the edge of a plane. Using the line joining them as a hinge the plane can be moved so as to uniquely include the third point, so the points are then coplanar. One plane includes all three points, and it is the only plane to do so. Going back to each of the two points, call them A and B, the third point C can be joined by a line so A and C can be on a separate plane from the plane that contains A and B. Similarly, a second plane can contain B and C. So we have four configurations: one plane containing all three points and three different planes each containing a pair of points: AB and AC, AB and BC, and AC and BC. So the three non-colinear points (not all three are in line, but two out of three must be) don't all lie on the same two planes: a pair of points only lies on each of the two planes, the third point shares a plane with only one of the other points. Does that seem clearer?  
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solve linear equation with 3 varables

Let the cost of a hat, shirt and jacket be H, S and J respectively. 3H+2S+J=140; 2H+2S+2J=170; 2J=180, so J=90; but something is wrong because this would make 2H+2S negative. Ignore the third equation and solve the first two in terms of J: 3H+2S=140-J and 2H+2S=170-2J. Subtract the latter from the former: H=-30+J or H=J-30. Put this value of H into H+S=85-J (dividing the equation by 2) and we get J-30+S=85-J; S=115-2J. The right-hand side must be positive so 115-2J>0 and J<115/2=57.50, so the jacket must be cheaper than $57.50. Also J-30>0 so J>30, the jacket is dearer than $30. Now we know that the jacket cost between $30 and $57.50. So 2J is between $60 and $115. H<27.50 and S<55 because of the limits on J. The third equation includes 2J and perhaps two more items adding up to $180. So the sum of up to two more items is between  $120 and $65, making the average price between $60 and $32.50. A graph helps, but doesn't solve the problem. Three equations can be plotted on the same graph: H=J-30; S=115-2J and Y=180-2J, where Y is the sum of other items that, together with the cost of two jackets, comes to $180. J is the "x" variable on the horizontal axis on which H, S and Y depend. The graph shows a number of interesting things. The line S=115-2J crosses H=J-30 when J=$48.33 and H=S=$18.33. To the left of the intersection the hat is cheaper than the T-shirt; to the right the hat is dearer. Let's assume the hat is more expensive than the T-shirt. So the jacket costs between $48.33 and $57.50, the hat costs between $18.33 and $27.50, and the T-shirt less than $18.33. The line Y=180-2J is parallel to S=115-2J and Y is between $65 and $83.33. If the hat costs $20, then the jacket costs $50 and the T-shirt $15, these values fit the first two equations. What about the third? Y=$80=4S+H (for example). If the third statement had been "Four shirts, a hat and two jackets cost $180", then the answer would have been: jacket costs $50, hat costs $20 and the T-shirt costs $15.
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is one third greater than two third

No one third is smaller than two third. One third is 1/3 and two third is 2/3. Since the denominator (which is 3 in this case) are the same, we will need to look at the numerators (which is 1 and 2 respectivelty in this case). If the denominator are the same for two fractions, the fraction with the larger numerator will be the larger number. Since 2 is greater than 1, in this case, 2/3 is the larger number.   As for the symbols, > means greater than and < means less than.
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2 angles of a triangle equal 180 what is the third angle

The three angles of a triangle add up to 180 in Euclidean space (that is, a "flat" triangle, not one drawn on a curved surface). If two angles already add up to 180 the third angle must be zero. If the triangle is drawn on a sphere it is possible for the triangle to have 3 angles of 90 degrees each, such as a triangle drawn with a right angle at a pole The figure ceases to be a triangle. For example, two right angles in one "flat" triangle add up to 180. The two sides would be parallel so would never meet. If one angle of a triangle was 60 degrees and the other 120, again two sides would be parallel, because the external angle would be 120 or 60. Two angles of a "flat" triangle cannot both be 180 degrees. The "triangle" would simply be a straight line. But lines drawn round a sphere form a spherical triangle. As two curved sides of the triangle approach a semi-circle the angle between them approaches 180 degrees.  A spherical triangle's sides are formed by the intersection of three great circles, so a spherical triangle can, for example, contain three right angles. So the sum of the angles in this case would be 270 degrees. Great circles have equal circumferences=2(pi)r where r is the radius of the sphere. All great circles have the same centre. The shortest distance between two points on a sphere is on the circumference of the great circle that passes through both of them.
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